Function: Return First Line of Another Cell (before line break)

Howdy all!
I have a bunch of cells that have multiple lines (line breaks created by pressing option-return). I want to create a function that will return the first line of a cell (IE: the text before the first line break). Any thoughts on how to do this?
IE, if A1=
Test 1
Test 2
Test 3
Then I want to point the function from another cell to A1 and have it return Test 1.
The code would look like this:
=REPLACE(A1,SEARCH([line break],A1),LEN(A1)−SEARCH([line break],A1)+1,"")
(IE: It searches for the line break, then replaces everything from that part on with nothing.)
The problem is that I don't know how to get Numbers to think about [line break]. Thought that =char() would work but I don't know the unicode to put in (85, 2028, and 2029 didn't work).
Thoughts?
Matthew

Thanks, I thought that I had tried that at some point, but I guess I hadn't done it correctly!
I made one adjustment, I subtracted one from the SEARCH. The formula as you have it actually returns the line break along with the first line (you can't see it in your example because your rows are taller). (I also removed the third peramiter from the SEARCH, but that is a personal preference.) Outside of that this works perfectly. Thanks!
B1=LEFT(A1,SEARCH("
",A1)−1)
Matthew

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nick_harambee wrote:
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create or replace function f_get_comp_os(p_fdt date)
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If you could edit your first post to change the subject line to include [SOLVED], that would be helpful.
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[email protected]

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Don't Retire Technet

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Yvan KOENIG (from FRANCE dimanche 11 janvier 2009 16:31:35)
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arun160411 wrote:
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