From ZipEntry to File without uncompressing?

Question

Hello,
I have some third party Java code that requires a java.io.File for its constructor input argument. The third party code only needs to read the file. It does this using RandomAccessFile.
In my code I am originally working with a ZipFile. So my question is, is there a way to modify a ZipEntry to a java.io.File without uncompressing or writing to disk, so I can pass it to the third party software? Or do I have to unzip it, pass that file to third party code, and then delete it after all is complete?
// Get zip file
ZipFile zipFile = new ZipFile(args[0]);
// get the important zip entry
ZipEntry mainEntry = zipFile.getEntry("main.txt");
What do I do here to convert mainEntry to a
java.io.File without uncompressing/writing the
file to disk???? Is this possible????
// This is the third party object which requires a File for
// input and which I REALLY do not want to change.
ThirdPartyObject tro = new ThirdPartyObject(mainEntryFile);
tro.doStuff();

Answer 1

durban_z wrote:
I have some third party Java code that requires a java.io.File for its constructor input argument. The third party code only needs to read the file. It does this using RandomAccessFile.If it needs a random access file, you have no choice (without writing way too much code) but to give it a real file. OTOH, if the consumer only needs a stream, you can just pass the zip stream instead without writing to a file first.