Generating Nested XML Documents

Hi,
We want to generate nested XML documents from sql queries using pl/sql.
If the output of the query is
EMPNO NAME MGRNO
1 Super Admin 0
2 Mgr1 1
4 SubMgr1_1 2
5 SubMgr2_1 2
3 Mgr2 1
6 SubMgr1_2 3
then XML generated should be in the format
Super Admin
Mgr1
SubMgr1_1
SubMgr2_1
Mgr2
SubMgr1_2
Your early response is appreciated.
Thanks.

No, the id is not unique, it is part of the data. Also, I don't need to update the XML document.
I store the data part (id, status, nodenum) in the "resp" table with a primary key as a combination of id and some other info. The table "nodes" will have a foreign key and multiple occurrences of node. Same with table "restricts" with multiple restrict.
Do I need to create a DOM tree then store each part of the XML into appropriate tables? And how do I do that? (which APIs, etc.)
Thanks,
Thuvan

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    L.LOCATION_NAME_EN AS "Community",
    "PROJECTS"."PROJECT_NAME_EN" as "Property_Name",
    "RES_SALE"."ASKING_PRICE" as "Price",
    ' ' as "Frequency",
    ST."SUB_TYPE" as "Unit_Model",
    R."RES_SIZE" as "Unit_Builtup_Area",
    R.BEDS as "Bedrooms",
    R.bath as "No_of_Bathrooms",
    "RES_SALE"."AD_TITLE" as "Property_Title",
    RES_SALE.DESCRIPTION as "Web_Remarks",
    to_char("RES_SALE"."UPDATED_ON",'YYYY-MM-DD HH:MI:SSPM') as "Last_Updated",
    R.VIDEO as "Web_Tour",
    select xmlagg(
                                 xmlforest(
                                'http://thevillaproject.com/apex/erp/IMAGES/'||IMG.ID AS "ImageUrl"
    FROM      
          IMAGES IMG     
    WHERE IMG.RES_ID = R.RES_ID ) Images )))).getclobval()
      into      v_xml
      FROM
          "RES_SALE" "RES_SALE"
    inner join
          RES R on (R."RES_ID"="RES_SALE"."RES_ID")
    inner join
              "UNIT_STATUS_LOOKUP" on (UNIT_STATUS_LOOKUP.status_id = "RES_SALE"."RES_STATUS")
    inner join
          "PROJECTS" "PROJECTS" on ("PROJECTS"."PROJECT_ID"=R."PROJECT_ID")
    inner join
          "UNIT_TYPE_LOOKUP" "UNIT_TYPE_LOOKUP" on ("UNIT_TYPE_LOOKUP"."TYPE_ID"=R."RES_TYPE")
    inner join
          "RES_SUB_TYPE_LOOKUP" ST on (ST."SUB_TYPE_ID"=R."SUB_TYPE")
    INNER JOIN
          COMPLEX_LOOKUP CL ON (CL.COMPLEX_ID = "PROJECTS".COMPLEX_ID)
    INNER JOIN
          LOCATIONS L ON (L.LOCATION_ID = CL.LOCATION_ID)
