Get Child XML

Hey everyone,
I needed some help with a issue I've been having. So I'm trying to create persistent inbox data and I'm saving it as XML. Everything is completely abstracted to hell and saved in a single xml file. Each inbox has a factory of which can take XML to create an inbox. So obviously I have set up my XML file in the following manner:
<inboxes>
<inbox factory-id="GMail"><data1 />asfasf<data2 /><data3 /><data4 /></inbox>
<inbox factory-id="Yahoo"><data1 />asfasfasd<data2 /><data3 /><data4 /></inbox>
</inboxes>So the way this works is that the factory id tells me which factory i need to send the child data to. The issue is I cant figure out how to get the xml string of a child using the SAX or DOM Parsers. Once I get to the startElement method I can easily figure out the factory-id but I cannot get all the child data (which could be mixed content as shown). within the inbox tag. Anyone have a good solution to this problem? Am I just being dumb? I would like to stick with Java implementations of these parsers or implement it on my own which really is looking to be a good solution.

You can't get that using any parsers. That's because the job of a parser is to convert an XML document to some internal format. With the SAX parser that internal format is a stream of SAX events, and with the DOM parser it's a tree of nodes.
If you want an XML document, you have to take an internal format and serialize it. Some XML products have explicit serializers, but with others you have to do an identity transformation to produce a document.
So what I would recommend is to parse your file into a DOM. Then identify the subtree you want the XML for, and serialize that subtree.

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How to get child elements of element in xml?

public class Test {
     public static void main(String[] args) {
          Document doc = null;
          System.out.println("!!!");
          try {
               // TODO if path is 'c:' then make it 'c:/'
               doc=DocumentBuilderFactory.newInstance().newDocumentBuilder().parse("test.xml");
          } catch (Exception e) {
               System.out.println("exception");
          Element root = doc.getDocumentElement();
          NodeList dsList = root.getElementsByTagName("GenericDataSource");
          Element e = (Element)dsList.item(0);
         NodeList nl = e.getChildNodes();
         System.out.println(nl.getLength());
         Node n = nl.item(0);
         Element ee = (Element)n;
}i want to get child elements. but its throwing exception on typecasting. can u tell me why?

thanks for the info.
i got 2 solutions
SOLUTION 1:
public class Test {
     public static void main(String[] args) throws Exception {
          Document doc = null;
          System.out.println("!!!");
          try {
               // TODO if path is 'c:' then make it 'c:/'
               doc=DocumentBuilderFactory.newInstance().newDocumentBuilder().parse("test.xml");
          } catch (Exception e) {
               System.out.println("exception");
          Element root = doc.getDocumentElement();
          NodeList dsList = root.getElementsByTagName("GenericDataSource");
          Element e = (Element)dsList.item(0);
         NodeList nl = e.getChildNodes();
         int count = 0;
         System.out.println(nl.getLength());
         for(int i=0;i<nl.getLength();i++){
                  Node n = nl.item(i);
                 //System.out.println(n.getClass().getName());
                 //System.out.println((Element)n);
                 if(n instanceof Element){ // this checks for node type
                      count++;
                      System.out.println("Element "+(Element)n);
SOLUTION 2: :
XPath xpath = XPathFactory.newInstance().newXPath();
         InputSource inputSource = new InputSource("test.xml");
         NodeList nodes = (NodeList) xpath.evaluate("//GenericDataSource/*", inputSource, XPathConstants.NODESET);
         System.out.println(nodes.getLength());
         System.out.println((Element)nodes.item(9));

OLAP API to get child nodes ?

Hi, I am new to OLAP API (Java), I spend some months in Hyperrion Essbase JAPI, now turn to Oracle but feel quite confused about a lot of concept. Here is a task in my hand that is to present the dimension tree in XML format, just like:
<?xml version="1.0" encoding="GBK"?>
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          <Member name="East" gen="2">
               <Member name="New_York" gen="3" />
               <Member name="Boston" gen="3" />
               <Member name="Chicago" gen="3" />
          </Member>
          <Member name="West" gen="2">
               <Member name="San_Francisco" gen="3" />
               <Member name="Seattle" gen="3" />
               <Member name="Denver" gen="3" />
               <Member name="Los_Angeles" gen="3" />
          </Member>
          <Member name="South" gen="2">
               <Member name="Dallas" gen="3" />
               <Member name="Houston" gen="3" />
               <Member name="Phoenix" gen="3" />
          </Member>
     </Member>
     <Member name="Product" gen="1">
          <Member name="Audio" gen="2">
               <Member name="Stereo" gen="3" />
I didn't find ways on how to get child nodes for a given node, for example, how can I get East,West,South,North nodes (called "member" in Essbase) from "Market" node?

