For a given date required last week day

Hi Friends,
Is there any function module exists if I will enter any date as input parameter
the last thursday date should come as output ?
For example 1: The input parameter is 15.04.2009 (15th is Wednesday) so the output is 09.04.2009(bcz last thrusday is 9th)
2. Suppose if the input parameter is 17.04.2009 (17th is friday) so the output is 16.04.2009(bcz last thrusday is 16th)
Thanks
Raj

Hi ,
You can use the following code:
data : v_date type datum,
         v_day(10) type c.
v_date = pass whatever date you want in format yyyymmdd .
do .
CALL FUNCTION 'DATE_TO_DAY'
EXPORTING
    date          = v_date
IMPORTING
   WEEKDAY       = v_day
if v_day <> 'Thursday'.
v_date = v_date - 1 .
else.
write: v_date .
exit.
endif.
enddo.
Regardrs,
Ashish Arora

Similar Messages

FM that gives number of day in the week for the given date

Hi,
I have a requirement to find the number of the day in a week for the given date. For example, 07/09/2009 is Thursday & 4th day of the week. Is there any FM to accomplish this task?
Appreciate your help in Advance.
Thanks,
Kannan.

Hi Kannan,
ISH_GET_DAY_OF_WEEK.
Regards,
Dilek

How to get the date of first day of a week for a given date

Hi gurus
can any one say me how to get the date of first day(date of Sunday) of a week for a given date in a BW transformations. For example for 02/23/2012 in source i need to get 02/19/2012(Sunday`s date) date in the result. I can get that start date of a week using BWSO_DATE_GET_FIRST_WEEKDAY function module. But this function module retrieves me the start date as weeks monday(02/20/2012) date. But i need sundays(02/19/2012) date as the start date. So it would be really great if anyone sends me the solution.
Thanks
Rav

Hi,
The simplest way would be to subtract 1 from the date date which you are already getting in transformation routine, but instead of doing that subtraction manually which might need bit of errort, you can simply use another FM to subtract 1 from given date.
RP_CALC_DATE_IN_INTERVAL
Regards,
Durgesh.

Any FM to get count of each week day for the given date range

Hi guys,
Any FM to get count of each week day for the given date range?
eg: If i give 14/07/2008 to 14/08/2008
I need to find how many Mondays, tuesdays...sundays in this given date range.
If not single FM is available, any logic that gives above result is also appreciated.
Thanks,
Vinod.

hi Vinod,
this is not a full solution, I just give you a basic idea:
DATA : lv_start TYPE sy-datum VALUE '20080714',
       lv_end   TYPE sy-datum VALUE '20080814'.
WHILE lv_start LE lv_end.
CALL FUNCTION 'FTR_DAY_GET_TEXT'
    EXPORTING
      pi_date = lv_start.
* IMPORTING
*   PE_DAY_TEXT1       =
*   PE_DAY_TEXT2       =
*   PE_DAY             =
* you have to summarize the output here somehow...
lv_start = lv_start + 1.
ENDWHILE.
hope this helps
ec

How to find the Day on a Week for any given Date

Hi..... I need your help to find out the Day on a Week for any given Date .
Say if the Date is 31/12/2009 , what would be the Day on a Week for this Date.
Are there any fucntions available to determine the same?
Please let me know....Thanks in Advance
Regards
Smita

Hi ,
You can using the following peice of code to get the Day of a Week for the given date :
Calendar now = Calendar.getInstance();
System.out.println("Current date : " + (now.get(Calendar.MONTH) + 1)
     + "-" + now.get(Calendar.DATE) + "-" + now.get(Calendar.YEAR));
//create an array of days
//Day_OF_WEEK starts from 1 while array index starts from 0
String[] strDays = new String[]{"Sunday", "Monday", "Tuesday", "Wednesday", "Thusday",   "Friday", "Saturday" };
String day_of_week = strDays[now.get(Calendar.DAY_OF_WEEK) - 1];
System.out.println("Current day is : " + strDays[now.get(Calendar.DAY_OF_WEEK) - 1] );
Edited by: Ritushree Saha on Jun 4, 2009 1:09 PM

Find the 'DAY' for a given 'DATE'

Hi Folks,
I need a help regarding finding the day for a given date.
My requirement is that..,
If I enter a date using 'parameters', it should write the 'day' for the corresponding date.
To be more specific.....,
if I enter date as ' 07/15/2008 ' it should return me the day as 'Tuesday'.
Regards,
Naveen G