    WHERE  "RES_SALE".RES_status IN (5,8) AND "RES_SALE".LIVE = 'Y' AND "RES_SALE".DESCRIPTION IS NOT NULL
      dbms_lob.append(v_retval,v_xml);
      OWA_UTIL.Mime_Header('text/xml'); 
      htp.p('Content-length: ' || to_char(dbms_lob.getlength(v_retval)));
      htp.p('Content-Disposition:  inline; filename="Just.xml"');
      owa_util.http_header_close;
      v_blob := wwv_flow_utilities.clob_to_blob(v_retval);
      wpg_docload.download_file(v_blob);
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    select
           xmlelement(
             "LISTINGS",
             xmlagg(
               xmlelement(
                 "LISTING",
                 xmlforest(
    'RR-'||R."RES_ID" as "Property_Ref_No",
    "UNIT_TYPE_LOOKUP"."UNIT_TYPE" as "Unit_Type",
    'Rent' as "Ad_Type",
    'Dubai' as "State",
    L.LOCATION_NAME_EN AS "Community",
    "PROJECTS"."PROJECT_NAME_EN" as "Property_Name",
    "RES_RENT"."ASKING_PRICE" as "Price",
    ' ' as "Frequency",
    ST."SUB_TYPE" as "Unit_Model",
    R."RES_SIZE" as "Unit_Builtup_Area",
    R.BEDS as "Bedrooms",
    R.bath as "No_of_Bathrooms",
    "RES_RENT"."AD_TITLE" as "Property_Title",
    "RES_RENT".DESCRIPTION as "Web_Remarks",
    to_char("RES_RENT"."UPDATED_ON",'YYYY-MM-DD HH:MI:SSPM') as "Last_Updated",
    R.VIDEO as "Web_Tour",
    select xmlagg(
                                 xmlforest(
                                'http://thevillaproject.com/apex/erp/IMAGES/'||IMG.ID AS "ImageUrl"
    FROM      
          IMAGES IMG     
    WHERE IMG.RES_ID = R.RES_ID ) Images ))))
    FROM
          "RES_RENT" "RES_RENT"
    inner join
          RES R on (R."RES_ID"="RES_RENT"."RES_ID")
    inner join
              "UNIT_STATUS_LOOKUP" on (UNIT_STATUS_LOOKUP.status_id = "RES_RENT"."RES_STATUS")
    inner join
          "PROJECTS" "PROJECTS" on ("PROJECTS"."PROJECT_ID"=R."PROJECT_ID")
    inner join
          "UNIT_TYPE_LOOKUP" "UNIT_TYPE_LOOKUP" on ("UNIT_TYPE_LOOKUP"."TYPE_ID"=R."RES_TYPE")
    inner join
          "RES_SUB_TYPE_LOOKUP" ST on (ST."SUB_TYPE_ID"=R."SUB_TYPE")
    INNER JOIN
          COMPLEX_LOOKUP CL ON (CL.COMPLEX_ID = "PROJECTS".COMPLEX_ID)
    INNER JOIN
          LOCATIONS L ON (L.LOCATION_ID = CL.LOCATION_ID)
    WHERE  "RES_RENT".RES_status IN (5,8) AND "RES_RENT".LIVE = 'Y' AND "RES_RENT".DESCRIPTION IS NOT NULL

