Get average number of duplicate records per user?

I am currently going through the activity log tables in the database to try and find out how many users make use of the application's batch processing functionality. As part of that, I'm trying to write a query to find out
the average number of activities each user has performed with each request, where a given request can have 1 (non-batch processing) or more (batch processing) records with an identical user ID and timestamp. Here's a simplified depiction of
the table in question:
LogEntryNumber
UserID
ActivityTime
1
1
2014-04-17 11:04:45.527
2
1
2014-04-17 11:04:45.527
3
1
2014-04-17 11:04:45.527
4
2
2014-04-30 07:52:39.243
5
2
2014-05-05 08:52:11.543
6
1
2014-05-13 08:41:09.173
7
3
2014-06-12 13:50:19.033
And here's the results I'd like to see:
UserID
AverageNumberOfActivitiesPerRequest
1
2
2
1
3
1
What would be the SQL query for getting these results?

One way
SELECT X.UserID
, AVG(X.C) AS AverageNumberOfActivitiesPerRequest
FROM (
SELECT UserID
, ActivityTime
, COUNT(*) AS C
FROM YourTable
GROUP BY UserID
, ActivityTime
) X
GROUP BY X.UserID
Edit: Actually that is doing an average on an integer so might not give you the results you expect - you can cast the COUNT(*) to NUMERIC/DECIMAL for better accuracy

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