Get Parent node from Base member

Hi ,
My user select base member from CV .
I want parent node for that base member .
I am using =EVPRO( App name , memmber id , "PARENTH1" ) .
I am not getting parent member from this funcation .
Pls let me know any other way for this ?
regards,
PSR

Hi,
EVPRO for getting the value for PARENTH1 of any member should work. Please check whether you have included all the parameters of this function inside double quotes.
EVPRO("APPNAME","MEMBER_ID","PROPERTY")
Hope this helps,
Regards,
G.Vijaya Kumar

Similar Messages

Hierarchy Query to get parent nodes?

Hi Everyone,
I want to write a hierarchy query which should give me the path starting from given node to its parents(Grand parents). below is the sample data and the output what i am expecting. and also the output what i am getting right now from my query.
CREATE TABLE RELATION (PARENT VARCHAR2(5),CHILD VARCHAR2(5) PRIMARY KEY);
--Data for the tree which starts from the root 'A'
Insert into RELATION (PARENT, CHILD) Values (NULL,'A');
Insert into RELATION (PARENT, CHILD) Values ('A', 'B');
Insert into RELATION (PARENT, CHILD) Values ('A', 'C');
Insert into RELATION (PARENT, CHILD) Values ('B', 'D');
Insert into RELATION (PARENT, CHILD) Values ('B', 'E');
Insert into RELATION (PARENT, CHILD) Values ('D', 'F');
Insert into RELATION (PARENT, CHILD) Values ('C', 'G');
--Data for the tree which starts from the root 'H'
Insert into RELATION (PARENT, CHILD) Values (NULL,'H');
Insert into RELATION (PARENT, CHILD) Values ('H', 'I');
Insert into RELATION (PARENT, CHILD) Values ('H', 'J');
Expected Output by passing values as 'F' which gives the path from bottom to up.
A<-B<-D<-F
My Query:
SELECT substr(sys_connect_by_path(child,'<-'),3)
FROM relation
WHERE connect_by_isleaf = 1
START WITH child = 'F'
CONNECT BY PRIOR parent = child
ORDER BY child;
Output of my query:
F<-D<-B<-A
I am getting the output in reverse order. i can use the reverse string function to reverse the string but the problem is the node can also contain the values like 'AC' 'BA'.. in future.
Can anyone please help me in getting the correct output.
Thank you in advance.

I like ListAgg :D
with RELATION(PARENT,CHILD) as(
select NULL,'A' from dual union all
select 'A', 'B' from dual union all
select 'A', 'C' from dual union all
select 'B', 'D' from dual union all
select 'B', 'E' from dual union all
select 'D', 'F' from dual union all
select 'C', 'G' from dual union all
select NULL,'H' from dual union all
select 'H', 'I' from dual union all
select 'H', 'J' from dual)
SELECT ListAgg(child,'<-')
within group(order by Level desc) as revPath
FROM relation
START WITH child = 'F'
CONNECT BY PRIOR parent = child;
revPath
A<-B<-D<-F

Getting Parent Node using SQL

Hello,
I am trying to query an XML which is stored in XMLTYPE datatype column in oracle table. I am using the below SQL:
select
EXTRACTVALUE (column_name, '/Person/Customer/Customer_First_Name'),
EXTRACTVALUE (column_name, '/Person/Customer/Customer_Last_Name'),
from TABLE_1 A, TABLE ( XMLSEQUENCE (EXTRACT (A.column_name, '/sdi_header//Person')) ) P
Sample XML:
<sdi_header>
<Person>
<Customer_First_Name>ABC</Customer_First_Name>
<Customer_Last_Name>DEF</Customer_First_Name>
</Person>
<warehouse>
<Person>
<Customer_First_Name>XYZ</Customer_First_Name>
<Customer_Last_Name>MNO</Customer_First_Name>
</Person>
</warehouse>
</sdi_header>
In the above query the Alias P has a //Person which means I am trying to extract all the repeating person Nodes information in XML. Retrieving all persons is working but I want to extract the parent node information of each Person like for Example in the above sample XML, it has two persons in it
1) 1 Person is coming under sdi_header node , in such case I need to get <sdi_header/> in SELECT statement
2) 1 Person is coming under warehouse node , in such case I need to get <warehouse/>in SELECT statement
How can the parent node information be extracted in SELECT statement.
Any suggestion/Help is much appreciated.
Thanks,
SKM
Edited by: user9116854 on Mar 1, 2010 10:24 AM
Edited by: user9116854 on Mar 1, 2010 10:30 AM
Edited by: user9116854 on Mar 1, 2010 10:35 AM
Edited by: user9116854 on Mar 1, 2010 10:45 AM
Edited by: user9116854 on Mar 2, 2010 8:05 AM

