Function to get all Level members in essbase

Hi All,
Could any one please tell me what is the function to get all Level Members in Essbase.

Hi IMD,
It sounds like you are looking for the @LEVMBRS function. It has two parameters, a dimension and the level number. You should also review the @RELATIVE function.
For much more in-depth information review the Technical Reference and Database Admin Guides which are part of the 11.1 docs.
Essbase 11.1 docs - http://download.oracle.com/docs/cd/E12825_01/nav/portal_3.htm
Database Admin Guide - http://download.oracle.com/docs/cd/E12825_01/epm.111/esb_dbag.pdf
Technical Reference - http://download.oracle.com/docs/cd/E12825_01/epm.111/esb_techref/frameset.htm?launch.htm
Chapter 22 in the Database Admin Guide covers use of Formuals
See the Member Set Functions of the Tech Ref
http://download.oracle.com/docs/cd/E12825_01/epm.111/esb_techref/frameset.htm?func_memsettype.htm
Regards,
-John

Similar Messages

  • Report script command to get all Level 0 members of a given member

    Hi,
    Is there any Report script command to get all Level 0 members of a given member (Parent)? (very similar to @RELATIVE (mbrName, 0) in Calc Scripts).
    <DIMBOTTOM gives all the level 0 members in the dimension.
    There is a command called
    <LEAVES mbrName
    This works only for ASO.
    Is there anything similar for BSO?
    Appreciate your thoughts.
    Thanks,
    Ethan.
    Edited by: user11397030 on Dec 15, 2009 11:50 AM
    Edited by: user11397030 on Dec 15, 2009 11:51 AM

    from my blog on report scripts at
    http://glennschwartzbergs-essbase-blog.blogspot.com/2008_07_01_archive.html
    Third, there is a command to stay away from, its DimBottom. [edited] Like @CURRMBR in calc scripts, DimBottom is one of those commands that is very slow. If you use Query designer to create a report, it uses a better way. It uses the link command. In sample.basic to get all level 0 products it uses
    <Link ((<LEV("Product", 0)) AND ( <DESC("Product")))

  • Function to get all the months name of a year from dual

    HI GURUS
    Is there any function to get all the months name of a year from dual
    thanks in advance

    What about this --
    satyaki>
    satyaki>select months_name
      2  from (
      3         select to_char(add_months(trunc(sysdate,'YEAR'),rownum-1),'MONTH') months_name
      4         from dual
      5         connect by rownum<=12
      6       );
    MONTHS_NAME
    JANUARY
    FEBRUARY
    MARCH
    APRIL
    MAY
    JUNE
    JULY
    AUGUST
    SEPTEMBER
    OCTOBER
    NOVEMBER
    MONTHS_NAME
    DECEMBER
    12 rows selected.
    satyaki>Regards.
    Satyaki De.

  • Get all the members having particular UDA's

    Hi,Is there any way in Essbase Java API to get the members which are having any of the UDA's given in a list? For example, If I have three UDA's UDA1, UDA2, UDA3. Now I want to get the members in a cube which are having any of these UDA's attached to it. I knowIEssMemberSelection.executeQuery(mbrName, queryType, queryOptions, dimName, UDAName, input2) will give me the members which are having UDAName which attached as UDA. I am looking for a method which can return me all the members if I give the arguements as an array

    No, there isn't a function that takes an array of UDAs and returns members that has one of the UDAs in the array. However, you can do the member selection multiple times, once for each UDA, and gather the info about the members that you need.Tim TowApplied OLAP, Inc.

  • Getting all level 0 member in a outline

    what is the best way to get all the level 0 member in a outline
    Please advise

    ok so you're doing a one-off exercise to identify non-level 0 data and you have a lot of members.
    I would still probably just dump it into Excel and then load it to a database to compare against the data.
    What you can do in Excel is turn on 'Navigate without Data' which gets you the list of members without retrieving data (a LOT faster). In Smartview it is under the Data Options tab. (Zoom In Level is under the General tab but you probably knew that)
    An alternative is to use OLAP Underground Outline Extracter and use a method other than Parent Child format.

