FM that gives number of day in the week for the given date

Hi,
I have a requirement to find the number of the day in a week for the given date. For example, 07/09/2009 is Thursday & 4th day of the week. Is there any FM to accomplish this task?
Appreciate your help in Advance.
Thanks,
Kannan.

Hi Kannan,
ISH_GET_DAY_OF_WEEK.
Regards,
Dilek

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How to find the Day on a Week for any given Date

Hi..... I need your help to find out the Day on a Week for any given Date .
Say if the Date is 31/12/2009 , what would be the Day on a Week for this Date.
Are there any fucntions available to determine the same?
Please let me know....Thanks in Advance
Regards
Smita

Hi ,
You can using the following peice of code to get the Day of a Week for the given date :
Calendar now = Calendar.getInstance();
System.out.println("Current date : " + (now.get(Calendar.MONTH) + 1)
     + "-" + now.get(Calendar.DATE) + "-" + now.get(Calendar.YEAR));
//create an array of days
//Day_OF_WEEK starts from 1 while array index starts from 0
String[] strDays = new String[]{"Sunday", "Monday", "Tuesday", "Wednesday", "Thusday",   "Friday", "Saturday" };
String day_of_week = strDays[now.get(Calendar.DAY_OF_WEEK) - 1];
System.out.println("Current day is : " + strDays[now.get(Calendar.DAY_OF_WEEK) - 1] );
Edited by: Ritushree Saha on Jun 4, 2009 1:09 PM

How to get the date of first day of a week for a given date

Hi gurus
can any one say me how to get the date of first day(date of Sunday) of a week for a given date in a BW transformations. For example for 02/23/2012 in source i need to get 02/19/2012(Sunday`s date) date in the result. I can get that start date of a week using BWSO_DATE_GET_FIRST_WEEKDAY function module. But this function module retrieves me the start date as weeks monday(02/20/2012) date. But i need sundays(02/19/2012) date as the start date. So it would be really great if anyone sends me the solution.
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Hi,
The simplest way would be to subtract 1 from the date date which you are already getting in transformation routine, but instead of doing that subtraction manually which might need bit of errort, you can simply use another FM to subtract 1 from given date.
RP_CALC_DATE_IN_INTERVAL
Regards,
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How to get start date of the period for a given date from cube

I have a situation where i need to find the start day of the period for a given date. is there a way to know that. i want to use that in my report. i enter the date from my report(i have date parameter), depends on the date, i want to display the start day
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ram

Hi ramprasad74,
According to your description, you are using Analysis Services as a data source for the report, the cube has hierarchy: Fyear, FQuarter, FPeriod, fweek, Fdate. You want to add a date parameter to the report, after you changed value of the parameter, the
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To achieve your goal, we need to add a parameter to the report, then use the parameter in mdx query. For detail information, please refer to the following steps:
In the Report Data pane, right-click on a dataset created from a SQL Server Analysis Services data source type, and then click Query. The MDX query designer opens in Design mode.
On the toolbar, click Design to toggle to Query mode.
On the MDX query designer toolbar, click Query Parameters symbol. The Query Parameters dialog box opens.
In the Parameter column, click <Enter Parameter>, and then type the name of a parameter.
In the Dimension column, choose a value from the drop-down list.
In the Hierarchy column, choose a value from the drop-down list.
In the Default column, from the drop-down list, select a single value.
Click OK.
In query designer dialog box, type the mdx query like below:
with member [Measures].[FirstChild]
as
[Date].[Fiscal].currentmember.parent.firstchild.name
select {[Measures].[FirstChild]} on 0,
[Date].[Fiscal].[Date].members on 1
from
( SELECT ( STRTOSET(@ParameterName, CONSTRAINED) ) on 0
from
[Cube]
Here are relevant threads you can reference:
https://social.msdn.microsoft.com/forums/sqlserver/en-US/c7146ac3-40ea-4d53-b321-c707aebbd405/how-to-pass-date-parameter-to-mdx-query
https://social.msdn.microsoft.com/forums/sqlserver/en-US/fd12a865-bc90-4a65-af42-ce38a8cfa29b/pass-date-time-parameter-to-mdx-query-ssrs
If you have any more questions, please feel free to ask.
Thanks,
Wendy Fu
If you have any feedback on our support, please click
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Find 3rd friday of the month for a given date

how to find out 3rd friday of the month for a given date? I can always pass the first day of the month as input
eg, input date is 01-JAN-09. need to get the 3rd friday 16-JAN-09 (Jan has 5 fridays 02, 09, 16,23,30)
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Edited by: user520824 on Apr 1, 2009 12:30 PM