Sounds like you are looking for something like this
Connected to Oracle Database 11g Enterprise Edition Release 11.1.0.6.0
SQL> WITH table_1 AS
2 (SELECT XMLTYPE('<sdi_header>
3 <Person>
4 <Customer_First_Name>ABC</Customer_First_Name>
5 <Customer_Last_Name>DEF</Customer_Last_Name>
6 </Person>
7 <warehouse>
8 <Person>
9 <Customer_First_Name>XYZ</Customer_First_Name>
10 <Customer_Last_Name>MNO</Customer_Last_Name>
11 </Person>
12 </warehouse>
13 </sdi_header>') column_name
14     FROM dual) -- WITH simulates your table I do not have
15 select t1.*
16    from TABLE_1,
17         XMLTABLE('for $i in /sdi_header//Person
18                     return <root>
19                          {$i/Customer_First_Name,
20                          $i/Customer_Last_Name}
21                          <parent>{$i/../name()}</parent>
22                     </root>'
23                  PASSING table_1.column_name
24                  COLUMNS
25                  fname   VARCHAR2(20) PATH 'Customer_First_Name',
26                  lname   VARCHAR2(20) PATH 'Customer_Last_Name',
27                  pnode   VARCHAR2(20) PATH 'parent') t1;
FNAME                LNAME                PNODE
ABC                  DEF                  sdi_header
XYZ                  MNO                  warehouseYou can find out how formatted that message by looking in the FAQ in the upper right. It uses the { code } tag (without spaces).

Getting Parent Node On tree Issue..

Hi,
I Have Constructed a Tree and i am Able to get the Details of the clicked Node on the Tree into the Backing Bean.
But I'm unable to get the Parent Node of the Clicked Child Node.
Ex:On Click of Employee(Child Node) in the Tree, I should get the Department (Parent Node) in Backing Bean.
I'm able to get only the details in the same Level of Tree Node(ie All Employees in the Selected Employee Level).
IDE: JDeveloper 10.1.3.2.
Please Suggest me.
Thanking You,
Bandaru.

Sounds like you are looking for something like this
Connected to Oracle Database 11g Enterprise Edition Release 11.1.0.6.0
SQL> WITH table_1 AS
2 (SELECT XMLTYPE('<sdi_header>
3 <Person>
4 <Customer_First_Name>ABC</Customer_First_Name>
5 <Customer_Last_Name>DEF</Customer_Last_Name>
6 </Person>
7 <warehouse>
8 <Person>
9 <Customer_First_Name>XYZ</Customer_First_Name>
10 <Customer_Last_Name>MNO</Customer_Last_Name>
11 </Person>
12 </warehouse>
13 </sdi_header>') column_name
14     FROM dual) -- WITH simulates your table I do not have
15 select t1.*
16    from TABLE_1,
17         XMLTABLE('for $i in /sdi_header//Person
18                     return <root>
19                          {$i/Customer_First_Name,
20                          $i/Customer_Last_Name}
21                          <parent>{$i/../name()}</parent>
22                     </root>'
23                  PASSING table_1.column_name
24                  COLUMNS
25                  fname   VARCHAR2(20) PATH 'Customer_First_Name',
26                  lname   VARCHAR2(20) PATH 'Customer_Last_Name',
27                  pnode   VARCHAR2(20) PATH 'parent') t1;
FNAME                LNAME                PNODE
ABC                  DEF                  sdi_header
XYZ                  MNO                  warehouseYou can find out how formatted that message by looking in the FAQ in the upper right. It uses the { code } tag (without spaces).

