Generate the random numbers

How Do I Generate Random Numbers in iWorks
Excel has the "F9" key to generate random numbers numbers don't
please see below what i'm trying to do
I open up a blank Excel worksheet, and type the number "1" into cell A1. Type the number "2" into cell A2. Then type the number "3" into cell A3. Type the number "4" into cell A4, and then type the number "5" into cell A5.
2
Type the word "PB" into cell A6.
3
Enter the function "=RANDBETWEEN(1,59)" into cell B1.
4
Enter an exact copy of this function "=RANDBETWEEN(1,59)" into cells B2, B3, B4, and B5.
5
Enter the function "=RANDBETWEEN(1,39)" into cell B6.
6
Hit the "F9" key to generate the random numbers simulating game.
But in numbers how do i do this?
Thanks!
Alex...

firstly your not asking about generating random numbers, your asking how do you make a workbook recalculate new random numbers. From M$'s website:
F9
Calculates all worksheets in all open workbooks
It does not produce random numbers the equations should produce random numbers as soon as you enter them in. If they dont then you have automatic reclaculations turned off and F9 is forcing a recalc.
In numbers there is not shortcut to forcing the workbook to recalculate other than enter data into a cell. So if you made a new table and then enter data. For every data point you enter you should see new data apear.
Was just validating the method for forcing and its not working on my ipad. I will mark this conversation and if i find it i will respond again.
Jason
Message was edited by: jaxjason

Similar Messages

Generate multiple random numbers?

Hi,
I'm trying to generate random numbers using Math.random()* n;
but I want the random numbers to reset to something different after
a particular event is called. Instead, I've noticed the numbers
either buzz away randomly in every frame (when placed inside
onEnterFrame), or it picks random numbers once, and then uses those
same values over and over (when placed outside the onEnterFrame).
How do i get actionscript to generate new random numbers
after each myMC.onPress = function(), or alternatively, after a
score changes (like some kind of watch feature?)

ok, i've got a half working version;
function ranbot(x) {
return Math.ceil(Math.random()* x) + "/" +
Math.ceil(Math.random()* x);
trace(ranbot(60));
but is it possible to set up the function so the numerator is
equal to or less than the denominator? Also, if the numerator is
set to never exceed the denominator, then a large percentage -
something like 25-50% of the output fractions would equal "1", like
55/55, 23/23, 7/7, 28/28, and so on.
I did something like this when using variables;
var randombot2:Number = Math.ceil(Math.random()* 99);
var randomtop2:Number = Math.min(randombot2 -
Math.floor(Math.random()* randombot2* 0.5),
Math.ceil(Math.random()* 99));
- but I do not understand how this works in function
terminology.

How can you generate Multiple random numbers from 1 to 49?

I am very new at programming with the iPhone SDK and I need some help with a project I am working on. What I want to do is set up a window with 6 labels and 1 button. When the user clicks the button, the program will populate 6 randomized numbers each ranging from 1 to 49, and then place each of 6 numbers in a label. But each time the program ends and starts again the numbers cannot be the same, and also when the user clicks the button, no label can have the same number twice, so for example. If label 1 had the number 10, the other 5 labels cannot have that number until the button is clicked again. I know how to set up the interface, I just need the code. I would so greatly appreciate someone's help in this matter. I have been trying to do this for days and I cannot figure it out. Possibly someone who knows tons about Objective C programming can help me!
Thank-you so very much!!

I see that you're writing a lottery number generator. Perhaps the easiest way to do it is to emulate a real lottery: fill an array (NSMutableArray, probably) with the numbers between 1 and 49, pick one at random, remove that number from the array, and repeat. (You can think of the numbers as being the balls and the array as being the machine that pops them out.)
One simple way to get the random indices needed is to extract six random bytes from Randomization Services using SecRandomCopyBytes, then loop over them, using the modulo operator (%) to select an index within the size of the array.
And no, I'm not going to write your code for you. If I was going to do that, I could package and sell the app myself.

How to generate unique random numbers

Hi All,
I am wondering whether there is already a random library or built-in function available in Java to produce some random numbers between certain ranges that are not repetitive. Let's look at a common examples as follows:
Random diceRoller = new Random();
for (int i = 0; i < 10; i++) {
int roll = diceRoller.nextInt(6) + 1;
System.out.println(roll);
}My understanding from this approach is that it allows the same number to be repeated over and over again. However, I would like to find out how to continue generating random numbers from remaining ones that haven't been generated earlier.
Using the above example to illustrate my intention:
1st random number generated - possibility of 1 - 6 showed up. Say 5 is picked.
2nd random number generated - possibility of 1, 2, 3, 4, 6 only. Say 2 is picked.
3rd random number generated - possibility of 1, 3, 4, 6 available. Say 1 is picked.
4th random number generated - possibility of 3, 4, 6 left. Say 6 is picked.
5th random number generated - possibility of 3, 4 remains. Say 4 is picked.
Any assistance would be much appreciated.
Many thanks,
Jack

