Get last letter of a string....

Hi guys.
Have a problem with ABAP in SAP.
I need to get the last character of the string, like this...
'AAAAAAAA BBBB 1 QQQQQQQQ 2'.
i need to take the last letter (2) to do more things b4.
I'm thinking to rotate the string and take the first letter, but i think will exist a FM that do my requirement.
See you.
Thanks: Miguel

Hi,
First get the string lengthof the variable.
data: lv_string type char4 value 'ABCD',
      lv_new type i,
      lv_new1 type char2.
*lv_new = strlen(lv_string).
CALL FUNCTION 'STRING_LENGTH'
EXPORTING
    string        = lv_string
IMPORTING
   LENGTH        = lv_new
lv_new = lv_new - 2.
lv_new1 = lv_string+lv_new(2).
write lv_new1.
You get the last two characters.
reward if useful..
regards,
nazeer
Message was edited by:
        nazeer shaik

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Formula for getting first letter of the string

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CA Forum: Formula
Hi, I have a problem to get the first letter of the string. I need to compare first letter first and then change the rest of string to number as unit cost for calculation. For example, I have string K100, C200,... if first letter = K then 0 else if first letter = C then tonumber200..... I use CRXI, any assistance will be appreciate.jmmj

Post Author: jmmj
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It works, thanks Kai!But when I tried to print the report, there are multiple lines shown same invoice number but different unit price. My formular is: IF {OEINPR3.COINTYPE} = 2 OR CCur({OEINPR3.LINETYPE}) = 1 //line type 1 for item, 2 for misc. charge THEN( IF {OEINPR3.COIN}[1] = "K" OR {OEINPR3.COIN}[1] = "N" THEN TONUMBER(MID({OEINPR3.COIN},2,20)) ELSE 0)ELSE 2 //for testing only The result I have: Line# Inv# unitprice total1 IN001 0.00 10.00 IN001 10.00 10.00 2 IN002 0.00 20.00 IN002 20.00 20.00.......The second line of each invoice is correct. How can I print just one line for each invoice which is correct? Thanks!jmmj

Check last letter in a string

Good Day All,
I have a string field that does not a Consistence length.
I want to check the last of this field and concatenate some text depending on the result.
I've tried this but does not work.
if mid({usp_wb_Reporting_AssetsUnderManagement_A2a_Main;1.account_long_name,1 Len{usp_wb_Reporting_AssetsUnderManagement_A2a_Main;1.account_long_name}-1) = "M"
then {usp_wb_Reporting_AssetsUnderManagement_A2a_Main;1.account_long_name} & " Managed"
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Basically I'm check the length and if return an M it's Managed everything else is Unmanaged.
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if you want to check last letter then try this
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Hi,
I am working on FM in which i have to put highfen mark which is working ok,but the problem if there is when the value of string finds a space it should not insert highfen in it and i am not able to put the condition in it as it showing the higfen even when the word is full in the first line.i want to show highfen where the word is not able to display complete. here is d code which i am using right now. plzz provide me guidlines to solve this problem.
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FUNCTION Z_STRING_LENGTH1.
*"*"Local Interface:
*" IMPORTING
*"     VALUE(I_STRING) TYPE STRING
*"     VALUE(LENGTH) TYPE I
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      DIFF1 TYPE C,
      STRING1 type string, "Stores the 1st String
      STRING2 type string, "Stores the 2nd String
      STRING3 type string, "Stores the 3rd String
      STRING4 type string, "Stores the 3rd String
      STRING5 type string, "Stores the 3rd String
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STRING_F = I_STRING.
STRING_LENGTH = STRLEN( I_STRING ).
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IF DIFF LE 0.
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ENDIF.
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e_string = STRING5.
ELSE.
concatenate STRING1 STRING2 into STRING5.
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ENDIF.
ENDFUNCTION.
Edited by: ricx .s on May 12, 2009 5:20 AM

Hi,
I checked your code... its working fine except for some cases it is giving dumps for which I have added certain if conditions....
Please check the modified code below... have optimized it as well by removing one extra if condition....
you can copy and paste the code below...
DATA: STRING_F TYPE STRING, "Stores the value in string format
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      DIFF TYPE I,          "Difference among the value
      DIFF1 TYPE C,
      STRING1 TYPE STRING, "Stores the 1st String
      STRING2 TYPE STRING, "Stores the 2nd String
      STRING3 TYPE STRING, "Stores the 3rd String
      STRING4 TYPE STRING, "Stores the 3rd String
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STRING_F = I_STRING.
STRING_LENGTH = STRLEN( I_STRING ).
DIFF = STRING_LENGTH - LENGTH.
IF DIFF LE 0.
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STRING3 = STRING1+LENGTH2(1).
IF STRING2 IS NOT INITIAL.
STRING4 = STRING2+0(1).
ENDIF.
" put this if condition as there is a dump occuring at this place.
" Dump occurs when you give the length value greater than or equal to
" the string length
" Say for example the value of I_STRING, I passed it as SIDDARTH
" and the length I passed as 8, then it gives me a dump
IF LENGTH LE STRING_LENGTH AND STRING3 NE SPACE AND STRING4 NE SPACE.
CONCATENATE STRING1 '-' STRING2 INTO STRING5.
E_STRING = STRING5.
ELSE.
CONCATENATE STRING1 STRING2 INTO STRING5.
E_STRING = STRING5.
ENDIF.

Got last letter in String

HI all ,
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Hi ,
Where you want to write code ?
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Finding last char in the string

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i need to find out whether the last char of a string is '/' (forward slash). please let me know if there's a FM to do that. Other post me the logic for this ASAP.
thanks

len = strlen(char).
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*write ur code
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chk this code
REPORT ychatest.
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<b>Reward points if helpful and close thrad if solved</b>
Message was edited by: Chandrasekhar Jagarlamudi

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Hi,
try this-
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Read last char of a String

I have the following code that functions like a basic RPN calculator:
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enter
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