  • Powershell to get all the members in about 20 DynamicDistribution group in exchange 2010

    I have about 20 DynamicDistribution groups in my exchange 2010 enviroment.  I need to run a report to show all the members in each group.  How can I accomplish this with powershell ?  thanks for all the help

    I assume you don't want the output of all 20 groups dumped into one single list.  So, you'd just use this:
    Use the Shell to preview the list of members of a dynamic distribution
    group
    This example returns the list of members for the dynamic distribution group Full Time Employees. The first command stores the dynamic distribution group object in the variable $FTE.
    The second command uses the Get-Recipient cmdlet to list the recipients that match the criteria defined for the dynamic distribution group.
    $FTE = Get-DynamicDistributionGroup "Full Time Employees"
    Get-Recipient -RecipientPreviewFilter $FTE.RecipientFilter
    For detailed syntax and parameter information, see Get-DynamicDistributionGroup and Get-Recipient.
    Mike Crowley | MVP
    My Blog --
    Baseline Technologies

  • BAPI to get  all levels of all hierarchies of all dimensions of a cube

    Hi Experts,
    Is there are way to get all properties of all levels of all hierarchies of all dimensions of a cube (InfoCube, ODSObject, QueryCube, InfoSet) in one BAPI call?
    Any useful answer will be rewarded with suitable points.
    Thanks,
    Rohan

    Hi
    Check the following Cube related BAPIS
    BAPI_CUBE_ACTIVATE
    BAPI_CUBE_CHANGE
    BAPI_CUBE_CREATE
    BAPI_CUBE_GETDETAIL
    BAPI_CUBE_GETLIST
    BAPI_INFOCUBE_READ_REMOTE_DATA
    BAPI_MDPROVIDER_GET_CUBES
    BAPI_MDPROVIDER_GET_STREAMCUBE
    UMK_BW_BAPI_CUBE_GETDETAIL
    Reward points for useful Answers
    Regards
    Anji

  • HOW DO I GET ALL LEVEL 0 MEMBER AND ITS PARENT IN A REPORT SCRIPT

    I want to create a report script that generate a list of all level 0 members and its parent for a particular dimension. I created the following report script that generate a list of level 0 members.
    //ESS_LOCALE English_UnitedStates.Latin1@Binary
    //The purpose of this script is to list
    //the Lvl0 descendants of the Account dimension
    { DECIMAL 2
    WIDTH 31 0
    SUPBRACKET
    SUPCOMMA
    SUPHEADING
    NOINDENTGEN
    SUPFEED
    ROWREPEAT }
    <SUPSHARE
    <ROW (Account)
    Lev0,Account
    !

    Hi Kris,
    I want to produce a report like this for all level 0 member
    For example --> database name; parent member; child member
    if it is not possible, can I produce a report for members at various level but with the level idenntifier.
    For example --> Account
    Level 3 100
    Level 2 100-10
    Level 1 100-10-20
    Level 0 100-10-20-1
    Level 0 100-10-20-2
    actual report row --> Level 1 100-10; 100-10-20
    Level 0 100-10-20; 100-10-20-1
    Level 0 100-10-20; 100-10-20-2

  • Getting all the members (variables, methods AND method bodies) of a java source file

    For a project I want to programmatically get access to the members of java source file (member variables, methods etc) as well as to the source code of those members. My question is what is the best method for this? So far I have found the following methods:
    Use AST's provided by the Java Source API and Java Tree API, as discussed in the following posts:
    http://today.java.net/pub/a/today/2008/04/10/source-code-analysis-using-java-6-compiler-apis.html
    http://weblogs.java.net/blog/timboudreau/archive/2008/02/see_java_code_t.html
    http://netbeans.dzone.com/announcements/new-class-visualization-module
    This has the disadvantage that the classes actually have to be compilable. When I look at the Netbeans Navigator view however, it provides me with a nicely formatted UI list, regardless of the "compilable" state of the class.
    Thus I started looking at how to do this... The answer appears to be through the use of tools such as JavaCC: https://javacc.dev.java.net/
    ANTLR: http://www.antlr.org/
    which are lexers and parsers of source code. However, since the Navigator panel already does this, couldn't I use part of this code to get me the list of variables and methods in a source file? Does the Navigator API help in this regard?
    Another route seems to be through tools such as
    BeautyJ: http://beautyj.berlios.de/
    which run on top of JavaCC if I am correct, and which has the ability to provide a clean view on your java code (or an XML view). However, BeautyJ does not seem to be too actively developed, and is only j2se1.4 compatible.
    I hope someone can shed a light on the best way to go about what I want to achieve. Somebody already doing this?
    (I crossposted on the Netbeans forums too, hope this is OK...)