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    Dear list,
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    Are the xml documents stored in a XMLType column?
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    http://www.oracle.com/technology/sample_code/tech/java/codesnippet/xmldb/transformxml/TransformXML.html
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  • SQL query to generate Nested XML

    Hello,
    I use Oracle 11g R2 SOE....
    I have two main tables
    COMMERCIALS_PROPERTIES (com_id number PK , com_size number, project_id number, com_type number)
    COM_PHOTOS (ID number PK , com_id number FK, content blob, mimetype varchar2)
    Please, note the following has nothing to do with my problem:
    CONTENT and MIMETYPE columns. Also, the lookup tables: PROJECTS , COM_TYPE
    In APEX ( Application Express ) we can expose a report as RESTful web service in XML format:
    I am using this query to generate the XML 1 feed, but I need to tweak the query to generate XML 2 feed.
    Is it possible, how to do it ???
    Select
    "COM"."COM_ID" as "COM_ID",
    "COM"."COM_SIZE" as "SIZE",
    "PROJECTS"."PROJECT_NAME_EN" as "PROJECT",
    "COM_TYPES"."COM_TYPE" as "COM_TYPE",
    'http://fam-erp.com/apex/erp/fateh/'||IMG.ID as "ImgURL"
    FROM
    COM_PHOTOS IMG inner join COMMERCIALS_PROPERTIES "COM"
    on   IMG.COM_ID = COM.COM_ID
    inner join "PROJECTS" "PROJECTS"
    on "PROJECTS"."PROJECT_ID"="COM"."PROJECT_ID"
    inner join "COM_TYPE_LOOKUP" "COM_TYPES"
    on "COM_TYPES"."TYPE_ID"="COM"."COM_TYPE"
    WHERE
      COM.COM_ID < 80 order by 1h1. XML 1
    h2. Please look only at <COM_ID> and <ImgURL>
    <ROWSET>
    <ROW>
    <COM_ID>77</COM_ID>
    <SIZE>842</SIZE>
    <PROJECT>Bayswater Tower</PROJECT>
    <COM_TYPE>Office</COM_TYPE>
    <ImgURL>http://fam-erp.com/apex/erp/fateh/1410</ImgURL>
    </ROW>
    <ROW>
    <COM_ID>77</COM_ID>
    <SIZE>842</SIZE>
    <PROJECT>Bayswater Tower</PROJECT>
    <COM_TYPE>Office</COM_TYPE>
    <ImgURL>http://fam-erp.com/apex/erp/fateh/1412</ImgURL>
    </ROW>
    <ROW>
    <COM_ID>78</COM_ID>
    <SIZE>756</SIZE>
    <PROJECT>Bayswater Tower</PROJECT>
    <COM_TYPE>Office</COM_TYPE>
    <ImgURL>http://fam-erp.com/apex/erp/fateh/1425</ImgURL>
    </ROW>
    <ROW>
    <COM_ID>78</COM_ID>
    <SIZE>756</SIZE>
    <PROJECT>Bayswater Tower</PROJECT>
    <COM_TYPE>Office</COM_TYPE>
    <ImgURL>http://fam-erp.com/apex/erp/fateh/1429</ImgURL>
    </ROW>
    </ROWSET>---------------------------
    h1. XML 2
    h2. Please look only at <COM_ID> and <Images> and <ImgURL>
    <ROWSET>
    <ROW>
    <COM_ID>77</COM_ID>
    <SIZE>842</SIZE>
    <PROJECT>Bayswater Tower</PROJECT>
    <COM_TYPE>Office</COM_TYPE>
    <Images>
          <ImgURL>http://fam-erp.com/apex/erp/fateh/1410</ImgURL>
          <ImgURL>http://fam-erp.com/apex/erp/fateh/1412</ImgURL>
    </Images>
    </ROW>
    <ROW>
    <COM_ID>78</COM_ID>
    <SIZE>756</SIZE>
    <PROJECT>Bayswater Tower</PROJECT>
    <COM_TYPE>Office</COM_TYPE>
    <Images>
            <ImgURL>http://fam-erp.com/apex/erp/fateh/1425</ImgURL>
            <ImgURL>http://fam-erp.com/apex/erp/fateh/1429</ImgURL>
    </Images>
    </ROW>
    </ROWSET>