HI,
FM LIST WITH RESPECT TO DAY, WEEK, AND MONTH.
CALCULATE_DATE : Calculates the future date based on the input .
DATE_TO_DAY : Returns the Day for the entered date.
DATE_COMPUTE_DAY : Returns weekday for a date
DATE_GET_WEEK : Returns week for a date
RP_CALC_DATE_IN_INTERVAL : Add days / months to a date
MONTHS_BETWEEN_TWO_DATES : To get the number of months between the two dates.
END_OF_MONTH_DETERMINE_2 : Determines the End of a Month.
HR_HK_DIFF_BT_2_DATES : Find the difference between two dates in years, months and days.
FIMA_DAYS_AND_MONTHS_AND_YEARS : Find the difference between two dates in years, months and days.
MONTH_NAMES_GET : Get the names of the month
WEEK_GET_FIRST_DAY : Get the first day of the week
HRGPBS_HESA_DATE_FORMAT : Format the date in dd/mm/yyyy format
SD_CALC_DURATION_FROM_DATETIME : Find the difference between two date/time and report the difference in hours
L_MC_TIME_DIFFERENCE : Find the time difference between two date/time
HR_99S_INTERVAL_BETWEEN_DATES : Difference between two dates in days, weeks, months
LAST_DAY_OF_MONTHS : Returns the last day of the month
DATE_CHECK_PLAUSIBILITY :Check for the invalid date.
Reward points if useful,
siri

Getting the week number for a given date

Oracle Database 11g Enterprise Edition Release 11.1.0.7.0 - 64bit Production
PL/SQL Release 11.1.0.7.0 - Production
CORE 11.1.0.7.0 Production
TNS for 64-bit Windows: Version 11.1.0.7.0 - Production
NLSRTL Version 11.1.0.7.0 - Production
Hello all.
I am currently migrating our product from SQL SERVER to ORACLE and have the following issue.
Basically I'm just trying to get the year week number for a given date but I'm having trouble with Oracle as it seems to think that the weeks run from Thursday to Thursday?. I presume this is something to do with the fact that the first day of the year was Thursday?
e.g.
SQL SERVER:
select DATEPART(wk, '2009-10-24') as Sat -- 43 - correct
select DATEPART(wk, '2009-10-25') as Sun -- 44 - correct
select DATEPART(wk, '2009-10-26') as Mon -- 44 - correct
select DATEPART(wk, '2009-10-27') as Tue -- 44 - correct
select DATEPART(wk, '2009-10-28') as Wed -- 44 - correct
select DATEPART(wk, '2009-10-29') as Thu -- 44 - correct
select DATEPART(wk, '2009-10-30') as Fri -- 44 - correct
select DATEPART(wk, '2009-10-31') as Sat -- 44 - correct
select DATEPART(wk, '2009-11-1') as Sun -- 45 - correct
select DATEPART(wk, '2009-11-2') as Mon -- 45 - correct
select DATEPART(wk, '2009-11-3') as Tue -- 45 - correct
select DATEPART(wk, '2009-11-4') as Wed -- 45 - correct
select DATEPART(wk, '2009-11-5') as Thu -- 45 - correct
ORACLE:
SELECT to_char(to_date('24-OCT-2009'), 'ww') as Sat from dual; -- 43 correct
SELECT to_char(to_date('25-OCT-2009'), 'ww') as Sun from dual; -- 43 incorrect - should be 44
SELECT to_char(to_date('26-OCT-2009'), 'ww') as Mon from dual; -- 43 incorrect - should be 44
SELECT to_char(to_date('27-OCT-2009'), 'ww') as Tue from dual; -- 43 incorrect - should be 44
SELECT to_char(to_date('28-OCT-2009'), 'ww') as Wed from dual; -- 43 incorrect - should be 44
SELECT to_char(to_date('29-OCT-2009'), 'ww') as Thu from dual; -- 44 correct
SELECT to_char(to_date('30-OCT-2009'), 'ww') as Fri from dual; -- 44 correct
SELECT to_char(to_date('31-OCT-2009'), 'ww') as Sat from dual; -- 44 correct
SELECT to_char(to_date('1-NOV-2009'), 'ww') as Sun from dual; -- 44 incorrect - should be 45
SELECT to_char(to_date('2-NOV-2009'), 'ww') as Mon from dual; -- 44 incorrect - should be 45
SELECT to_char(to_date('3-NOV-2009'), 'ww') as Tue from dual; -- 44 incorrect - should be 45
SELECT to_char(to_date('4-NOV-2009'), 'ww') as Wed from dual; -- 44 incorrect - should be 45
SELECT to_char(to_date('5-NOV-2009'), 'ww') as Thu from dual; -- 45 correct
Now I don't want to get into a discussion with regard to locales etc.
In my world (and is seems SQL SERVER's) the first day of the week is Sunday and the last Saturday.
Is there some NLS_? setting or something that I'm missing?
thanks for any help on this.
Andy

