Get all the members having particular UDA's
Hi,Is there any way in Essbase Java API to get the members which are having any of the UDA's given in a list? For example, If I have three UDA's UDA1, UDA2, UDA3. Now I want to get the members in a cube which are having any of these UDA's attached to it. I knowIEssMemberSelection.executeQuery(mbrName, queryType, queryOptions, dimName, UDAName, input2) will give me the members which are having UDAName which attached as UDA. I am looking for a method which can return me all the members if I give the arguements as an array
No, there isn't a function that takes an array of UDAs and returns members that has one of the UDAs in the array. However, you can do the member selection multiple times, once for each UDA, and gather the info about the members that you need.Tim TowApplied OLAP, Inc.
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Powershell to get all the members in about 20 DynamicDistribution group in exchange 2010
I have about 20 DynamicDistribution groups in my exchange 2010 enviroment. I need to run a report to show all the members in each group. How can I accomplish this with powershell ? thanks for all the help
I assume you don't want the output of all 20 groups dumped into one single list. So, you'd just use this:
Use the Shell to preview the list of members of a dynamic distribution
group
This example returns the list of members for the dynamic distribution group Full Time Employees. The first command stores the dynamic distribution group object in the variable $FTE.
The second command uses the Get-Recipient cmdlet to list the recipients that match the criteria defined for the dynamic distribution group.
$FTE = Get-DynamicDistributionGroup "Full Time Employees"
Get-Recipient -RecipientPreviewFilter $FTE.RecipientFilter
For detailed syntax and parameter information, see Get-DynamicDistributionGroup and Get-Recipient.
Mike Crowley | MVP
My Blog --
Baseline Technologies -
Getting all the members (variables, methods AND method bodies) of a java source file
For a project I want to programmatically get access to the members of java source file (member variables, methods etc) as well as to the source code of those members. My question is what is the best method for this? So far I have found the following methods:
Use AST's provided by the Java Source API and Java Tree API, as discussed in the following posts:
http://today.java.net/pub/a/today/2008/04/10/source-code-analysis-using-java-6-compiler-apis.html
http://weblogs.java.net/blog/timboudreau/archive/2008/02/see_java_code_t.html
http://netbeans.dzone.com/announcements/new-class-visualization-module
This has the disadvantage that the classes actually have to be compilable. When I look at the Netbeans Navigator view however, it provides me with a nicely formatted UI list, regardless of the "compilable" state of the class.
Thus I started looking at how to do this... The answer appears to be through the use of tools such as JavaCC: https://javacc.dev.java.net/
ANTLR: http://www.antlr.org/
which are lexers and parsers of source code. However, since the Navigator panel already does this, couldn't I use part of this code to get me the list of variables and methods in a source file? Does the Navigator API help in this regard?
Another route seems to be through tools such as
BeautyJ: http://beautyj.berlios.de/
which run on top of JavaCC if I am correct, and which has the ability to provide a clean view on your java code (or an XML view). However, BeautyJ does not seem to be too actively developed, and is only j2se1.4 compatible.
I hope someone can shed a light on the best way to go about what I want to achieve. Somebody already doing this?
(I crossposted on the Netbeans forums too, hope this is OK...)I'm currently developing a LaTeX editor(MDI) and I do the same thing, but I don't know what exactly do you need.
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I'm having some trouble transferring audio books to my iPhone. It usually takes 3 or 4 tries to get all the parts transferred. I didn't use to have this problem - all parts would transfer in one try.
carolinechx wrote:
i know the description may be a little bit too confusing
Mostly because you are not using any capital letters or paragraph returns and your post is difficult to read. -
How to get all the approver list for a particular transaction in iExpense
Is there any API to get all the approver list for a particular transaction in iExpense workflow after submitting an expense report?
Hi All,
Could anyone please let me know API to get all AME approvers in one go.
I am currently using below API to get approver list.
ame_api.getallapprovers (applicationidin => 201 , -- PO
transactionidin => l_document_id , -- req header id
transactiontypein => 'PURCHASE_REQ'
,approversout => l_appr_list
But if any of the approver is INACTIVE then API is going into exception and not showing all approvers. Requirement is like to show all approvers with their statuses (ACTIVE / INACTIVE).
Reply ASAP. -
Query to get all the worksheets for a particular work book
Hi All,
I want to get all the associated worksheets for a particular workbook. What query will fetch mne those details. Also, where can find the EUL5 tables documentation
Regards
ThomasHi Tamir,
Thanks so far. I am yet to make the crucial breakthrough as far my application goes. Are you talking about the EUL5_QPP_STATS table? I tried retrieving worksheets even from that table also with the following query
SELECT DISTINCT Eul5QppStats.QS_DOC_NAME,Eul5QppStats.QS_DOC_DETAILS
FROM EUL5_QPP_STATS Eul5QppStats,EUL5_DOCUMENTS Eul5Documents
WHERE Eul5QppStats.QS_DOC_NAME = Eul5Documents.DOC_NAME
However, the worksheet data retrieved by Discoverer Oracle's product is not matching my dataset for every workbook. Please suggest.
