For String == return true, then returns false in another app.

Question

First App:
import java.awt.*;
import java.awt.event.*;
public class again
     TextField t1, t2;
     public again()
          Frame f=  new Frame();
          t1 = new TextField(10);
          t2 = new TextField(10);
          Button b1 = new Button("Compare");
          b1.addActionListener(new ActionListener()
               public void actionPerformed(ActionEvent e)
                    String one = t1.getText();
                    if(one=="123")
                         System.out.println("true");
                    else
                         System.out.println("false");
          f.add(t1);
          f.add(t2);
          f.add(b1);
          f.setLayout(new FlowLayout(FlowLayout.LEFT));
          f.setSize(500,500);
          f.setVisible(true);
     public static void main(String args[])
          new again();
}Second App:
public class comp
     public static void main(String [] arg)
          String str1 ="123";
          String str2 ="123";
          if(str1=="123")
               System.out.println("true");
          else
               System.out.println("false");
}

Answer 1

DogsAreBarking wrote:
None of these books talk about compile time pool constants. Read the JLS.
As far as i know equals is used to compare reference types and == is used to compare primitive types.Read your books again. So why would strA == strB not lead to a compiler error if it's just for primitives? '==' is the operator to check for referential identity or primitive equality.
May I quote you when you were told not to use '==':
yes yes yes... i know all that