Getting Hindi input thro Keyboard

Hi!!
I am developing a GUI where I can enter Indic scripts in Swing components.I am making use of the Win2000 keyboard layout for Hindi.Bu when I start typing in,I get only ? in the JTextArea component.Kindly let me know how to enable the swing component(I tried setting the locale and font,but didn't work)to display approriate glyphs.Also TELL ME how to get the UNicode equivalent of this string.

Hi,
Hindi language support has been added since J2SDK/JRE version 1.4, but due to a
problem, Windows' Hindi keyboard layout could not be used with the Java 2
SDK/JRE. As a work around, we provided a Devanagari input method written in
Java in the SDK/JRE in version 1.4.1. Please take a look at:
http://java.sun.com/j2se/1.4.1/changes.html#i18n
Also, there is an article that includes a sample input method for 9 indic
languages, and detailed procedure to use it at:
http://java.sun.com/products/jfc/tsc/articles/InputMethod/inputmethod.html
And last but not least, the new SDK/JRE version 1.4.2 has been released just yesterday,
which corrected the above Windows keyboard layout problem. So with this
release, you can use Hindi keyboard layout with your Java applications.
Hope this helps.
Naoto

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Help - how to get 2 inputs

hi, i am creating this basic program/game. i need to get two inputs from the user. the problem is when i run the program it gets the first input from the user but then doesn't get the second input.. please help, the code is as follows:
public class game
public static void main(String[] args)
char rock = 'r';
char paper = 'p';
char sciccsors = 's';
do
System.out.println("Player 1 please enter a letter");
char c1 = SavitchIn.readChar();
System.out.println("Player 2 please enter a letter");
char c2 = SavitchIn.readChar();
winnercalculation(c1,c1);
game.winnercalculation(c1,c2);
} while (quitoption());
public static void winnercalculation(char c1, char c2)
char rock = 'r';
char paper = 'p';
char sciccsors = 's';
if ((c1 == rock) && (c2 == paper))
System.out.println("Player 2 Wins");
private static boolean quitoption()
System.out.print("Would you like to repeat this program?");
System.out.println(" (y for yes or n for no)");
char answer = SavitchIn.readLineNonwhiteChar();
return ((answer == 'y') || (answer == 'Y'));
thanks for your help
alex
(i will reply to this post with the code required to make the SavitchIn.readline thing work.