NLS independent solution:
SELECT DT,
        TO_CHAR(DT,'FMDay') day,
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          WHEN TRUNC(TRUNC(DT,'MM') + 7,'IW') - 3 < TRUNC(DT,'MM') THEN TRUNC(TRUNC(DT,'MM') + 7,'IW') + 18
          ELSE TRUNC(TRUNC(DT,'MM') + 7,'IW') + 11
        END THIRD_FRIDAY_OF_THE_MONTH
FROM (
         SELECT TO_DATE(LEVEL || '/2009','MM/YYYY') DT
           FROM DUAL
           CONNECT BY LEVEL < 13
DT        DAY       THIRD_FRI
01-JAN-09 Thursday 16-JAN-09
01-FEB-09 Sunday    20-FEB-09
01-MAR-09 Sunday    20-MAR-09
01-APR-09 Wednesday 17-APR-09
01-MAY-09 Friday    15-MAY-09
01-JUN-09 Monday    19-JUN-09
01-JUL-09 Wednesday 17-JUL-09
01-AUG-09 Saturday 21-AUG-09
01-SEP-09 Tuesday   18-SEP-09
01-OCT-09 Thursday 16-OCT-09
01-NOV-09 Sunday    20-NOV-09
DT        DAY       THIRD_FRI
01-DEC-09 Tuesday   18-DEC-09
12 rows selected.
SQL> SY.

Getting the day of the week from a given date help plz

private String getWeekDay( ) - return the correct week day given the day, month and year for this date.
I had given this an effort and got stumped, my inital thought was to use mods but any input would be helpful

try
int dow = Calendar.getInstance().get(Calendar.DAY_OF_WEEK);

Discovering the day of the week for given date

hi guys, im trying to discover the day of the week for a given date when i do this it works fine:
select to_char(sysdate,'FMDAY') from dual
however, when i try to pass in my own value as a parameter i get the error: invalid number
select to_char(:mydate,'FMDAY') from dual .
the value im passing through to mydate is 21/02/2011 so i have no idea why it is not working. Any help would be greatly appreciated. thanks
Edited by: 786733 on 21-Feb-2011 03:41

786733 wrote:
hi guys, im trying to discover the day of the week for a given date when i do this it works fine:
select to_char(sysdate,'FMDAY') from dual
however, when i try to pass in my own value as a parameter i get the error: invalid number
select to_char(:mydate,'FMDAY') from dual .
the value im passing through to mydate is 21/02/2011 so i have no idea why it is not working. Any help would be greatly appreciated. thanksyou're probably passing in a string instead of a date, so you need to convert it to a date with the appropriate format.
select to_char(to_date(:mydate,'DD/MM/YYYY'),'FMDAY') from dual

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Customer Exit for Number of Days from 1 st Apr to last date of Month Enter

Hello BI Experts,
I have a requirement to count the number of days from 1 st April of current year to the last date of month entered.
For example : The use will enter say July 2010 or 003.2010 (as Fiscal Year Variant is V3 ).
Today is 14 July ...So we have to first find out the end date of the July month ie 31 st July
Then go to 1 st April 2010.
Now calculate the Number of days between 1 st April to 31 st July 2010.
I consider I have to create two Customer Exit variable
as below
1 st customer exit Bex variable say ZLY_MTH ( Last day of Month Entered)
and i_step = 1
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i_step =1 .
Please provide me the logic for the above two.
Thanks in Advance.
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PSUDEO CODE:
1. Initially LOOP AT I_T_VAR_RANGE INTO LOC_VAR_RANGE WHERE VNAM = 'ZMONTH'.
2. Get the Month input using VAR_MONTH2 = LOC_VAR_RANGE-LOW+4(2)
3. Now calculate Month+1: VAR_MONTH2 = VAR_MONTH2 + 1 (Refer **)
4. Now calculate the Current Year: VAR_YEAR = LOC_VAR_RANGE-LOW+0(4).
5. Get the 1st Day of the Month (VAR_MONTH2): CONCATENATE '01' '/' VAR_MONTH2 '/' VAR_YEAR INTO L_S_RANGE-LOW.
6. SUBRACT 1 (0DATE) from this DATE (This will give the logic for last day of the current month)
Insert this code also for using the date conversions
        CALL FUNCTION 'CONVERSION_EXIT_ALPHA_INPUT'
          EXPORTING
            INPUT = VAR_MONTH2
          IMPORTING
            OUTPUT = VAR_MONTH2.
Pls. check out this logic. Guess it would solve your need.
Thanks,
Arun Bala

Find the 'DAY' for a given 'DATE'

Hi Folks,
I need a help regarding finding the day for a given date.
My requirement is that..,
If I enter a date using 'parameters', it should write the 'day' for the corresponding date.
To be more specific.....,
if I enter date as ' 07/15/2008 ' it should return me the day as 'Tuesday'.
Regards,
Naveen G