How to retrieve a child node's immediate parent node from a tree table?

Hello
Hi,
I have a category_subcategories table, and I would like to know how to construct a sql and sub-sql for retrieving a child node's immediate parent node.
Here is my first part of the sql, it only returns the node "Flash"'s parent and its grand-parents:
SELECT parent.category_name, node.lft, node.rgt
FROM category_subcategories AS node,
category_subcategories AS parent
WHERE node.lft > parent.lft AND node.lft < parent.rgt
AND node.category_name = 'FLASH'
ORDER BY parent.lft;
| name |
| ELECTRONICS |
| PORTABLE ELECTRONICS |
| MP3 PLAYERS | |
how can I modify this query so that it returns Flash' parent - 'MP3 Players'?
Thanks a lot
Sam

Hi,
This is an Oracle forum. If you're not iusing Oracle, make that clear. Always say what version of your softwate you're using, whether it's Oracle or anything else.
Whenever you have a question, post a little sample data (CREATE TABLE and INSERT statements), and the results you want from that data. Explain how you get those results from that data.
It looks like you're using the Nested Sets technique for modeling a tree. To get the parents of given nodes, do something like this:
SELECT        parent.category_name
,       node.lft
,       node.rgt
FROM        category_subcategories      node     -- Can't use AS with table alias in Oracle
,       category_subcategories      parent
WHERE        parent.lft      IN (
                    SELECT     MAX (lft)
                    FROM     category_subcategories
                    WHERE     lft     < node.lft
                    AND     rgt     > node.rgt
AND        node.category_name          = 'FLASH'
ORDER BY parent.lft; This should work in Oracle 8.1 and up. (I can't actually test it unless you post CREATE TABLE and INSERT statements for some sample data). You may need to modify the syntax a little for your database.
785102 wrote:
Hello,
I tried to implement the solution as follow:
mysql> select parent.*
-> from category_subcategories as parent
-> having parent.lft =
-> (select max(parent.lft) from
-> (SELECT parent.category_name, parent.lft, parent.rgt
-> FROM category_subcategories AS node,
-> category_subcategories AS parent
-> WHERE node.lft > parent.lft AND node.lft < parent.rgt
-> AND node.category_name = 'Sofa'
-> ORDER BY parent.lft
-> )
-> );
ERROR 1248 (42000): Every derived table must have its own alias
mysql>
But I got an error.
What is wrong with it?What does the error message say?
Apparantly, in your system (unlike Oracle), every sub-query must have a name. Try something like this:
select      parent.*
from      category_subcategories as parent
having      parent.lft = (
               select      max(parent.lft)
               from     (
                         SELECT        parent.category_name
                         ,       parent.lft
                         ,       parent.rgt
                         FROM        category_subcategories      AS node,
                                category_subcategories      AS parent
                         WHERE        node.lft      > parent.lft
                         AND        node.lft      < parent.rgt
                         AND        node.category_name = 'Sofa'
                         ORDER BY parent.lft     -- Is this a waste of effort?
                    ) AS got_name_lft_and_rgt
              )     AS got_lft
;What is the purpose of having the inner sub-query, the one I called got_name_lft_and_rgt?
Also, in Oracle, an ORDER BY clause in a sub-query doesn;t guarantee that any super-queries will keep that order. Why do you have an ORDER BY clause in the sub-query, and not in the main query?

Insert Parent Node From Tree To Another

Hello
My problem is: haw can I insert or shift Parent Node with its child from tree to another without use SQL query.
I should find the child and if this child has a child to shift with the parent to another tree, there are no tools or function can return the child of the node? Or what is the best procedure to do that?
I will be thankful if there some one can help me
Regards

You can grab the data with ftree.populate_group_from_tree and then use ftree.add_tree_data to put it in another tree.