this is the code required for the SavitchIn read- copy the below code and save it as SavitchIn.java:
import java.io.*;
import java.util.*;
*Class for simple console input.
*A class designed primarily for simple keyboard input of the form
*one input value per line. If the user enters an improper input,
*i.e., an input of the wrong type or a blank line, then the user
*is prompted to reenter the input and given a brief explanation
*of what is required. Also includes some additional methods to
*input single numbers, words, and characters, without going to
*the next line.
public class SavitchIn
*Reads a line of text and returns that line as a String value.
*The end of a line must be indicated either by a new-line
*character '\n' or by a carriage return '\r' followed by a
*new-line character '\n'. (Almost all systems do this
*automatically. So, you need not worry about this detail.)
*Neither the '\n', nor the '\r' if present, are part of the
*string returned. This will read the rest of a line if the
*line is already partially read.
public static String readLine()
char nextChar;
String result = "";
boolean done = false;
while (!done)
nextChar = readChar();
if (nextChar == '\n')
done = true;
else if (nextChar == '\r')
//Do nothing.
//Next loop iteration will detect '\n'
else
result = result + nextChar;
return result;
*Reads the first string of nonwhite characters on a line and
*returns that string. The rest of the line is discarded. If
*the line contains only white space, then the user is asked
*to reenter the line.
public static String readLineWord()
String inputString = null,
result = null;
boolean done = false;
while(!done)
inputString = readLine();
StringTokenizer wordSource =
new StringTokenizer(inputString);
if (wordSource.hasMoreTokens())
result = wordSource.nextToken();
done = true;
else
System.out.println(
"Your input is not correct. Your input must");
System.out.println(
"contain at least one nonwhitespace character.");
System.out.println(
"Please, try again. Enter input:");
return result;
*Precondition: The user has entered a number of type int on
*a line by itself, except that there may be white space before
*and/or after the number.
*Action: Reads and returns the number as a value of type int.
*The rest of the line is discarded. If the input is not
*entered correctly, then in most cases, the user will be
*asked to reenter the input. In particular, this applies to
*incorrect number formats and blank lines.
public static int readLineInt()
String inputString = null;
int number = -9999;//To keep the compiler happy.
//Designed to look like a garbage value.
boolean done = false;
while (! done)
try
inputString = readLine();
inputString = inputString.trim();
number = Integer.parseInt(inputString);
done = true;
catch (NumberFormatException e)
System.out.println(
"Your input number is not correct.");
System.out.println("Your input number must be");
System.out.println("a whole number written as an");
System.out.println("ordinary numeral, such as 42");
System.out.println("Minus signs are OK,"
+ "but do not use a plus sign.");
System.out.println("Please, try again.");
System.out.println("Enter a whole number:");
return number;
*Precondition: The user has entered a number of type long on
*a line by itself, except that there may be white space
*before and/or after the number.
*Action: Reads and returns the number as a value of type
*long. The rest of the line is discarded. If the input is not
*entered correctly, then in most cases, the user will be asked
*to reenter the input. In particular, this applies to
*incorrect number formats and blank lines.
public static long readLineLong()
String inputString = null;
long number = -9999;//To keep the compiler happy.
//Designed to look like a garbage value.
boolean done = false;
while (! done)
try
inputString = readLine();
inputString = inputString.trim();
number = Long.parseLong(inputString);
done = true;
catch (NumberFormatException e)
System.out.println(
"Your input number is not correct.");
System.out.println("Your input number must be");
System.out.println("a whole number written as an");
System.out.println("ordinary numeral, such as 42");
System.out.println("Minus signs are OK,"
+ "but do not use a plus sign.");
System.out.println("Please, try again.");
System.out.println("Enter a whole number:");
return number;
*Precondition: The user has entered a number of type double
*on a line by itself, except that there may be white space
*before and/or after the number.
*Action: Reads and returns the number as a value of type
*double. The rest of the line is discarded. If the input is
*not entered correctly, then in most cases, the user will be
*asked to reenter the input. In particular, this applies to
*incorrect number formats and blank lines.
public static double readLineDouble()
String inputString = null;
double number = -9999;//To keep the compiler happy.
//Designed to look like a garbage value.
boolean done = false;
while (! done)
try
inputString = readLine();
inputString = inputString.trim();
number = Double.parseDouble(inputString);
done = true;
catch (NumberFormatException e)
System.out.println(
"Your input number is not correct.");
System.out.println("Your input number must be");
System.out.println("an ordinary number either with");
System.out.println("or without a decimal point,");
System.out.println("such as 42 or 9.99");
System.out.println("Please, try again.");
System.out.println("Enter the number:");
return number;
*Precondition: The user has entered a number of type float
*on a line by itself, except that there may be white space
*before and/or after the number.
*Action: Reads and returns the number as a value of type
*float. The rest of the line is discarded. If the input is
*not entered correctly, then in most cases, the user will
*be asked to reenter the input. In particular,
*this applies to incorrect number formats and blank lines.
public static float readLineFloat()
String inputString = null;
float number = -9999;//To keep the compiler happy.
//Designed to look like a garbage value.
boolean done = false;
while (! done)
try
inputString = readLine();
inputString = inputString.trim();
number = Float.parseFloat(inputString);
done = true;
catch (NumberFormatException e)
System.out.println(
"Your input number is not correct.");
System.out.println("Your input number must be");
System.out.println("an ordinary number either with");
System.out.println("or without a decimal point,");
System.out.println("such as 42 or 9.99");
System.out.println("Please, try again.");
System.out.println("Enter the number:");
return number;
*Reads the first nonwhite character on a line and returns
*that character. The rest of the line is discarded. If the
*line contains only white space, then the user is asked to
*reenter the line.
public static char readLineNonwhiteChar()
boolean done = false;
String inputString = null;
char nonWhite = ' ';//To keep the compiler happy.
while (! done)
inputString = readLine();
inputString = inputString.trim();
if (inputString.length() == 0)
System.out.println(
"Your input is not correct.");
System.out.println("Your input must contain at");
System.out.println(
"least one nonwhitespace character.");
System.out.println("Please, try again.");
System.out.println("Enter input:");
else
nonWhite = (inputString.charAt(0));
done = true;
return nonWhite;
*Input should consist of a single word on a line, possibly
*surrounded by white space. The line is read and discarded.
*If the input word is "true" or "t", then true is returned.
*If the input word is "false" or "f", then false is returned.
*Uppercase and lowercase letters are considered equal. If the
*user enters anything else (e.g., multiple words or different
*words), then the user is asked to reenter the input.
public static boolean readLineBoolean()
boolean done = false;
String inputString = null;
boolean result = false;//To keep the compiler happy.
while (! done)
inputString = readLine();
inputString = inputString.trim();
if (inputString.equalsIgnoreCase("true")
|| inputString.equalsIgnoreCase("t"))
result = true;
done = true;
else if (inputString.equalsIgnoreCase("false")
|| inputString.equalsIgnoreCase("f"))
result = false;
done = true;
else
System.out.println(
"Your input number is not correct.");