HI,
FM LIST WITH RESPECT TO DAY, WEEK, AND MONTH.
CALCULATE_DATE : Calculates the future date based on the input .
DATE_TO_DAY : Returns the Day for the entered date.
DATE_COMPUTE_DAY : Returns weekday for a date
DATE_GET_WEEK : Returns week for a date
RP_CALC_DATE_IN_INTERVAL : Add days / months to a date
MONTHS_BETWEEN_TWO_DATES : To get the number of months between the two dates.
END_OF_MONTH_DETERMINE_2 : Determines the End of a Month.
HR_HK_DIFF_BT_2_DATES : Find the difference between two dates in years, months and days.
FIMA_DAYS_AND_MONTHS_AND_YEARS : Find the difference between two dates in years, months and days.
MONTH_NAMES_GET : Get the names of the month
WEEK_GET_FIRST_DAY : Get the first day of the week
HRGPBS_HESA_DATE_FORMAT : Format the date in dd/mm/yyyy format
SD_CALC_DURATION_FROM_DATETIME : Find the difference between two date/time and report the difference in hours
L_MC_TIME_DIFFERENCE : Find the time difference between two date/time
HR_99S_INTERVAL_BETWEEN_DATES : Difference between two dates in days, weeks, months
LAST_DAY_OF_MONTHS : Returns the last day of the month
DATE_CHECK_PLAUSIBILITY :Check for the invalid date.
Reward points if useful,
siri

Getting the week number for a given date

Oracle Database 11g Enterprise Edition Release 11.1.0.7.0 - 64bit Production
PL/SQL Release 11.1.0.7.0 - Production
CORE 11.1.0.7.0 Production
TNS for 64-bit Windows: Version 11.1.0.7.0 - Production
NLSRTL Version 11.1.0.7.0 - Production
Hello all.
I am currently migrating our product from SQL SERVER to ORACLE and have the following issue.
Basically I'm just trying to get the year week number for a given date but I'm having trouble with Oracle as it seems to think that the weeks run from Thursday to Thursday?. I presume this is something to do with the fact that the first day of the year was Thursday?
e.g.
SQL SERVER:
select DATEPART(wk, '2009-10-24') as Sat -- 43 - correct
select DATEPART(wk, '2009-10-25') as Sun -- 44 - correct
select DATEPART(wk, '2009-10-26') as Mon -- 44 - correct
select DATEPART(wk, '2009-10-27') as Tue -- 44 - correct
select DATEPART(wk, '2009-10-28') as Wed -- 44 - correct
select DATEPART(wk, '2009-10-29') as Thu -- 44 - correct
select DATEPART(wk, '2009-10-30') as Fri -- 44 - correct
select DATEPART(wk, '2009-10-31') as Sat -- 44 - correct
select DATEPART(wk, '2009-11-1') as Sun -- 45 - correct
select DATEPART(wk, '2009-11-2') as Mon -- 45 - correct
select DATEPART(wk, '2009-11-3') as Tue -- 45 - correct
select DATEPART(wk, '2009-11-4') as Wed -- 45 - correct
select DATEPART(wk, '2009-11-5') as Thu -- 45 - correct
ORACLE:
SELECT to_char(to_date('24-OCT-2009'), 'ww') as Sat from dual; -- 43 correct
SELECT to_char(to_date('25-OCT-2009'), 'ww') as Sun from dual; -- 43 incorrect - should be 44
SELECT to_char(to_date('26-OCT-2009'), 'ww') as Mon from dual; -- 43 incorrect - should be 44
SELECT to_char(to_date('27-OCT-2009'), 'ww') as Tue from dual; -- 43 incorrect - should be 44
SELECT to_char(to_date('28-OCT-2009'), 'ww') as Wed from dual; -- 43 incorrect - should be 44
SELECT to_char(to_date('29-OCT-2009'), 'ww') as Thu from dual; -- 44 correct
SELECT to_char(to_date('30-OCT-2009'), 'ww') as Fri from dual; -- 44 correct
SELECT to_char(to_date('31-OCT-2009'), 'ww') as Sat from dual; -- 44 correct
SELECT to_char(to_date('1-NOV-2009'), 'ww') as Sun from dual; -- 44 incorrect - should be 45
SELECT to_char(to_date('2-NOV-2009'), 'ww') as Mon from dual; -- 44 incorrect - should be 45
SELECT to_char(to_date('3-NOV-2009'), 'ww') as Tue from dual; -- 44 incorrect - should be 45
SELECT to_char(to_date('4-NOV-2009'), 'ww') as Wed from dual; -- 44 incorrect - should be 45
SELECT to_char(to_date('5-NOV-2009'), 'ww') as Thu from dual; -- 45 correct
Now I don't want to get into a discussion with regard to locales etc.
In my world (and is seems SQL SERVER's) the first day of the week is Sunday and the last Saturday.
Is there some NLS_? setting or something that I'm missing?
thanks for any help on this.
Andy