    Hi, Fateh
    One possible way is to use XML functions to create your XML.
    Using XML functions you can do the IMAGES as an XMLAGG subquery rather than join to the image table.
    Here's an example using SCOTT schema:
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      2            "ROWSET"
      3          , xmlagg(
      4               xmlelement(
      5                  "ROW"
      6                , xmlforest(
      7                     d.deptno as "ID"
      8                   , d.dname as "NAME"
      9                   , (
    10                        select xmlagg(
    11                                  xmlelement(
    12                                     "ImgUrl"
    13                                   , 'http://the.server.com/'||e.empno
    14                                  )
    15                                  order by e.empno
    16                               )
    17                          from scott.emp e
    18                         where e.deptno = d.deptno
    19                     ) as "Images"
    20                  )
    21               )
    22               order by d.deptno
    23            )
    24         ) the_xml
    25    from scott.dept d
    26    /* joins to the other tables EXCEPT image table */
    27  /
    THE_XML
    <ROWSET><ROW><ID>10</ID><NAME>ACCOUNTING</NAME><Images><ImgUrl>http://the.serverThat output is an XMLTYPE column (think of it as a CLOB with added functionality ;-) )
    My SQL*PLUS cuts the output, but believe me, it is all there.
    Just to show it, here's the same example wrapped in an XMLSERIALIZE function to pretty-print the XML:
    SQL> select xmlserialize(
      2            content
      3            xmlelement(
      4               "ROWSET"
      5             , xmlagg(
      6                  xmlelement(
      7                     "ROW"
      8                   , xmlforest(
      9                        d.deptno as "ID"
    10                      , d.dname as "NAME"
    11                      , (
    12                           select xmlagg(
    13                                     xmlelement(
    14                                        "ImgUrl"
    15                                      , 'http://the.server.com/'||e.empno
    16                                     )
    17                                     order by e.empno
    18                                  )
    19                             from scott.emp e
    20                            where e.deptno = d.deptno
    21                        ) as "Images"
    22                     )
    23                  )
    24                  order by d.deptno
    25               )
    26            )
    27            as varchar2(4000)
    28            indent size=2
    29         ) the_xml
    30    from scott.dept d
    31    /* joins to the other tables EXCEPT image table */
    32  /
    THE_XML
    <ROWSET>
      <ROW>
        <ID>10</ID>
        <NAME>ACCOUNTING</NAME>
        <Images>
          <ImgUrl>http://the.server.com/7782</ImgUrl>
          <ImgUrl>http://the.server.com/7839</ImgUrl>
          <ImgUrl>http://the.server.com/7934</ImgUrl>
        </Images>
      </ROW>
      <ROW>
        <ID>20</ID>
        <NAME>RESEARCH</NAME>
        <Images>
          <ImgUrl>http://the.server.com/7369</ImgUrl>
          <ImgUrl>http://the.server.com/7566</ImgUrl>
          <ImgUrl>http://the.server.com/7788</ImgUrl>
          <ImgUrl>http://the.server.com/7876</ImgUrl>
          <ImgUrl>http://the.server.com/7902</ImgUrl>
        </Images>
      </ROW>
      <ROW>
        <ID>30</ID>
        <NAME>SALES</NAME>
        <Images>
          <ImgUrl>http://the.server.com/7499</ImgUrl>
          <ImgUrl>http://the.server.com/7521</ImgUrl>
          <ImgUrl>http://the.server.com/7654</ImgUrl>
          <ImgUrl>http://the.server.com/7698</ImgUrl>
          <ImgUrl>http://the.server.com/7844</ImgUrl>
          <ImgUrl>http://the.server.com/7900</ImgUrl>
        </Images>
      </ROW>
      <ROW>
        <ID>40</ID>
        <NAME>OPERATIONS</NAME>
      </ROW>
    </ROWSET>For a webservice you do not need to pretty-print the XML that is returned by the webservice.
    I do not know APEX, so I do not know if APEX supports exposing an allready built piece of XML rather than exposing a query result.
    But my guess is that it should do it very nicely if you query an XMLTYPE datatype (that is - use the first of my examples rather than the pretty-printed one.)
    If you can't get APEX to do it this way, then I suggest you try asking in the APEX forum rather than the SQL forum ;-)