System.out.println("Your input must be");
System.out.println("one of the following:");
System.out.println("the word true,");
System.out.println("the word false,");
System.out.println("the letter T,");
System.out.println("or the letter F.");
System.out.println("You may use either upper-");
System.out.println("or lowercase letters.");
System.out.println("Please, try again.");
System.out.println("Enter input:");
return result;
*Reads the next input character and returns that character. The
*next read takes place on the same line where this one left off.
public static char readChar()
int charAsInt = -1; //To keep the compiler happy
try
charAsInt = System.in.read();
catch(IOException e)
System.out.println(e.getMessage());
System.out.println("Fatal error. Ending Program.");
System.exit(0);
return (char)charAsInt;
*Reads the next nonwhite input character and returns that
*character. The next read takes place immediately after
*the character read.
public static char readNonwhiteChar()
char next;
next = readChar();
while (Character.isWhitespace(next))
next = readChar();
return next;
*The following methods are not used in the text, except for
*a brief reference in Chapter 2. No program code uses them.
*However, some programmers may want to use them.
*Precondition: The next input in the stream consists of an
*int value, possibly preceded by white space, but definitely
*followed by white space.
*Action: Reads the first string of nonwhite characters
*and returns the int value it represents. Discards the first
*whitespace character after the word. The next read takes
*place immediately after the discarded whitespace.
*In particular, if the word is at the end of a line, the
*next reading will take place starting on the next line.
*If the next word does not represent an int value,
*a NumberFormatException is thrown.
public static int readInt() throws NumberFormatException
String inputString = null;
inputString = readWord();
return Integer.parseInt(inputString);
*Precondition: The next input consists of a long value,
*possibly preceded by white space, but definitely
*followed by white space.
*Action: Reads the first string of nonwhite characters and
*returns the long value it represents. Discards the first
*whitespace character after the string read. The next read
*takes place immediately after the discarded whitespace.
*In particular, if the string read is at the end of a line,
*the next reading will take place starting on the next line.
*If the next word does not represent a long value,
*a NumberFormatException is thrown.
public static long readLong()
throws NumberFormatException
String inputString = null;
inputString = readWord();
return Long.parseLong(inputString);
*Precondition: The next input consists of a double value,
*possibly preceded by white space, but definitely
*followed by white space.
*Action: Reads the first string of nonwhitespace characters
*and returns the double value it represents. Discards the
*first whitespace character after the string read. The next
*read takes place immediately after the discarded whitespace.
*In particular, if the string read is at the end of a line,
*the next reading will take place starting on the next line.
*If the next word does not represent a double value,
*a NumberFormatException is thrown.
public static double readDouble()
throws NumberFormatException
String inputString = null;
inputString = readWord();
return Double.parseDouble(inputString);
*Precondition: The next input consists of a float value,
*possibly preceded by white space, but definitely
*followed by white space.
*Action: Reads the first string of nonwhite characters and
*returns the float value it represents. Discards the first
*whitespace character after the string read. The next read
*takes place immediately after the discarded whitespace.
*In particular, if the string read is at the end of a line,
*the next reading will take place starting on the next line.
*If the next word does not represent a float value,
*a NumberFormatException is thrown.
public static float readFloat()
throws NumberFormatException
String inputString = null;
inputString = readWord();
return Float.parseFloat(inputString);
*Reads the first string of nonwhite characters and returns
*that string. Discards the first whitespace character after
*the string read. The next read takes place immediately after
*the discarded whitespace. In particular, if the string
*read is at the end of a line, the next reading will take
*place starting on the next line. Note, that if it receives
*blank lines, it will wait until it gets a nonwhitespace
*character.
public static String readWord()
String result = "";
char next;
next = readChar();
while (Character.isWhitespace(next))
next = readChar();
while (!(Character.isWhitespace(next)))
result = result + next;
next = readChar();
if (next == '\r')
next = readChar();
if (next != '\n')
System.out.println(
"Fatal Error in method readWord of class SavitchIn.");
System.exit(1);
return result;
*Precondition: The user has entered a number of type byte on
*a line by itself, except that there may be white space before
*and/or after the number.
*Action: Reads and returns the number as a value of type byte.
*The rest of the line is discarded. If the input is not
*entered correctly, then in most cases, the user will be
*asked to reenter the input. In particular, this applies to
*incorrect number formats and blank lines.
public static byte readLineByte()
String inputString = null;
byte number = -123;//To keep the compiler happy.
//Designed to look like a garbage value.
boolean done = false;
while (! done)
try
inputString = readLine();
inputString = inputString.trim();
number = Byte.parseByte(inputString);
done = true;
catch (NumberFormatException e)
System.out.println(
"Your input number is not correct.");
System.out.println("Your input number must be a");
System.out.println("whole number in the range");
System.out.println("-128 to 127, written as");
System.out.println("an ordinary numeral, such as 42.");
System.out.println("Minus signs are OK,"
+ "but do not use a plus sign.");
System.out.println("Please, try again.");
System.out.println("Enter a whole number:");
return number;
*Precondition: The user has entered a number of type short on
*a line by itself, except that there may be white space before
*and/or after the number.
*Action: Reads and returns the number as a value of type short.
*The rest of the line is discarded. If the input is not
*entered correctly, then in most cases, the user will be
*asked to reenter the input. In particular, this applies to
*incorrect number formats and blank lines.
public static short readLineShort()
String inputString = null;
short number = -9999;//To keep the compiler happy.
//Designed to look like a garbage value.
boolean done = false;
while (! done)
try
inputString = readLine();
inputString = inputString.trim();
number = Short.parseShort(inputString);
done = true;
catch (NumberFormatException e)
System.out.println(
"Your input number is not correct.");
System.out.println("Your input number must be a");
System.out.println("whole number in the range");
System.out.println("-32768 to 32767, written as");
System.out.println("an ordinary numeral, such as 42.");
System.out.println("Minus signs are OK,"
+ "but do not use a plus sign.");
System.out.println("Please, try again.");
System.out.println("Enter a whole number:");
return number;
public static byte readByte() throws NumberFormatException
String inputString = null;
inputString = readWord();
return Byte.parseByte(inputString);
public static short readShort() throws NumberFormatException
String inputString = null;
inputString = readWord();
return Short.parseShort(inputString);
//The following was intentionally not used in the code for
//other methods so that somebody reading the code could more
//quickly see what was being used.
*Reads the first byte in the input stream and returns that
*byte as an int. The next read takes place where this one
*left off. This read is the same as System.in.read(),
*except that it catches IOExceptions.
public static int read()
int result = -1; //To keep the compiler happy
try
result = System.in.read();
catch(IOException e)
System.out.println(e.getMessage());
System.out.println("Fatal error. Ending Program.");
System.exit(0);
return result;