Reg
Thomas -
Urgent solution needed for the Problem ( get all the combination from table
we are having a table in following format
day | grpID | pktID
sun | 1 | 001
sun | 1 | 002
sun | 1 | 003
sun | 2 | 007
sun | 2 | 008
sun | 2 | 009
mon | 1 | 001
mon | 1 | 002
mon | 1 | 003
mon | 2 | 007
mon | 2 | 008
mon | 2 | 009
tue | 1 | 001
tue | 1 | 002
tue | 1 | 003
tue | 2 | 007
tue | 2 | 010
1. We have a combination of pkdIDs related with a specific grpID, for a particular day.
Ex: For Sunday, we have two combination list for grpID=1 is (001,002,003) and for group id = 2 is (007,008,009)
2. We need to get all the available combined pktid for each group id for all the days .
Eg the the expected result that is needed from the above table
(001,002,003)
(007,008,009)
(007,010)SQL> with tbl as
2 (select 'sun' d, 1 grp, '001' pk from dual union all
3 select 'sun' d, 1 grp, '002' pk from dual union all
4 select 'sun' d, 1 grp, '003' pk from dual union all
5 select 'sun' d, 2 grp, '007' pk from dual union all
6 select 'sun' d, 2 grp, '008' pk from dual union all
7 select 'sun' d, 2 grp, '009' pk from dual union all
8 select 'mon' d, 1 grp, '001' pk from dual union all
9 select 'mon' d, 1 grp, '002' pk from dual union all
10 select 'mon' d, 1 grp, '003' pk from dual union all
11 select 'mon' d, 2 grp, '007' pk from dual union all
12 select 'mon' d, 2 grp, '008' pk from dual union all
13 select 'mon' d, 2 grp, '009' pk from dual union all
14 select 'tue' d, 1 grp, '001' pk from dual union all
15 select 'tue' d, 1 grp, '002' pk from dual union all
16 select 'tue' d, 1 grp, '003' pk from dual union all
17 select 'tue' d, 2 grp, '007' pk from dual union all
18 select 'tue' d, 2 grp, '010' pk from dual) -- end of data sample
19 select distinct '('||ltrim(max(c1) keep (dense_rank last order by lv),',')||')'
20 from (select d,grp,level lv,sys_connect_by_path(pk,',') c1
21 from tbl
22 connect by d=prior d and grp = prior grp and pk > prior pk)
23 group by d,grp;
'('||LTRIM(MAX(C1)KEEP(DENSE_RANKLASTORDERBYLV),',')||')'
(001,002,003)
(007,008,009)
(007,010)
SQL>That works on 9i. Other possiblities on 10g.
Nicolas. -
How to get all the values from the dropdown menu
How to get all the values from the dropdown menu
I need to be able to extract all values from the dropdown menu; I know how to get all those values as a string, but I need to be able to access each item; (the value in a dropdown menu will change dynamically)
How do I get number of item is selection dropdown?
How do I extract a ?name? for each value, one by one?
How do I change a selection by referring to particular index of the item in a dropdown menu?
Here is the Path to dropdown menu that I'm trying to access (form contains number of similar dropdowns)
RSWApp.om.GetElementByPath "window(index=0).form(id=""aspnetForm"" | action=""advancedsearch.aspx"" | index=0).formelement[SELECT](name=""ctl00$MainContent$hardwareBrand"" | id=""ctl00_MainContent_hardwareBrand"" | index=16)", element
Message was edited by: testtestThe findElement method allows various attributes to be used to search. Take the following two examples for the element below:
<Select Name=ProdType ID=testProd>
</Select>
I can find the element based on its name or any other attribute, I just need to specify what I am looking for. To find it by name I would do the following:
Set x = RSWApp.om.FindElement("ProdType","SELECT","Name")
If I want to search by id I could do the following:
Set x = RSWApp.om.FindElement("testProd","SELECT","ID")
Usually you will use whatever is available. Since the select element has no name or ID on the Empirix home page, I used the onChange attribute. You can use any attribute as long as you specify which one you are using (last argument in these examples)
You can use the FindElement to grab links, text boxes, etc.
The next example grabs from a link on a page
Home
Set x = RSWApp.om.FindElement("Home","A","innerText")
I hope this helps clear it up. -
When creating a book in iphoto, how can I get all the photos from the album I want to use to show up in the order that they are in the album? When I tried to use the option to add my own photos instead of having the program "flow" them, they showed up all mixed up.
iPhoto puts them in the book in chronological order. So to get your photos from an album into an iPhoto book in the same order you will need to use the Photos ➙ Batch Change ➙ Date menu option and set them all to the same date with a 1 minute time difference between each.