htran_888 wrote:
Hi All,
I am wondering whether there is already a random library or built-in function available in Java to produce some random numbers between certain ranges that are not repetitive. Let's look at a common examples as follows:
Random diceRoller = new Random();
for (int i = 0; i < 10; i++) {
int roll = diceRoller.nextInt(6) + 1;
System.out.println(roll);
}My understanding from this approach is that it allows the same number to be repeated over and over again. However, I would like to find out how to continue generating random numbers from remaining ones that haven't been generated earlier.
Using the above example to illustrate my intention:
1st random number generated - possibility of 1 - 6 showed up. Say 5 is picked.
2nd random number generated - possibility of 1, 2, 3, 4, 6 only. Say 2 is picked.
3rd random number generated - possibility of 1, 3, 4, 6 available. Say 1 is picked.
4th random number generated - possibility of 3, 4, 6 left. Say 6 is picked.
5th random number generated - possibility of 3, 4 remains. Say 4 is picked.
Any assistance would be much appreciated.If it is your school assignment then you have the answer above (List & the lists length).
(You might want to look at Collections)

How do you generate multiple random numbers between 1 and 49

I am new at mac programming and I want to make an iPhone app with the free SDK. What I would like to try is a random number generator. I imagine it as when the user clicks a button 6 random numbers from 1 to 49 would appear in a label or another control. If someone could please give me the code that would place these randomized numbers in a label I would greatly appreciate it. I know how to link all the controls together, I just need the code. Thank-you to anyone that can help!

semi-sudo code goes here
--prepare and array which will have number from 0 to 49
--loop thru the array like this
int i=0
for (i; i<=49; i++) {
int a=arc4random() % 49] ;
int b=arc4random() % 49];
--here exchange the objects so that they are shuffled
[myArray exchangeObjectAtIndex:a withObjectAtIndex:b];

Generating negative random numbers

Hi,
I'm trying to generate random float numbers between -1 and +1. But the nextFloat() method of the Random class supposedly only generates floats between 0.0f and 1.0f.
How do I generate floats between 0.0f and -1.0f?
Please help?
Thanks.

Right... I just figured out that if you want a random number in the range (m,n) you use
x=(n-m)*(getNextFloat())+m
so in the range(-1,1) you have (1-(-1))*getNextFloat()+(-1)
=2*getNextFloat()-1

_dynSessConf - How to tweak logic to generate the random number.

Hi,
Can someone please let me know how we can tweak the logic when the random session confirmation number is generated and added as _dynSessConf.
We have a requirement where this random number needs to be a bit longer than the currently generated default value.
Regards,
Saurav

The session confirmation number used for _dynSessConf is already a randomly generated cryptographic number of long type which is hard to guess. Anyways, if you want to further modify it here is one of the approach that I can suggest.
You can probably start with the component /atg/dynamo/servlet/sessiontracking/SessionIdGenerator in the component browser. In its details you will find it has a uniqueIdGenerator property which points to /atg/dynamo/servlet/sessiontracking/UniqueIdGenerator. Following on further it would eventually lead you to the components /atg/dynamo/service/random/SecureRandom and /atg/dynamo/service/random/SecureRandomConfiguration. Look at the service configurations of these components and see if you can get something which you can change or customize to meet your requirements.

Help in generating the same random numbers each time of the program executi

dear friends
i am facing a problem that the random numbers generated at time of each exectuion of the program are not the same, i want to generate the same random numbers every time time i run the program. i need your help. i am giving the code in c++ if anybody can help in providing the solution so that i get the same random numbers at every run of the program. waiting for your help
wit regards
jaya shankar
#include<iostream.h>
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#include<math.h>
class density
int s[150][150],parent[150][150],i,j,l,n,loop;
public:
void bd(void);
void css(void);
void density :: bd(void)
cout<<"ENTER THE POPULATION SIZE = ";
cin>>n;
cout<<"\nENTER THE NO.OF LOOPS = ";
cin>>loop;
for(i=0;i<n;i++)
for(j=0;j<80;j++)
s[i][j]=rand()%2;
cout<<"s:"<<s[i][j];
void density :: css(void)
int a,b;
float c;
for(i=0;i<n;i=i+2)
b=rand()%100;
cout<<"random b="<<b;
main()
density d;
d.bd();
d.css();

To generate the same random,it's impossible!
why do you want to do that?

