Finding epoch seconds for given date.

Question

Hi,
I could able to find out the epoch seconds for particular date in linux using
date -d 'Apr 2 2005 15:31:17' '+%s'
But I am looking for the commands in solaris which does the same work.
I will be thank full if some one could help me.
I tried to do manual......but epoch seconds that I get are differing..
I found following snippet in mktime function
556 unsigned long
557 mktime(const unsigned int year0, const unsigned int mon0,
558 const unsigned int day, const unsigned int hour,
559 const unsigned int min, const unsigned int sec)
560 {
561 unsigned int mon = mon0, year = year0;
562
563 /* 1..12 -> 11,12,1..10 */
564 if (0 >= (int) (mon -= 2)) {
565 mon += 12; /* Puts Feb last since it has leap day */
566 year -= 1;
567 }
568
569 return ((((unsigned long)
570 (year/4 - year/100 + year/400 + 367*mon/12 + day) +
571 year*365 - 719499
572 )*24 + hour /* now have hours */
573 )*60 + min /* now have minutes */
574 )*60 + sec; /* finally seconds */
575 }
but could not make out why 367*mon/12.....instead of 365, I could not locate
the position where previous months days in this year added.
Is 719499 is number of days from 0th year to 1970 ?
Thank you,
Sateesh.

Answer 1

Hi Darren,
Regarding the first option of OS command
date ...'+%s' works in linux only. It will not
work in Solaris. So if I get some command in solaris
which does same work it will be great.Most distributions that use a Linux kernel distribute the gnu 'date' program. That program works the same on Solaris as it does on Linux. That's why I suggested it to you earlier.
# /build/coreutils-5.93/bin/date '+%s'
1177951907
# uname -rsv
SunOS 5.8 Generic_117350-43
Darren