  • Generate nested xml

    I have following tables :
    DEPT
    DEPT_ID    DEPT_NAME      GRP_NAME
    1          Engineering    Research and Development
    2          Tool Design    Research and Development
    EMP
    EMP_ID      FIRST_NAME    MIDDLE_NAME    LAST_NAME     DEPT_ID    HIRE_DATE      
    1           Roberto       Luc            Tamburello    1          1997-12-12     
    2           Rob           (null)         Walters       2          1998-01-05     
    3           Thierry       (null)         D'Hers        2          1998-01-11     
    4           Janice        B.             Galvin        2          2001-01-23     
    EMP_TEL
    EMP_ID    TEL_ID
    1         1
    1         5
    2         2
    3         3
    4         4
    TEL
    TEL_ID    AREA_CODE    PHONE_NO    EXT     TEL_TYPE_ID    
    1         111          1111111     111     1
    2         222          2222222     222     1
    3         333          3333333     333     1
    4         444          4444444     444     1
    5         555          5555555     (null)  2
    TEL_TYPE
    TEL_TYPE_ID    TEL_TYPE_CD
    1              OFFICE
    2              FAX
    3              CELLIs there a way to generate below xml in one sql statement?
    <Company>
      <Department>
        <DepartmentName>Engineering</DepartmentName>
        <GroupName>Research and Development</GroupName>
        <Employee>
          <FirstName>Roberto</FirstName>
          <MiddleName>Luc</MiddleName>
          <LastName>Tamburello</LastName>
          <HireDate>1997-12-12</HireDate>
          <Telephone>
            <TelephoneType>OFFICE</TelephoneType>
            <TelephoneNumber>111-111-1111</TelephoneNumber>
            <Extension>111</Extension>
          </Telephone>
          <Telephone>
            <TelephoneType>FAX</TelephoneType>
            <TelephoneNumber>555-555-5555</TelephoneNumber>
          </Telephone>
        </Employee>
      </Department>
      <Department>
        <DepartmentName>Tool Design</DepartmentName>
        <GroupName>Research and Development</GroupName>
        <Employee>
          <FirstName>Rob</FirstName>
          <LastName>Walters</LastName>
          <HireDate>1998-01-05</HireDate>
          <Telephone>
            <TelephoneType>OFFICE</TelephoneType>
            <TelephoneNumber>222-222-2222</TelephoneNumber>
            <Extension>222</Extension>
          </Telephone>
        </Employee>
        <Employee>
          <FirstName>Thierry</FirstName>
          <LastName>D'Hers</LastName>
          <HireDate>1998-01-11</HireDate>
          <Telephone>
            <TelephoneType>OFFICE</TelephoneType>
            <TelephoneNumber>333-333-3333</TelephoneNumber>
            <Extension>333</Extension>
          </Telephone>
        </Employee>
        <Employee>
          <FirstName>Janice</FirstName>
          <MiddleName>B.</MiddleName>
          <LastName>Galvin</LastName>
          <HireDate>2001-01-23</HireDate>
          <Telephone>
            <TelephoneType>OFFICE</TelephoneType>
            <TelephoneNumber>444-444-4444</TelephoneNumber>
            <Extension>444</Extension>
          </Telephone>
        </Employee>
      </Department>
    </Company>

