Getting exe path - JSmoothed my jar

Question

I created an application and I read the path of my jar code like this:
Class cls =myClass.class;
        ProtectionDomain domain = cls.getProtectionDomain();
        CodeSource source = domain.getCodeSource();
        URL url = source.getLocation();
        String path=url.toString();
        path=path.substring(0,path.lastIndexOf('/'));Let�s suppose my app.jar is located in "C:/Program and Files/mySoftware/bb.jar"
Then, my path returns "C:/Program and Files/mySoftware"
Now I wrapped my jar into .exe file using Jsmooth(yes, I need to do that)
When I run my .exe file it finds a different code location like this:
"C:/Program and Files/tmp/images".
Is there a different way of grabbing the exe path?
Thx!!

Answer 1

ThomYork wrote:
Hi again DrLaszlo.
I tried all the previous answers on the thread about the path.
Now that I created a file .exe for my application, I could get its path using
String tmp = System.getProperty("user.dir");
Actually that's how you get the current working directory. Probably you set that to be the directory where the exe was located, but you can't rely on that in general.
Since I was trying to load an image file I had the MalformedURLException when I created
the url using the path.
So, I verify if "tmp" starts with "file:\". If not, I add it and works fine.
if(!tmp.startsWith("file:\\")){
     tmp="file:\\"+tmp;     
You should use slashes in URLs, not backslashes.