This is what you need.
SELECT ceil(( 7+(trunc(to_date('25-OCT-2009'),'d')-trunc(to_date('25-OCT-2009'),'Y')) )/7) FROM dual
HTH!!!
--tested all these statements.
Works as you wish!!
SELECT ceil(( 7+(trunc(to_date('24-OCT-2009'),'d')-trunc(to_date('24-OCT-2009'),'Y')) )/7) as Sat from dual;
SELECT ceil(( 7+(trunc(to_date('25-OCT-2009'),'d')-trunc(to_date('25-OCT-2009'),'Y')) )/7) as Sun from dual;
SELECT ceil(( 7+(trunc(to_date('26-OCT-2009'),'d')-trunc(to_date('26-OCT-2009'),'Y')) )/7) as Mon from dual;
SELECT ceil(( 7+(trunc(to_date('27-OCT-2009'),'d')-trunc(to_date('27-OCT-2009'),'Y')) )/7) as Tue from dual;
SELECT ceil(( 7+(trunc(to_date('28-OCT-2009'),'d')-trunc(to_date('28-OCT-2009'),'Y')) )/7) as Wed from dual;
SELECT ceil(( 7+(trunc(to_date('29-OCT-2009'),'d')-trunc(to_date('29-OCT-2009'),'Y')) )/7) as Thu from dual;
SELECT ceil(( 7+(trunc(to_date('30-OCT-2009'),'d')-trunc(to_date('30-OCT-2009'),'Y')) )/7) as Fri from dual;
SELECT ceil(( 7+(trunc(to_date('01-NOV-2009'),'d')-trunc(to_date('01-NOV-2009'),'Y')) )/7) as Sat from dual;
SELECT ceil(( 7+(trunc(to_date('02-NOV-2009'),'d')-trunc(to_date('02-NOV-2009'),'Y')) )/7) as Sun from dual;
SELECT ceil(( 7+(trunc(to_date('03-NOV-2009'),'d')-trunc(to_date('03-NOV-2009'),'Y')) )/7) as Mon from dual;
SELECT ceil(( 7+(trunc(to_date('04-NOV-2009'),'d')-trunc(to_date('04-NOV-2009'),'Y')) )/7) as Tue from dual;
SELECT ceil(( 7+(trunc(to_date('05-NOV-2009'),'d')-trunc(to_date('05-NOV-2009'),'Y')) )/7) as Wed from dual;
SELECT ceil(( 7+(trunc(to_date('06-NOV-2009'),'d')-trunc(to_date('06-NOV-2009'),'Y')) )/7) as Thu from dual;
Cheers!!!
Bhushan
Edited by: Buga on Oct 29, 2009 10:46 AM

How to get the week number for a given date?

hi guys,
what is coding to get the week number for a given date?
For example, 1/1/05 is week 1. then 8/1/05 is week 2.

The second parameter to pass to the method is supposed to be one of the month constants JANUARY - DECEMBER. It happens to be that their numerical values are 0-11, not 1-12, so your "12" refers to the "13th" month of the year.
givenDate = new GregorianCalendar(2003, Calendar.DECEMBER, 31);
If you want to construct dates and times from strings like you seem to be, look into SimpleDateFormat http://javaalmanac.com/egs/java.text/ParseTime.html
(even still I got WEEK_OF_YEAR as 1 which is true but not really what I expected, excuse my previous reply but I wanted to check the facts before posting this)

How to get start date of the period for a given date from cube

I have a situation where i need to find the start day of the period for a given date. is there a way to know that. i want to use that in my report. i enter the date from my report(i have date parameter), depends on the date, i want to display the start day
of the period. how can i write expression for that in my report?
ram