    Is there a way to generate below xml in one sql statement?yes, this way:
    SQL> select xmlelement("Company",
      2               xmlagg(
      3                  xmlelement("Department",
      4                             xmlforest(dept_name as "DepartmentName",
      5                                       grp_name as "GroupName"
      6                                       ),
      7                             (select xmlagg(
      8                                         xmlelement("Employee",
      9                                                    xmlforest(FIRST_NAME as "FirstName",
    10                                                              MIDDLE_NAME as "MiddleName",
    11                                                              LAST_NAME as "LastName",
    12                                                              to_char(HIRE_DATE,'yyyy-mm-dd') as "HireDate"
    13                                                              ),
    14                                                    (Select xmlagg(
    15                                                              xmlelement("Telephone",
    16                                                                         xmlforest(TEL_TYPE_CD as "TelephoneType",
    17                                                                                   AREA_CODE||'-'||PHONE_NO as "TelephoneNumber",
    18                                                                                   EXT as "Extension"
    19                                                                                   )
    20                                                                         )
    21                                                                   )
    22                                                        from TEL t, TEL_TYPE tt, EMP_TEL et
    23                                                       where t.TEL_TYPE_ID=tt.TEL_TYPE_ID
    24                                                         and et.EMP_ID = e.EMP_ID
    25                                                         and et.TEL_ID = t.TEL_ID
    26                                                    )
    27                                                   )
    28                                              )
    29                                from emp e
    30                               where e.DEPT_ID=d.DEPT_ID
    31                              )
    32                             )
    33                      )
    34                    ).extract('/*') doc
    35    from DEPT d;
    DOC
    <Company>
      <Department>
        <DepartmentName>Engineering</DepartmentName>
        <GroupName>Research and Development</GroupName>
        <Employee>
          <FirstName>Roberto</FirstName>
          <MiddleName>Luc</MiddleName>
          <LastName>Tamburello</LastName>
          <HireDate>1997-12-12</HireDate>
          <Telephone>
            <TelephoneType>OFFICE</TelephoneType>
            <TelephoneNumber>111-1111111</TelephoneNumber>
            <Extension>111</Extension>
          </Telephone>
          <Telephone>
            <TelephoneType>FAX</TelephoneType>
            <TelephoneNumber>555-5555555</TelephoneNumber>
          </Telephone>
        </Employee>
      </Department>
      <Department>
        <DepartmentName>Tool Design</DepartmentName>
        <GroupName>Research and Development</GroupName>
        <Employee>
          <FirstName>Rob</FirstName>
          <LastName>Walters</LastName>
          <HireDate>1998-01-05</HireDate>
          <Telephone>
            <TelephoneType>OFFICE</TelephoneType>
            <TelephoneNumber>222-2222222</TelephoneNumber>
            <Extension>222</Extension>
          </Telephone>
        </Employee>
        <Employee>
          <FirstName>Thierry</FirstName>
          <LastName>D&apos;Hers</LastName>
          <HireDate>1998-01-11</HireDate>
          <Telephone>
            <TelephoneType>OFFICE</TelephoneType>
            <TelephoneNumber>333-3333333</TelephoneNumber>
            <Extension>333</Extension>
          </Telephone>
        </Employee>
        <Employee>
          <FirstName>Janice</FirstName>
          <MiddleName>B.</MiddleName>
          <LastName>Galvin</LastName>
          <HireDate>2001-01-23</HireDate>
          <Telephone>
            <TelephoneType>OFFICE</TelephoneType>
            <TelephoneNumber>444-4444444</TelephoneNumber>
            <Extension>444</Extension>
          </Telephone>
        </Employee>
      </Department>
    </Company>Max
    [My Italian Oracle blog|http://oracleitalia.wordpress.com/2010/01/17/supporto-di-xml-schema-in-oracle-xmldb/]

  • Generate nested XML using OracleXMLQuery generates error

    Hello,
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    PrintWriter out = response.getWriter();
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    I have exactly the same problem by using XSU.
    If somebody solve it already ?
    David, can you please provide more information or small example, how can I extract OracleConnection or Oracle Specific Driver inside the Weblogic App. Server and not generic weblogic.jdbc.rmi.SerialConnection instance.
    I'm using Oracle thinDriver on Oracle8i.
    Thank you in advance.
    <BLOCKQUOTE><font size="1" face="Verdana, Arial">quote:</font><HR>Originally posted by David G:
    have seen similar problems with wrapped jdbc driver being passed into Weblogic pool service and then cast back into OracleDriver after getting it back from Weblogic's JNDI DataSource lookup ...the Oracle extensions do not seem to survive Weblogic's jdbc pool services handling. I have gone over to running all my connection pools in Oracle's own namespace jdbc_access:// for JNDI lookups on DataSource pools instead. Much happier. <HR></BLOCKQUOTE>
    null

  • New to XML, need to generate XML document

    I have an existing application that uses an Oracle 9.2.0.3 database. An existing PL/SQL procedure generates a flat file interface using UTL_FILE. My task is to upgrade this procedure to generate an XML file and transform this XML file into different outputs (e.g. flat file interface, PDF file which I plan to use XSL Formatting Objects). My question is how should I generate the XML document from the PL/SQL procedure? Should I use the Oracle 9i SQL/XML capabilities? specifically xmlelement, etc? An if so should I also use UTL_FILE to generate the XML file? Your help will be appreciated.

    Williams,
    Do you want to generate an XML file from the data present in relational tables using PL/SQL ?
    In that case you can use XML SQL Utility(XSU).
    For more information on XSU click [url http://otn.oracle.com/docs/products/oracle9i/doc_library/release2/appdev.920/a96621/adx23xsp.htm#1008317]here.
    Regards,
    Anupama
    [url http://otn.oracle.com/sample_code/]OTN Sample Code

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