How to get Parent nodes and corresponding child nodes in BI Hierarchy

Hi all,
I have a standard function module 'RSNDI_SHIE_STRUCTURE_GET3' to get child node if i pass parent node. But I need child nodes along with the provided parent node as I use this in a loop in BI.
Thanks

Could any one help me in this regards .
Thanks in advance
Regards,
sri

HOw to get parent node name value through its child node?

Hi,
Experts,
I am able to get child node name values but according to attribute name value i want to get its parent name value how to achieve that. For that i have used If_Ixml_element->Get_parent. Please pass some idea on it.
Thanks in advance,
Shabeer ahmed.

Hello Shabeer
I think the coding should be straightforward:
DATA: lo_element   TYPE REF TO if_ixml_element,
          lo_child        TYPE REF TO if_ixml_node,
          lo_parent      TYPE REF TO if_ixml_node.
" NOTE: LO_ELEMENT holds your child node
lo_child ?= lo_element.
lo_parent = lo_child->get_parent( ).
Regards
Uwe

Cant get current node from TreeCellEditor isCellEditable().

I have a custom TreeCellEditor but I do not want to allow the user to edit the root node.
I was hoping to use isCellEditable() but I can not seem to get the node that is being edited from the EventObject.
I can get the JTree, (from event.getSource(), but there is no way to get the node that is being tested. I have tried using:
tree.getEditingPath()
tree.getLastPathComponent()
tree.getSelectionPath()But they all return null at the time isCellEditable() is called.
Does anyone know of a way to get the node that is being tested?
Thanks,
Jerome.

well, that method is meant to be generic such that it decides if editing is possible for the type of event.
JTable has a separate isCellEditable method, but so does TableModel, so typically, you have a custom table model that implements the method there to return, and in that you know what cell.
For JTree, I don't know why there's no similar method in the TreeModel interface. There is in JTree, but I really think that should be a function of the model, not the view.
For JTable, I believe it's only there as a pass-thru, calling the table model's method underneath to get the value.

Using xpath to get parent nodes

hi! i�m trying to copy some elements from a xml file, and i have some problems.
i have this file
?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="xslpath.xsl"?>
<bookstore>
<book id="0">
<title id="pt">Harry Magico</title>
<desc id="1">
<price id="3">29.99</price>
<price1 id="3">329.95</price1>
</desc>
<name>nome</name>
</book>
</bookstore>
i�m using a xsl to copy the nodes.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="/">
<xsl:copy-of select="/bookstore/book/title/ancestor-or-self::price1"/> 
</xsl:template>
</xsl:stylesheet>
well, if i select price1 node, what i want to get is:
<?xml version="1.0" encoding="utf-8"?>
<bookstore>
<book id="0">
<desc id="1">
<price1 id="3">329.95</price1>
</desc>
</book>
</bookstore>
i just want copy the node without is "brothers" :) and with is parents.
can anyone help me?

hi! i�m trying to copy some elements from a xml file,
and i have some problems.
i have this file
?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl"
href="xslpath.xsl"?>
<bookstore>
<book id="0">
<title id="pt">Harry Magico</title>
<desc id="1">
<price id="3">29.99</price>
<price1 id="3">329.95</price1>
</desc>
<name>nome</name>
</book>
</bookstore>
i�m using a xsl to copy the nodes.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:template match="/">
<xsl:copy-of
select="/bookstore/book/title/ancestor-or-self::price
"/> 
</xsl:template>
l:stylesheet>
well, if i select price1 node, what i want to get
is:
<?xml version="1.0" encoding="utf-8"?>
<bookstore>
<book id="0">
<desc id="1">
<price1 id="3">329.95</price1>
</desc>
</book>
</bookstore>
i just want copy the node without is "brothers" :)
and with is parents.
can anyone help me?right off my head, try this:
/bookstore/book/title/desc/price1/ancestor-or-self::*

