Finding missing sequence

Question

Hello all.
I'm using the Oracle 10g Database. i'm trying to figure out how to write a simple sql query to:
find the missing numbers in a table between say 86002895 and 86005197 (inclusive)
Ex: Current Scenario : table_1 :
tracking_no | id_value
86002895 | 10
86002896 | 10
86002899 | 10
86002900 | 10
86002910 | 10
86005196 | 10
86005197 | 10
Expected Result1:
" missing tracking_id " where id_value = 10 from table_1 ;
86002897
86002898
86002900 to 86002910
86002910 to 86005196
Thanks in advance :)

Answer 1

user8635888 wrote:
Ex: Current Scenario : table_1 :
tracking_no | id_value
86002895 | 10
86002896 | 10
86002899 | 10
86002900 | 10
86002910 | 10
86005196 | 10
86005197 | 10
Expected Result1:
" missing tracking_id " where id_value = 10 from table_1 ;
86002897
86002898
86002900 to 86002910
86002910 to 86005196
Thanks in advance :)Maybe something like the following:
SQL> SELECT * FROM TEST_TAB
  2  /
TRACKING_NO   ID_VALUE
   86002895         10
   86002896         10
   86002899         10
   86002900         10
   86002910         10
   86005196         10
   86005197         10
7 rows selected.
SQL> SELECT   CASE
  2              WHEN tracking_no + 1 = lead_no - 1 THEN TO_CHAR (tracking_no +1)
  3              ELSE TO_CHAR (tracking_no + 1) || '-' || TO_CHAR (lead_no - 1)
  4           END
  5              Missing_track_no
  6    FROM   (SELECT   tracking_no,
  7                     LEAD (tracking_no, 1, NULL)
  8                        OVER (ORDER BY tracking_no ASC)
  9                        lead_no
10              FROM   test_tab
11             WHERE   ID_VALUE = 10)
12   WHERE   lead_no != tracking_no + 1
13  /
MISSING_TRACK_NO
86002897-86002898
86002901-86002909
86002911-86005195
3 rows selected.
SQL>You can tweak the above query to match your requirement.
Hope this helps.
Regards,
Jo