Formula For Calculating An Average

I have the below formula in a group footer (Group Footer #1) that is suppose to calculate the average between the accumlated number of days (i.e. {@Days Taken}) divided by the number of records (i.e. Count (). The value for the number of days is correct and the value for the record count is correct. For some reason the value for the average is not correct.  The average is not re-calculating when there is a new group.  The average is repeated for each group.  Is there anything wrong with this formula ?
Sum ({@Days Taken})/Count ()

Lenell,
You need to tell it to divide the sums per group.
So;
Sum ({@Days Taken},)/Count (,)
Replace with the field that you are grouping on.

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    Thanks

    ellroy wrote:
    I basically want a formula where I can average Letters out to a B- or C+. Can I do this from just letters alone or do I need to assign numbers. Speaking to my curriculum coordinator, she said stick to LETTERS and see if we can sort out something for that as we don't officially report in numbers.
    So that would mean I would need an average formula that would calculate B + C + C + D + A into a single Letter. I dont know if it is possible without using numbers. I hope you understand what I'm trying to explain. It's quite hard!
    You say where the cutoffs are, is that A=90-100%?
    Can you just use letters to make an average of the letter? 
    AVERAGE, which calculates the arithmetic mean of a set of values, works with numerical values.
    On your posted layout, you have a table showing the letter equivalent of a percentage score:
    A score under 40 = E
    A score 40 or higher, but under 50 = D
    A score 50 or higher, but under 65 = C
    A score 56 or higher, but under 85 = B
    A score 85 or higher = A
    Those numerical scores may be summed, averaged, and a letter grade assigned. With the specifications given in that table, the letter grade will not include a + or -.
    Your layout includes nine numerical scores for the first student (all of which are well under 40. My assumption here is that each is the student's score out of the number in the same column of row 3 (ie, the first, 13, is 13 out of 14, the second is 10 out of 16, etc,)
    This raises a question:
    Does each point noted contribute equally to the final average?
    Or
    Does each quiz/exercise contribute equally to the final average?
    For the letter grades to be averaged, you will need to set a specific numerical equivalent (not a range) for each letter grade.
    For the letter grades and number grades to be combined into a single final letter grade, the numerical equivalents noted above must be chosen with that goal in mind, OR the numerical scores must be converted into letter grades, then reconverted into specific numerical equivalents for each letter grade, inserted into the set of (converted) letter grades, averaged, then reconverted to the equivalent letter grade.
    As you can see, there are yet a few hurdles to overcome.
    Regards,
    Barry

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