Getting bits of a byte

I'm searching for an easy methode to get a bit of a byte. Is it possible to act on a single bit of a byte maybe in a way like the following:
byte myvar = (byte) 15;
boolean mostsig = mybit.BIT7;
and upside down
byte myvar;
myvar.BIT6 = true;
I searched the whole day but fund only solutions for integers. I don't want to go a long way by converting to an int and then to a String of bits ....
thx very much [alibaba]

thx I allready read the BitSet thing but it wasn't helpful because there is no function implemented to load a whole byte inside. But the bitmasking was good
thank you!!!
have fun [alibabashack]
don't wonder about alibabashackweb
alibabashackweb = alibabashack
I just had some probs I think a bug in the forum caused this. now I have an account and two screen names^^

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32 bit integer to byte

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String tChar;
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best regards

Create an int from the bytes and format that as a hex string, adding on as many extra zeros as necessary?
You could always build up a char[8] and fill it by bit-shifting and masking your int to fill it with 0-F values. This is essentially all Integer.toHexString does and it's not so special that you couldn't just reimplement it in a utility method yourself.
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OK so im a mechanical guy, not a programming guy so lets start there. I just learned how hexadecimals work and have limited experience in LABview. I have been searching this topic for days, maybe its just my vocabulary but I havent found anything.
I need to analyze a signal coming from a CAN system. I dont have the can device yet but I'm accessing position sensors on the system. They come in as 8-bit hexadecimal messages. I am currently simulating this message as a string in LABview so i can get one part of my program ready. The manufacturer has given me example code that requires concatenating two bytes but I only need 3 of the bits to be concatenated. (one needs the last bit trimmed and the other 2 need the first bit trimed.) I have already concatenated the two bytes necessary but cannot figure out how to get rid of an individual bit. I need to do this as hex values to get the proper measurements. I know my programming grammar is probably a bit off so let me give you an example.
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jpc335 wrote:
I was told by the manufacturer that the 3 bit hexadecimal string can then be converted into usable numbers. So if its faster/easier to replace the first byte with a 0 or turn it into a 3 bit hex string. Either will work.
You want to break yourself of this misuse of bit ASAP. A bit is a single 1 or 0. Hex requires 4 bits to find the values. The purpose of hex is to reduce the number of bits you must write out so things are easier to read.
0000 - 0
0001 - 1
1010 - A
1111 - F
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