Hi, I am new to OLAP API (Java), I spend some months in Hyperrion Essbase JAPI, now turn to Oracle but feel quite confused about a lot of concept. Here is a task in my hand that is to present the dimension tree in XML format, just like:
<?xml version="1.0" encoding="GBK"?>
     <Member name="Market" gen="1">
          <Member name="East" gen="2">
               <Member name="New_York" gen="3" />
               <Member name="Boston" gen="3" />
               <Member name="Chicago" gen="3" />
          </Member>
          <Member name="West" gen="2">
               <Member name="San_Francisco" gen="3" />
               <Member name="Seattle" gen="3" />
               <Member name="Denver" gen="3" />
               <Member name="Los_Angeles" gen="3" />
          </Member>
          <Member name="South" gen="2">
               <Member name="Dallas" gen="3" />
               <Member name="Houston" gen="3" />
               <Member name="Phoenix" gen="3" />
          </Member>
     </Member>
     <Member name="Product" gen="1">
          <Member name="Audio" gen="2">
               <Member name="Stereo" gen="3" />
I didn't find ways on how to get child nodes for a given node, for example, how can I get East,West,South,North nodes (called "member" in Essbase) from "Market" node?

How can I get the XML structure from a flat structure?

Hi all,
in my XI SP 12 I use a JMS adapter to read information using the WebSphereMQ transport protocol.
The structure that I receive have this format:
<Name_A.KeyFieldValue><Name_A.fieldName_A1_Value>...<Name_A.fieldName_AN_Value>
<NumberRecordType_B><NumberRecordType_c>
<Name_B.KeyFieldValue><Name_B.fieldName_B1_Value>...<Name_B.fieldName_BN_Value>
<Name_B.KeyFieldValue><Name_B.fieldName_B1_Value>...<Name_B.fieldName_BN_Value>
<Name_C.KeyFieldValue><Name_C.fieldName_C1_Value>...<Name_C.fieldName_CN_Value>
<Name_C.KeyFieldValue><Name_C.fieldName_C1_Value>...<Name_C.fieldName_CN_Value>
the problem is that in this structure each line is not separated by a carriage return or a comma, I have all the information in a single line:
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and the customer don't want to insert a line separator.
Then, the question is:
How can I get the XML structure from this structure?
If possible, I don't want to develop new Module and add it in the JMS Module Sequence.
PS I have already read the article "How to Use the Content Conversion Module with the XI 3 J2EE JMS Adapter.pdf" and it doesn't seem to help me.
Best Regards,
Paolo

To get context parameters from your web.xml file you can simply get the ActionServlet object from an implementing action object class. In the perform (or execute) method make the following call.
ServletContext context = getServlet().getServletContext();
String tempContextVar =
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How do you query the Hotmail Calendar with a freebusy URL to get an XML response ?

Hello,
I've posted this on the Exchange Server Legacy thread, but they point me back here....
Assuming that Outlook's (Hotmail's) Calendar service still supports XML FreeBusy requests, what am I doing wrong here ?
I'm sending this GET request to obtain an XML return that I can then further process:
GET / HTTP/1.1
owa/public/?cmd=freebusy&start=2014-12-04T14: 00:00+01:00&end=2014-12-08T16:00:00+01:00&interval=30&u=SMTP:*** Email address is removed for privacy ***
Translate: t User-Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.2; .NET CLR 1.1.4322)
Content-Type: text/xml
Host:
www.calendar.live.com
(Translate: t comes from http://www.infinitec.de/post/2004/12/31/Retrieving-a-users-availability-(freebusy-data).aspx)
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What is the correct syntax for this ?

Hi,
From your description, I would like to clarify the following things:
1. If you use an Exchange account, you can use an OWA command to retrieve Free/busy information for a particular user.
2. In your case, you use an Hotmail account. Actually, we have a dedicated support team regarding the Microsoft Outlook.com . I recommend you ask your question on our Microsoft Outlook.com forum which is staffed by more experts specializing in this kind
of problems. Your understanding will be appreciated.
For your convenience:
http://answers.microsoft.com/en-us/outlook_com/forum/ocalendar?tab=Threads
Hope this can be helpful to you.
Best regards,
If you have feedback for TechNet Subscriber Support, contact
[email protected]
Amy Wang
TechNet Community Support

What is the simplest way to get a xml-file from 10g R2 -database ?

Hi,
I'm new in xml, there are so many tools to work with xml:
what is the simplest way to get a xml-file from 10g R2 -database ?
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thank you
Norbert

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How to get an XML string from a Java Bean without wrting to a file first ?