    I'm currently developing a LaTeX editor(MDI) and I do the same thing, but I don't know what exactly do you need.

  • Scene Graph traversal. Getting all the children of a node recursively

    Hi,
    Requirement: To resize all the controls of a scene (including controls that contain text like label, button) as per the scene size
    Approach: To implement the above requirement (see code snippet below), I added Listeners for width and height properties of a Scene and whenever the scene size changes, I get all the children of the root node of the scene and invoked the setScaleX() and setScaleY() for the children.
    Problem: In my design, labels and buttons are wrapped inside VBox, HBox etc. Method getChildrenUnmodifiable() returns only the first level of children and hence my HBox and VBox are getting scaled as per the scene size but not the children of VBox and HBox. Is there a built-in function to get all the children of a node recursively ? Or what is the best way to resize text as the scene size changes ?
    Scene mainScene = new Scene(borderPane, PERMANENT_WIDTH,
                    PERMANENT_HEIGHT, Color.HONEYDEW);
    rootNode = mainScene.getRoot();
            mainScene.widthProperty().addListener(new ChangeListener() {
                @Override
                public void changed(ObservableValue observable, Object oldValue,
                        Object newValue) {
                    Double widthScalingFactor = ((Double) newValue) / PERMANENT_WIDTH;
                     ObservableList<Node> children = rootNode.getChildrenUnmodifiable();
                    for (Node child : children) {
                        child.setScaleX(widthScalingFactor);
            mainScene.heightProperty().addListener(new ChangeListener() {
                @Override
                public void changed(ObservableValue observable, Object oldValue,
                        Object newValue) {
                    Double heightScalingFactor = ((Double) newValue) / PERMANENT_HEIGHT;
                    ObservableList<Node> children = rootNode.getChildrenUnmodifiable();
                    for (Node child : children) {
                        child.setScaleY(heightScalingFactor);
            });Thanks.

    Added the following code to get all the children recursively. now the scaling is applied to all nodes of a scene.
        private static void getChildren(Parent parentNode) {
            if (parentNode.getChildrenUnmodifiable().size() != 0) {
                ObservableList<Node> tempChildren = parentNode
                        .getChildrenUnmodifiable();
                allChildren.addAll(tempChildren);
                for (Node n : tempChildren)
                    getChildren((Parent) n);
            } else
                allChildren.add(parentNode);
        }

  • Display all levels in Cash Flow Report (FF7A)

    Hi all,
    I am new to FF7A and I would like to get all levels of my different grouping levels to appear on one screen. I can't figure how to do it.
    So far I can see BANKEN and PERSONEN and drilldown in each of them but can't get to see the details of both on one screen. This is required by my client as they want to export the cash flow report with all its details in Excel.
    Any idea?
    Regards,

    Hi ,
    Kindly check your configuration under grouping structure there whether while creating the grouping structure and mentioned grouping type at levle based and mentioned all the account ,then in the FF7A slect that particular groupingh structure then the report can be obtained at all level .

  • Making member in BM showing all possible members from all levels

    When i import essbase model with drag and drop option i get one additional member called, for example, Times - Default. It shows all available members from all levels of its dimension.
    How can i create similar member in relational model?

    I doubt that is possible with relational data because, unlike essbase structure, relational data do not allow you to store alias at design time.
    If you spell the business requirement here, we may be able to tell you any alternative.

  • BAPI  to get all properties of all levels of all hierarchies of a cube

    Hi Experts,
    Is there are way to get all properties of all levels of all hierarchies of all dimensions of a cube (InfoCube, ODSObject, QueryCube, InfoSet)  in one BAPI call?
    I use BAPI_MDPROVIDER_GET_PROPERTIES, and only set input parameters: CAT_NAM, CUBE_NAM. But it only returns all Level1's properties.
    Any useful answer will be awarded with suitable points.
    Thanks,
    Rohan

    Hi,
    Thanks for giving reply.
    Recommended Function module is not a RFC, so it is not working.
    Thanks,
    Rohan

  • Getting all types of files with the help of get_file_name function

    hi all,
    i am using Forms [32 Bit] Version 6.0.8.24.1 (Production).
    i have used get_file_name function to the file name of all type of files
    but i am able to get only the folders when i tried like below
    :FILE_NAME := GET_FILE_NAME(NULL,NULL,NULL,'Choose a Directory',OPEN_FILE,FALSE);my requirement to get all types of files on the window(user will selects whichever way he wants)
    Can i acheive it through get_file_name or i have to go for any alternative to get the file list, so that user can select by browsing the folders.
    Please help.
    Thanks..

    hi,
    in my code the select file was set to false(so showing only the directories) now i have set it to 'true'. its showing the files now.
    with the help of my above shown code i can get the full path of the file.
    is there any way to get only the file name?(other than the last occurance of '/' logic or that is only the way?)
    Please help.
    Thanks..