Help in generating the same random numbers at every time of executuion

dear friends
i am facing a problem that the random numbers generated at time of each exectuion of the program are not the same, i want to generate the same random numbers every time time i run the program. i need your help. i am giving the code in c++ if anybody can help in providing the solution so that i get the same random numbers at every run of the program. waiting for your help
wit regards
jaya shankar
#include<iostream.h>
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#include<math.h>
class density
int s[150][150],parent[150][150],i,j,l,n,loop;
public:
void bd(void);
void css(void);
void density :: bd(void)
cout<<"ENTER THE POPULATION SIZE = ";
cin>>n;
cout<<"\nENTER THE NO.OF LOOPS = ";
cin>>loop;
for(i=0;i<n;i++)
for(j=0;j<80;j++)
s[j]=rand()%2;
cout<<"s:"<<s[j];
void density :: css(void)
int a,b;
float c;
for(i=0;i<n;i=i+2)
b=rand()%100;
cout<<"random b="<<b;
main()
density d;
d.bd();
d.css();

You have to read the documentation for the java.util.Random class.
"If two instances of Random are created with the same seed, and the same sequence of method calls is made for each, they will generate and return identical sequences of numbers. In order to guarantee this property, particular algorithms are specified for the class Random"
Here is a peace of code that will do wat you need:
Random rand = new Random(100);
for(int i=0; i<10; i++)
System.out.println("Random="+ rand.nextInt(10));

How t generate random numbers at everytime of exceutuion of the program

dear friends
i am facing a problem that the random numbers generated at time of each exectuion of the program are not the same, i want to generate the same random numbers every time time i run the program. i need your help. i am giving the code in c++ if anybody can help in providing the solution so that i get the same random numbers at every run of the program. waiting for your help
wit regards
jaya shankar
#include<iostream.h>
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#include<math.h>
class density
int s[150][150],parent[150][150],i,j,l,n,loop;
public:
void bd(void);
void css(void);
void density :: bd(void)
cout<<"ENTER THE POPULATION SIZE = ";
cin>>n;
cout<<"\nENTER THE NO.OF LOOPS = ";
cin>>loop;
for(i=0;i<n;i++)
for(j=0;j<80;j++)
s[j]=rand()%2;
cout<<"s:"<<s[j];
void density :: css(void)
int a,b;
float c;
for(i=0;i<n;i=i+2)
b=rand()%100;
cout<<"random b="<<b;
main()
density d;
d.bd();
d.css();

This will help you I think.
import java.io.*;
import java.util.*;
public class RandomTest
     public static void main( String arg[]) throws Exception
          Random number = new Random(100);
          for( int i = 0 ; i < 15; i++){
               System.out.println( number.nextInt( 100 )) ;

How to generate random numbers of the same at each time of execution of thm

dear friends
i am facing a problem that the random numbers generated at time of each exectuion of the program are not the same, i want to generate the same random numbers every time time i run the program. i need your help. i am giving the code in c++ if anybody can help in providing the solution so that i get the same random numbers at every run of the program. waiting for your help
wit regards
jaya shankar
#include<iostream.h>
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#include<math.h>
class density
int s[150][150],parent[150][150],i,j,l,n,loop;
public:
void bd(void);
void css(void);
void density :: bd(void)
cout<<"ENTER THE POPULATION SIZE = ";
cin>>n;
cout<<"\nENTER THE NO.OF LOOPS = ";
cin>>loop;
for(i=0;i<n;i++)
for(j=0;j<80;j++)
s[j]=rand()%2;
cout<<"s:"<<s[j];
void density :: css(void)
int a,b;
float c;
for(i=0;i<n;i=i+2)
b=rand()%100;
cout<<"random b="<<b;
main()
density d;
d.bd();
d.css();

Do not randomize the random number interface when you start your application. When the random number interface is not randomized when starting you get the same sequence of numbers each and every time you use it.

How can I generate multiple unique random numbers?

Hello,
I am trying to generate multiple random numbers between a given set of numbers (1-52) and not have the same number generated twice within that set. I can compare the last and next numbers with the compare function but how would I go about comparing all of the generated numbers without using a huge list of shift registers...
Any help/ideas are welcome and appreciated.
Jason
Solved!
Go to Solution.

Here is an implementation of Jason's solution.
steve
Help the forum when you get help. Click the "Solution?" icon on the reply that answers your
question. Give "Kudos" to replies that help.
Attachments:
random.vi ‏10 KB

How do I generate an array of random numbers that relate to an output wave that falls within a certain frequency range?

I have been creating random numbers that I'm using within a system, the system is working fine, but now I have realised that the random numbers must be outputted to speakers in such a way as to filter out all but a low frequency range.
I was thinking about generating a dither signal with a bandpass filter, but could not get it to give me out a full array of 250 values which I could then manipulate.
The sampling frequency of the output is 200Hz and the 250 data points must fall within the 0-100Hz range.
Another course of action I am considering is to use an FFT and an inverse FFT to get the data that I'm looking for, but I'm fair
ly inexperienced with using labVIEW and can't quite get it to work.
Thanks for the help,
Hank.