I know we can save a Java Bean to an XML file with XMLEncoder and then read it back with XMLDecoder.
But how can I get an XML string of a Java Bean without writing to a file first ?
For instance :
My_Class A_Class = new My_Class("a",1,2,"Z", ...);
String XML_String_Of_The_Class = an XML representation of A_Class ?
Of course I can save it to a file with XMLEncoder, and read it in using XMLDecoder, then delete the file, I wonder if it is possible to skip all that and get the XML string directly ?
Frank

I think so too, but I am trying to send the object to a servlet as shown below, since I don't know how to send an object to a servlet, I can only turn it into a string and reconstruct it back to an object on the server side after receiving it :
import java.io.*;
import java.net.*;
import java.util.*;
class Servlet_Message        // Send a message to an HTTP servlet. The protocol is a GET or POST request with a URLEncoded string holding the arguments sent as name=value pairs.
public static int GET=0;
public static int POST=1;
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// the URL of the servlet to send messages to
public Servlet_Message(URL servlet) { this.servlet=servlet; }
public String sendMessage(Properties args) throws IOException { return sendMessage(args,POST); }
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// @exception IOException if error sending request
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public String sendMessage(Properties args,int method) throws IOException
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//        try { sb.append(sep+URLEncoder.encode(name,"UTF-16")+"="+URLEncoder.encode(args.getProperty(name),"UTF-16")); }
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Frank

Issue using Get-Child-Item

Have a function that will scan (grep) files in a folder with a certain extension. For some reason, Get-Child-Item always returns empty / 0 files on my folder even though you can look at the folder and see files of the specified extension (*.config).
Suspect either I am doing something wrong or permissions are somehow getting in the way. How do you properly use Get-ChildItem
in this context?
function scan-Files
param(
[parameter(mandatory=$True)]
[string]$folder,
[parameter(mandatory=$True)]
[string]$filePattern,
[parameter(mandatory=$False)]
[bool]$recurse = $False
Write-Host "Folder = $folder"
Write-Host "FilePattern = $filePattern"
$files = Get-ChildItem -Include $filePattern -Path $folder
#always empty for some reason
if ($files)
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}...#Invoke our function$folder = "C:\Program Files\Microsoft SQL Server\MSRS12.MSSQLSERVER\Reporting Services\ReportServer\"
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scan-Files -folder $folder -filePattern $filePattern

The Gods of the computer demand it. Without it you are only enumerating a folder item. With it you are enumerating the contents of the folder. Include only works on files that have been selected.
Example:
dir 'C:\Program Files\Microsoft SQL Server\MSRS12.MSSQLSERVER\Reporting Services\ReportServer\*.txt' -include *.config
dir 'C:\Program Files\Microsoft SQL Server\MSRS12.MSSQLSERVER\Reporting Services\ReportServer\*.c*' -include *.config
dir 'C:\Program Files\Microsoft SQL Server\MSRS12.MSSQLSERVER\Reporting Services\ReportServer' -filter *.config
Try all to see how they work.
\_(ツ)_/

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This blog explains:
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ora:buildscript="${oracle.jdeveloper.deploy.dir}/ojdeploy-build.xml"
ora:statuslog="${oracle.jdeveloper.deploy.dir}/ojdeploy-statuslog.xml">
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value="${oracle.jdeveloper.workspace.path}"/>
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I need to get an xml, which shape by webServiceProxy for send to webService, because i need to secure it.Please try again.
P.S Sorry for my bad EnglishThanks but that's the problem. You haven't expressed your problem clearly. So it can't be answered, whether in this thread or any other.
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Is it possible to get entire XML body in UDF?

Hi to all!
Is it possible to get entire XML body in UDF in XI ?

Hi,
Check out this thread for some idea..
Re: How to dump the complete MainDocument to a CLOB field?
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Regards
Aashish Sinha
PS : reward points if helpful

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public Document mywebservice(Document input){
Document d;
return d;
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Where to get to xml to alter photo gallery?

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Or thoughts on this tutorial helping?
http://kiyuco.com/tutorials/build-a-custom-gallery-using-the-photo-gallery-module

The first thing to change is the module paramaters...
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rowLength - Set the number of photos displayed per row
targetFrame - Set the destination frame where the photos will open (such as _blank)
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How to get an XML string store in CLOB or LONG column ?

How to get an XML string store in CLOB or LONG column ?
We use XSU with the following command
String str = qry.getXMLString();
but all the "<" are replace by "<"
It's impossible to parse the result for XSLT transformation
Thank's for your help
Denis Calvayrac
Example :
in the column "TT_NAME"
"<name><firstname>aaa</<firstname><lastname>bbb</lastname></name>
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</TT_NAME>
but, I have this result
<TT_NAME>
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Can you post some of your code, so I can take a look ?
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How to get the XML Payload of called process from calling process?

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Attached is the Flowrate_Test.seq and the PumpTest.seq which should be there in the folder path "C:\Documents and Settings\All Users\Documents\National Instruments\TestStand 4.2.1\Examples\PropertyLoader\LoadingLimits\LimitsFromExcelFile\UsingCVI".
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Attachments:
PumpTest.seq ‏6 KB
FlowRate_test.seq ‏11 KB

Get Child XML

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