HFR - Getting the value from a member prompt to render in a report

I have need to see the value or values selected from an HFR report prompt on the report once the report renders.
The prompt value is desired to be placed in the Header of the report but ultimately as long we can see the prompt value rendered/placed any where on the report that will be good.
Is there a function or other means to capture the selected dimension value stemming from a prompt selection?
The more complex piece to this questions is that the row member where the prompt resides is using an advanced member selection which takes the value of the member prompt AND the Lev0 list of members to display on the report. Doing the level 0 "AND" of the advanced member selection removes any chance of getting the original prompt value select.
If any one has any ideas or tried and true techniques, please share.
Thanks in advance.
Cheers,
Christian
http://www.artofbi.com

Hi Christian
It sounds like you are familiar with the text functions that can get you member names / aliases from cells.
Have you thought about retrieving the member from the prompt and then simply hiding the column/row,
e.g. in column A select 'Prompt for Dim'
in column B select 'Descendants of Same Member as Col A' AND 'Level 0 Dim'
hide column A
use the text function to get you the name/alias from column A
Hope this helps
Stuart

How to get parents data from a leaf in a recursive table

I want to get a list of all parents data related to a leaf in a table.
The table has 3 rows id, description, parent.
if I have the id of one of this items I want to get all his parents, is there a way to get this with a select or with connect by prior?

Maybe
select substr(sys_connect_by_path(to_char(empno),','),2) parant_chain
from emp
where connect_by_isleaf = 1
start with empno = 7369
connect by empno = prior mgr
PARANT_CHAIN
7369,7902,7566,7839
Regards
Etbin

Get Parent Community from Current Comm using the G6 PRC

Can anyone provide or point me to a sample of code that gets the Parent Community ID from the current community using the G6 PRC? I can find samples of doing this in this discussion, but they appear to reference older versions of the EDK. Ideally, given the current community ID, I would like to walk backwards through the hierarchy until I find the root community (the community with no parent ID).
Thanks in advance,Jeff

Have you thought about using pt:standard.tree instead of rolling your own?
Chris Bucchere | bdg | [email protected] | www.bdg-online.com

SRM Get parent node

Dear experts,
I need to know a FM or BAPI in order to know the parent objetc/record/document that contains an element.
SAP provides the BAPI BAPI_RECORD_GETELEMENTS to get the elements of a record, but I need the opposite operation (get the record that contains the element).
Thanks in advance.
Best regards,
A. Cepa

Hi,
EVPRO for getting the value for PARENTH1 of any member should work. Please check whether you have included all the parameters of this function inside double quotes.
EVPRO("APPNAME","MEMBER_ID","PROPERTY")
Hope this helps,
Regards,
G.Vijaya Kumar

Re: Hierarchy Query to get parent nodes?

Guys i need a help here please....
i want to query using any single value for example in where clause for "E" , i want to retrieve whole bunch from "A" to "G" which are all interlinked. is there any way for this?..
im lookking like
A
B
C
D
E
F
G
when i query for "E"
Thanks in advance..

sorry,,, i couldn't explain properly...
here is the example...
CREATE TABLE RELATION (PARENT VARCHAR2(5),CHILD VARCHAR2(5) PRIMARY KEY);
---this is group 1
Insert into RELATION (PARENT, CHILD) Values ('A', 'B');
Insert into RELATION (PARENT, CHILD) Values ('A', 'C');
Insert into RELATION (PARENT, CHILD) Values ('B', 'D');
Insert into RELATION (PARENT, CHILD) Values ('B', 'E');
Insert into RELATION (PARENT, CHILD) Values ('D', 'F');
Insert into RELATION (PARENT, CHILD) Values ('C', 'G');
--This is group 2
Insert into RELATION (PARENT, CHILD) Values ('H', 'I');
Insert into RELATION (PARENT, CHILD) Values ('H', 'J');
Insert into RELATION (PARENT, CHILD) Values ('J', 'K');
Insert into RELATION (PARENT, CHILD) Values ('K', 'M');
I WILL TAKE group 1 ..
i want from relation table single column all related falling in one group . like..
when i look for E i should get all the below..
A
B
C
D
E
F
G
even though E is not directly linked to A it is linked through B. basically all in one group but the link is not direct. i dont have any group key in my table..
the query column (where clause) can be either parent or child..
hope u will gettit.. thanks for ur patience...

Get Parent node from Base member

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