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The first thing I would recommend would be for you to collaborate with your colleague Vinodh, since his/her recent thread is very similar to yours: Calling a BAPI from web page
In your case, the iGrid applet will run the Xacue query template and automatically display the results from your output parameter.
I would encourage you to take a look at the sticky thread at the top of the forum entitled "MII Manufacturing Templates Updated" since this MII project is full of samples for you and your colleague to learn from.

Hi I have only 2 days in USA to buy Mac Book Pro 13" with Retina display. The issue here is that I'd like to get the westerns spanish keyboard and at the apple store the guy said it will take 6 days. I was wondering if I do the purchase NY on the 7th of M

Hi I have only 2 days in USA to buy Mac Book Pro 13" with Retina display. The issue here is that I'd like to get the westerns spanish keyboard and at the apple store the guy said it will take 6 days. I was wondering if I do the purchase within the express checkout, Will I be able to get the laptop before leaving NY on the 7th of May 2014?
I do not have any experience with the express checkout, actually I do know how it works, any advice please?
Thanks!!!!

Call the store on the telephne and ask. However, I doubt it since a store would not normally have an item with non-USA features
Also, this is the Mac Pro desktop forum. I requested your post be moved to the MacBook Pro laptop forum

My apple keyboard had some problems, the store replaced it for me. I had to sign in to my computer, and couldn't get to pair the keyboard with the computer, as could not sign in. I know there is a command that lets you override this, does anyone know whic

My apple keyboard had some problems, the store replaced it for me. I had to sign in to my computer, and couldn't get to pair the keyboard with the computer, as could not sign in. I know there is a command that lets you override this, does anyone know which buttons to press. I gather when you do this, a box comes up and pairs the two with a number you have to type in.

Hi rpaspinall,
Thanks for using Apple Support Communities.
For more information on this, take a look at this article:
Apple Wireless Keyboard: Difficulty during pairing process
http://support.apple.com/kb/ts1569
Best of luck,
Mario

Getting Hindi input thro Keyboard

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