As you may already know, in the Functions palette/Analysis VIs/Filters VIs are VIs for filtering. There are also some examples for using these filters under Examples/Analysis/fltrxmpl. You may find some of these are related to your situation, especially for filtering out the higher values.
An option is to simply output the random values to a Comparison/"less than or equal" function, where only values <= to 100 would be sent to an array which is in a For loop. Use the iteration counter of the For loop to count up to 250, at which time you would pass the whole array to your next node. This would let you have 250 values between 0 and 100 for your final array.
Good luck.

Figuring out the occurence of random numbers?

So, I'm taking this Computer Science class, and I've been struggling so much with today's lesson.
For this particular question, I have to get 20 random numbers between 1-5, represent them in text format, and the show how often each of the numbers occured. I've done the first two of the three parts, but this last part really has me stumped..
(Note: I'm using Ready to Program by Holt.... so I'm using their console)
Here's the code I got so far:
import java.util.*;
import hsa.Console;
import java.io.*;
public class RandomNumbers
    static Console c;
    static public void main (String[] args) throws IOException
        c = new Console ();
        int a;
        Random generator = new Random();
        c.println("Generating Numbers: ");
        for(a=1;a<=20;a++)
            int r = generator.nextInt(5)+1;
                switch(r)
                     case 1: c.print("One",10); break;
                     case 2: c.print("Two",10); break;
                     case 3: c.print("Three",10); break;
                     case 4: c.print("Four",10); break;
                     case 5: c.print("Five",10); break;
}}

I had a similar assignment my last semester for C++. I would think the general idea is the same.
Here I declare an Array. Then I store the values of the dice rolled in the array and display it on the screen. The syntax will be different since you are not using C++.
#include <iostream>          // preprocessor directive
#include <ctime>          // preprocessor directive
#include <cmath>          // preprocessor directive
#include <cstdlib>          // preprocessor directive
using namespace std;     // enables preprocessor directives
int random_int(int a, int b);          // function prototpye
int main ()     // main function
     srand(time(NULL));          // enables random numbers to be generated
     int d1, d2, sum;                         // declaring variables
     int a[10] = {0,0,0,0,0,0,0,0,0,0};     // initializes valus in array to 0
     int roll;                                   // declaring variable
     cout << "Roll how many times?";          // ask number of times to roll dice
     cin >> roll;                              // get number of times to roll dice
     for(int i=0; i<=roll; i++)               // to roll the dice the numbers or times asked
          d1 = random_int(1,6);               // generates number for die 1
          d2 = random_int(1,6);               // generates number for die 2
          sum = d1 + d2;                         // adds the two dice together
          if(sum == 2)                         // increase value in array by 1 that corresponds to 2
               a[0]++;
          else if(sum==3)                         // increase value in array by 1 that corresponds to 3
               a[1]++;
          else if(sum==4)                         // increase value in array by 1 that corresponds to 4
               a[2]++;
          else if(sum==5)                         // increase value in array by 1 that corresponds to 5
               a[3]++;
          else if(sum==6)                         // increase value in array by 1 that corresponds to 6
               a[4]++;
          else if(sum==7)                         // increase value in array by 1 that corresponds to 7
               a[5]++;
          else if(sum==8)                         // increase value in array by 1 that corresponds to 8
               a[6]++;
          else if(sum==9)                         // increase value in array by 1 that corresponds to 9
               a[7]++;
          else if(sum==10)                    // increase value in array by 1 that corresponds to 10
               a[8]++;
          else if(sum==11)                    // increase value in array by 1 that corresponds to 11
               a[9]++;
          else if(sum==12)                    // increase value in array by 1 that corresponds to 12
               a[10]++;
     for(int j = 2; j<=12; j++)
          cout << j << " " << a[j-2] <<endl;          // output the array
     return 0; //exit program
int random_int(int a, int b)          // used to generate te random numbers
     int random = rand()%(b-a+1) + a;
     return (random);
}

Random numbers in a table

I'm new to java, so please bear with me. What I want to do is create a program which chooses random numbers (between 0-9) in a table, and then presents a diagram of how many of each number comes up.
e.g. if the table size was 10, the output could be something like:
0 *
1 **
2
3 *
9 **
with the stars representing the number of times the number showed up. Any assistance you could provide would be great and appreciated. Thank you

1) Create a Map. The key will be one of the random numbers, the value will be a counter of the number of times the number has been stored.
2) Generate a random number.
3) Place the random number in the map key, and increment the value.
4)Print the random numbers and as many asterisks as the counter values.
I believe this is classwork? Asking about problems in the code that are not working is ok - asking people to write sample code for you is not ok. Part of the assignment requires you to read the documentation and figure out how to write the code.

Generate the random numbers

Similar Messages

Maybe you are looking for