Hi ramprasad74,
According to your description, you are using Analysis Services as a data source for the report, the cube has hierarchy: Fyear, FQuarter, FPeriod, fweek, Fdate. You want to add a date parameter to the report, after you changed value of the parameter, the
report will return the first day of FPeriod.
To achieve your goal, we need to add a parameter to the report, then use the parameter in mdx query. For detail information, please refer to the following steps:
In the Report Data pane, right-click on a dataset created from a SQL Server Analysis Services data source type, and then click Query. The MDX query designer opens in Design mode.
On the toolbar, click Design to toggle to Query mode.
On the MDX query designer toolbar, click Query Parameters symbol. The Query Parameters dialog box opens.
In the Parameter column, click <Enter Parameter>, and then type the name of a parameter.
In the Dimension column, choose a value from the drop-down list.
In the Hierarchy column, choose a value from the drop-down list.
In the Default column, from the drop-down list, select a single value.
Click OK.
In query designer dialog box, type the mdx query like below:
with member [Measures].[FirstChild]
as
[Date].[Fiscal].currentmember.parent.firstchild.name
select {[Measures].[FirstChild]} on 0,
[Date].[Fiscal].[Date].members on 1
from
( SELECT ( STRTOSET(@ParameterName, CONSTRAINED) ) on 0
from
[Cube]
Here are relevant threads you can reference:
https://social.msdn.microsoft.com/forums/sqlserver/en-US/c7146ac3-40ea-4d53-b321-c707aebbd405/how-to-pass-date-parameter-to-mdx-query
https://social.msdn.microsoft.com/forums/sqlserver/en-US/fd12a865-bc90-4a65-af42-ce38a8cfa29b/pass-date-time-parameter-to-mdx-query-ssrs
If you have any more questions, please feel free to ask.
Thanks,
Wendy Fu
If you have any feedback on our support, please click
here.

Print MULTIPLE sales order for a given date

Hi Gurus,
My requirement is to print sales order for a given date like the one given below.
VL71 - Output from Outbound Deliveries
VL74 - Output from Handling
VF31 - Output from Billing
VOK4- Output Determination: Inventory mgmt.
Is there any T.code for printng multiple sales order instead one-by-one printing using VA02/VA03?
Please hlep me in this regard.
Regards,
Anbu

Hi anbu,
This is very much possible to mass printing for sales orders.
Goto SE38 T.Code.
Enter the program name as "RSNAST00".
Press Execute or F8
Select output application as "V1" which is sales.
Enter your object key here.
Enter your output type.
Select the transaction medium as "1".
Tick "send again".
Press on Execute or "f8".
Regards,
Krishna.

Find 3rd friday of the month for a given date

how to find out 3rd friday of the month for a given date? I can always pass the first day of the month as input
eg, input date is 01-JAN-09. need to get the 3rd friday 16-JAN-09 (Jan has 5 fridays 02, 09, 16,23,30)
input date : 01-feb-09, need to get 20-feb-09
Edited by: user520824 on Apr 1, 2009 12:30 PM

NLS independent solution:
SELECT DT,
        TO_CHAR(DT,'FMDay') day,
        CASE
          WHEN TRUNC(TRUNC(DT,'MM') + 7,'IW') - 3 < TRUNC(DT,'MM') THEN TRUNC(TRUNC(DT,'MM') + 7,'IW') + 18
          ELSE TRUNC(TRUNC(DT,'MM') + 7,'IW') + 11
        END THIRD_FRIDAY_OF_THE_MONTH
FROM (
         SELECT TO_DATE(LEVEL || '/2009','MM/YYYY') DT
           FROM DUAL
           CONNECT BY LEVEL < 13
DT        DAY       THIRD_FRI
01-JAN-09 Thursday 16-JAN-09
01-FEB-09 Sunday    20-FEB-09
01-MAR-09 Sunday    20-MAR-09
01-APR-09 Wednesday 17-APR-09
01-MAY-09 Friday    15-MAY-09
01-JUN-09 Monday    19-JUN-09
01-JUL-09 Wednesday 17-JUL-09
01-AUG-09 Saturday 21-AUG-09
01-SEP-09 Tuesday   18-SEP-09
01-OCT-09 Thursday 16-OCT-09
01-NOV-09 Sunday    20-NOV-09
DT        DAY       THIRD_FRI
01-DEC-09 Tuesday   18-DEC-09
12 rows selected.
SQL> SY.