OT -
Before this new version of Thunderbird, when I typed in the first letter of an e-mail address, it would display all the e-mail address starting with that letter and I could pick the address which I wanted. Now, when I type in the first letter of an e-mail address I get all the e-mail addresses in my address book in no particular order and I wind up with all the e-mail addresses in my 'write' command. If you pick the one you want to send, you invariably wind up with addresses you don't want in your 'to' box. Is there some way I can get back to the old system which was a lot easier and less frustrating than the new version that just seems to defy common sense and reasoning and is very inconvenient as it takes forever to get the e-mail address right that you want to send your message to?
You probably need to go back to TB24.6
https://ftp.mozilla.org/pub/mozilla.org/thunderbird/releases/24.6.0/
Choose your platform and then your language, click the offered file to download it, then run it.
You want win32/ for any version of Windows. -
How do I get all the songs from an album to show in the album view? Currently, if an album lists the artist plus a guest artist, those are shown separately and appear to be two different albums on my iPod. How do I get all the songs on that album together on my iPod? If the album is a collaboration wtih many artists, each sond may appear as a separate album.
I used to have this problem.
First, you need to go back on iTunes
you need to go to each of the songs that are having this problem
Click the album so all the songs drop down
Right click the songs that have this problem
Click ' Get info '
Click the tab that says " info '
The box that says ' album artist ' should probably be empty (correct me if I'm wrong)
Click it and type the artist of the entire album, NOT the songs guest artist
as such,
ARTIST
JAY-Z Feat. Justin Timberlake
ALBUM ARTIST
JAY-Z
These should be separate for each artist
If you write the same album artists for each song by that artist, all the songs should be on 1 album -
Need to get all the files, (well music and video), from my ipod touch 5th gen to my itunes libary. (So basically sync the other way to normal)
Laptop hard drive broke so had to buy a new one and obviously now need to sort out my itunes.
Did try downloading all my purchased stuff onto itunes but it has missed some things off, and there are some files I did not purchase from itunes so need a way of getting them back on there.
Sure this question has been asked a million times but can't find anything to help me on here so thought I'd ask.
-Did have a look at going onto the start menu and opening the hidden items thing but couldn't see any reference to ipod or device on it so wasn't sure how to do it that way.
-On itunes under my device when its connected, the section about manually restoring and backing up, would that help me? Because that says it will manually back up my ipod to my computer then could restore that back up, obviously I don't want to accidnetally get rid of everything on my ipod so didn't want to try that just in case without checking.
(And yes I have disabled auto sync to device when conncected!)
Can anyone help me please? Sorry if i've overcomplicated this!
Thanks:)
ChrisBacking up an iOS device will copy some data to a backup file within iTunes, but this excludes all media. You can also transfer iTunes Store purchases from the iDevice to iTunes but, without using a third-party tool, nothing else. As long as you do not sync the iPod with your new library, the media that's on it will remain ... for as long as it keeps functioning, is not lost, stolen, eaten by the dog, ...
You may also have an option to recover your previous library from your old laptop; as long as its hard drive isn't fried, a computer repair store or technician may be able to extract the drive, mount it in an external enclosure, and copy your data to another PC. Whatever you choose, there is no real alternative to having all your media on your computer, managed by iTunes, and regularly backed up to another device/location. -
Get all the tabs in internet options in IE
hi,
i am using IE 10 in my windows server 2012. while i try to edit the settings of Internet Options by clicking the Gear Symbol of IE, am seeing that none of the tabs except "General" is avaialble.
can anyone pls tell how to enable the otehr tabs? i am having admin rights on my machine.would like to know what are thise settings i need to make in order to get all the settings in my internet options .
Tabs namely Security,Privacy, Content , connections, programs, advanced are missing from my id.
DasHi Shankardas,
Here is my result:
This is configured by the Group Policy:
Computer Configuration---administrative Templates---Windows Components---Internet Explorer---Internet Control Panel
Please remember to mark the replies as answers if they help, and unmark the answers if they provide no help. If you have feedback for TechNet Support, contact [email protected] -
I am having problems with my itunes. I have purchase an album from itunes but it has been seperated so i have 3 songs from the album on 1 album the 3 songs on another and the 1 song on another. How do i get all the songs on 1 album like it should normally do?
Try these Discussions...
https://discussions.apple.com/message/10990796#10990796
https://discussions.apple.com/message/21989767#21989767 -
How do i get all the songs from 1 album to appear as 1 album instead of 3 albums because 2 of the songs feature guest artists in my itunes library?
Generally all you need to do is fill in an appropriate Album Artist. For more details see my article on Grouping Tracks Into Albums, in particular the topic One album, too many covers.
tt2
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