This is what you need.
SELECT ceil(( 7+(trunc(to_date('25-OCT-2009'),'d')-trunc(to_date('25-OCT-2009'),'Y')) )/7) FROM dual
HTH!!!
--tested all these statements.
Works as you wish!!
SELECT ceil(( 7+(trunc(to_date('24-OCT-2009'),'d')-trunc(to_date('24-OCT-2009'),'Y')) )/7) as Sat from dual;
SELECT ceil(( 7+(trunc(to_date('25-OCT-2009'),'d')-trunc(to_date('25-OCT-2009'),'Y')) )/7) as Sun from dual;
SELECT ceil(( 7+(trunc(to_date('26-OCT-2009'),'d')-trunc(to_date('26-OCT-2009'),'Y')) )/7) as Mon from dual;
SELECT ceil(( 7+(trunc(to_date('27-OCT-2009'),'d')-trunc(to_date('27-OCT-2009'),'Y')) )/7) as Tue from dual;
SELECT ceil(( 7+(trunc(to_date('28-OCT-2009'),'d')-trunc(to_date('28-OCT-2009'),'Y')) )/7) as Wed from dual;
SELECT ceil(( 7+(trunc(to_date('29-OCT-2009'),'d')-trunc(to_date('29-OCT-2009'),'Y')) )/7) as Thu from dual;
SELECT ceil(( 7+(trunc(to_date('30-OCT-2009'),'d')-trunc(to_date('30-OCT-2009'),'Y')) )/7) as Fri from dual;
SELECT ceil(( 7+(trunc(to_date('01-NOV-2009'),'d')-trunc(to_date('01-NOV-2009'),'Y')) )/7) as Sat from dual;
SELECT ceil(( 7+(trunc(to_date('02-NOV-2009'),'d')-trunc(to_date('02-NOV-2009'),'Y')) )/7) as Sun from dual;
SELECT ceil(( 7+(trunc(to_date('03-NOV-2009'),'d')-trunc(to_date('03-NOV-2009'),'Y')) )/7) as Mon from dual;
SELECT ceil(( 7+(trunc(to_date('04-NOV-2009'),'d')-trunc(to_date('04-NOV-2009'),'Y')) )/7) as Tue from dual;
SELECT ceil(( 7+(trunc(to_date('05-NOV-2009'),'d')-trunc(to_date('05-NOV-2009'),'Y')) )/7) as Wed from dual;
SELECT ceil(( 7+(trunc(to_date('06-NOV-2009'),'d')-trunc(to_date('06-NOV-2009'),'Y')) )/7) as Thu from dual;
Cheers!!!
Bhushan
Edited by: Buga on Oct 29, 2009 10:46 AM

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Can somebody give me the formula for the balance column in a check register please? I am trying to setup like sample in iWork but am missing something.

Can somebody give me the formula for the balance column in a check register please? I am setting the register up like the sample in iWork 09 but I seem to be missing something in the formula.

OM,
The way the checking account balance column works is to designate one cell for the starting balance, indicate income with positive figures and outgo with negative figures, summing the transactions and adding the sum to the starting figure.
The formula used, =$F$1+SUM(OFFSET(F3,3-ROW(),-1,ROW()-2)), is not too difficult to understand if you study the syntax for Offset. The author of this template didn't do us any favors because the expression could have been written more clearly, in my opinion. I'll explain how it's done in the template, and then how I would have written it. With the two approaches you may be able to see what it's all about.
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How I would have written the balance expression:
=F$1+SUM(OFFSET(E$3,0,0,ROW()-2))
I believe it's easier to follow.
The starting balance is still in F1, but only the row needs to be absolute - a fine point, I know.
In my expression the base cell for the Offset function is the first entry cell of the transactions, E3. The row needs to be absolute, there is no reason for the base cell to move about as it does in the author's version.
In my approach, both the row and column offsets are zero. We always start at E3.
In my approach, the number of rows in the range is the current row number minus 2, just as in the author's expression. That means we include all rows from Row 3 to the current row.
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Jerry

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*https://support.mozilla.org/kb/Browsing+basics
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*http://en.wikipedia.org/wiki/Screenshot
*https://support.mozilla.org/kb/how-do-i-create-screenshot-my-problem
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FM that gives number of day in the week for the given date

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