Name of users of a particular Tcode for a given date range

Hi experts,
I am making an alv where inputs will be
1> T_code(as parameter)
2> Date Range(as Select options)
I have to display the following fields:::
1> User name
2> Frequency of use the Tcode for the given Date range.
Please give me the tables where I can get the relation of those fields.
N.B. I know the transaction AL08 and SM04.But it won't solve my purpose.
Thanx in advance,
Sourav

>
SOURAV PAUL wrote:
> Hi experts,
> I am making an alv where inputs will be
> 1> T_code(as parameter)
> 2> Date Range(as Select options)
by creating the report As per your this requirement you need not to create any Bulk on your SAP.Just use STAD/STAT transaction they are availabe for this purpose.
and more you may track by security log audit by SM20 get these details.
i'm worried about tables which sre storing these details.

[HELP] Error: "JDBC theme based FOI support is disabled for the given data"

Hi all,
I have already set up MapViewer version 10.1.3.3 on BISE1 10g OC4J server. I am current using JDK 1.6. I create a mvdemo/mvdemo user for demo data.
The MapViewer demo is running fine with some demo without CHART. But give this error with some maps that have CHART like: "Dynamic theme, BI data and Pie chart style", "Dynamic theme and dynamic Bar chart style". The error is:
----------ERROR------------
Cannot process the FOI response from MapViewer server. Server message is: <?xml version=\"1.0\" encoding=\"UTF-8\" ?> <oms_error> MAPVIEWER-06009: Error processing an FOI request.\nRoot cause:FOIServlet:MAPVIEWER-06016: JDBC theme based FOI support is disabled for the given data source. [mvdemo]</oms_error>.
----------END ERROR------
I searched many threads on this forum, some point me to have this allow_jdbc_theme_based_foi="true" in mapViewerConfig.xml and restart MapViewer.
<map_data_source name="mvdemo"
jdbc_host="localhost"
jdbc_sid="bise1db"
jdbc_port="1521"
jdbc_user="mvdemo"
jdbc_password="mvdemo"
jdbc_mode="thin"
number_of_mappers="3"
allow_jdbc_theme_based_foi="true"
/>
Error Images: [http://i264.photobucket.com/albums/ii176/necrombi/misc/jdbcerror.png|http://i264.photobucket.com/albums/ii176/necrombi/misc/jdbcerror.png]
I have this configuration, but no luck. Could anyone show me how to resolve this problem?
Rgds,
Dung Nguyen

Oop, i managed to have this prob resolved!
My prob may come from this I use both scott and mvdemo schema for keeping demo data (import demo data).
Steps i made to resolve my prob are:
1) Undeploy MapViewer from Application Server Control (http://localhost:9704/em in my case)
2) Drop user mvdemo
3) Download mapviewer kit from Oracle Fusion Middleware MapViewer & Map Builder Version 11.1.1.2
4) Deploy MapViewer again
5) Recreate mvdemo and import demo data
6) Run mcsdefinition.sql, mvdemo.sql with mvdemo user (granted dba already)
7) Edit mapViewerConfig.xml
<map_data_source name="mvdemo"
jdbc_host="dungnguyen-pc"
jdbc_sid="bise1db"
jdbc_port="1521"
jdbc_user="mvdemo"
jdbc_password="!mvdemo"
jdbc_mode="thin"
number_of_mappers="3"
allow_jdbc_theme_based_foi="true"
/>
Save & Restart MapViewer
And now, all demos run fine. Hope this helpful for who meet prob like my case.

Table and fields for " Batch Code Date " and "Shelf Life days".

Hi All,
What is the field for " Batch Code Date " and "Shelf Life days".
And in which table are they present.
Thanks & Regards,
Ahmed.

Check the table
MCHA Batches
Field VFDAT Shelf Life Expiration or Best-Before Date

How to query a item stock quantity for a given date

Hi there,
I need to query the stock quantity of an item for a given date. For example, i want to know how many pieces of A i have on stock at the 20th of march 2009.
I know there is a report, but i need the value for a subquery.
Regards Steffen

Sorry Gordon,
Your query is not wrong, far from me to insult your work. It does indeed make full sense if the business process allows the item description to change.
If not, we can avoid a "inner join" = smaller, cleaner and (theoritically) faster query
Here is your code with the little review:
SELECT T0.ItemCode, T0.Dscription, sum(T0.InQty - T0.OutQty) as 'On Hand'
FROM DBO.OINM T0
WHERE T0.DocDate <= '[%0]' and T0.ItemCode = '[%1]'
GROUP BY T0.ItemCode, T0.Dscription
Cheers
tested on 2007 SP00 PL46

For a given date required last week day

Similar Messages

Maybe you are looking for