  • Function Module to get all feild names in a structure

    Hello Friends,
    Is there a function module,where i give the structure name and get all the feild names within that structure.
    regards
    kaushik

    Hi,
    You can use the for run time type descriptor classes to do this :
    Here is a simple example :
    REPORT  z_assign_comp.
    TYPE-POOLS : slis.
    include <icon>.
    "&   Dynamic Programming ! Using Structure Descriptior Class.          *
    DATA: BEGIN OF line OCCURS 0,
            col1 TYPE i,
            col2(10) TYPE c,
            col3 TYPE i,
          END OF line.
    FIELD-SYMBOLS : <fs> TYPE ANY.
    FIELD-SYMBOLS : <itab_line> TYPE ANY.
    DATA : BEGIN OF t_comp OCCURS 0,
            comp(5) TYPE c,
           END OF t_comp.
    DATA : l_struc TYPE REF TO cl_abap_structdescr.
    DATA : l_typedesc TYPE REF TO cl_abap_typedescr.
    DATA : lt_comp TYPE abap_compdescr_tab,
           w_comp LIKE LINE OF lt_comp.
    line-col1 = 11.line-col2 = 'SAP'.line-col3 = 33.
    APPEND line.
    line-col1 = 44.line-col2 = 'P.I.'.line-col3 = 66.
    APPEND line.
    ASSIGN line TO <itab_line>.
    "Call the static method of the structure descriptor describe_by_data
    CALL METHOD cl_abap_structdescr=>describe_by_data
      EXPORTING
        p_data      = <itab_line>
      RECEIVING
        p_descr_ref = l_typedesc.
    "The method returns a reference of  a type descriptor class therefore we
    "need to Cast the type descriptor to a more specific class i.e
    "Structure Descriptor.
    l_struc ?= l_typedesc.
    "Use the Attribute COMPONENTS of the structure Descriptor class to get
    "the field names of the structure
    lt_comp = l_struc->components.
    LOOP AT line.
      WRITE :/ 'Row : ', sy-tabix.
      LOOP AT lt_comp INTO w_comp.
    "   Using the ASSIGN component ,assigns a data object to a field symbol.
        ASSIGN COMPONENT w_comp-name OF STRUCTURE line TO <fs>.
        WRITE :/ w_comp-name, ' ', <fs>.
      ENDLOOP.
    ENDLOOP.
    Hope this helps.
    regards,
    Advait

Maybe you are looking for

  • Color grading render out of PS CS4 Problems

    Ive got some footage shot from my Canon T2i (1080p @ 30fps) that ive edited the levels in to adjust the color. When I go to export it in Apple Pro Res 422 it works fine, the only problem is the file is MASSIVE. Ive got a 9 second clip that renders ou

  • Problems with old(ish) EIDE drive in new Neo4 system

    I've been building my new system today, the only components I have retained are the optical and hard drives and the memory. System is as follows K8N Neo4 (non SLI edition) Athlon 64 3700+ PC3200 Crucial 1Gb (2x512Mb sticks in dual channel) BFG 7800GT

  • How to execute sql script from linux command line

    Hello everyone ! Just short question. On my server I must install script in crontab which will eexecute some sql statements. How can I write command which will execute script from file without asking about password ? sqlplus user/pass ... and then wh

  • Airport connection is strong but unable to load pages

    On my Macbook all of a sudden now it says it is connected but web pages won't load at all I have tried to restart and turn on and off the airport, and nothing. Tried with Safari Chrome and Firefox. Tks

  • Working with HDV footage in FCP3

    Hello folks, I have a HDV clip which is .mov file, 1080i60 HDV. I am trying to find the way to be able to import it into FCP3. If I leave it as it it, FCP is telling me that it is an unknown file. So I am wondering, how can I convert it into some fil