Getting the associated display from such funny data

Question

Dear All;
I was just wondering whether this can be done.
I have the following sample data below
create table tip
(ID varchar2(300),
  quantity number(30)
insert into tip
    (id, quantity)
values
   ('4Z1-4' || chr(44) ||'6-9'||chr(44)||'7B1-4'|| chr(44) ||'6-9', 16);and this is the display I want below
4Z1
4Z2
4Z3
4Z4
4Z6
4Z7
4Z8
4Z9
7B1
7B2
7B3
7B4
7B6
7B7
7B8
7B9The seperation utilizies the associated quantity as well. All help is appreciated. Thank you

Answer 1

user13328581 wrote:
Amazing Blu; One more question could you please explain the logic to me. Thanks for your effort so farWhy don't you take each part of the query (from the inner select outwards) and see what each bit does. e.g. for starters...
SQL> ed
Wrote file afiedt.buf
  1  with tip as (select '4Z1-4,6-9,7B1-4,6-9' as id, 16 as quantity from dual)
  2  --
  3  -- end of test data
  4  --
  5  --select id||to_char(lower_range+y.rn-1,'fm99999') as id
  6  --from (
  7  --      select rn, parts
  8  --            ,last_value(id ignore nulls) over (order by rn) as id
  9  --            ,to_number(regexp_substr(range,'[0-9]+',1,1)) as lower_range
10  --            ,to_number(regexp_substr(range,'[0-9]+',1,2)) as higher_range
11  --      from (
12              select rownum as rn
13                    ,regexp_substr(id,'[^,]+',1, rownum) as parts
14                    ,regexp_replace(regexp_substr(id,'[^,]+',1, rownum),'([0-9]+[A-Z])?.*','\1') as id
15                    ,regexp_replace(regexp_substr(id,'[^,]+',1, rownum),'([0-9]+[A-Z])?(.*)','\2') as range
16              from tip
17              connect by regexp_substr(id,'[^,]+',1, rownum) is not null
18  --           )
19  --     ) x
20  --     join (select rownum rn from dual connect by rownum <= 99999) y
21* --     on (y.rn <= (x.higher_range-x.lower_range)+1)
SQL> /
        RN PARTS               ID         RANGE
         1 4Z1-4               4Z         1-4
         2 6-9                            6-9
         3 7B1-4               7B         1-4
         4 6-9                            6-9then...
SQL> ed
Wrote file afiedt.buf
  1  with tip as (select '4Z1-4,6-9,7B1-4,6-9' as id, 16 as quantity from dual)
  2  --
  3  -- end of test data
  4  --
  5  --select id||to_char(lower_range+y.rn-1,'fm99999') as id
  6  --from (
  7        select rn, parts
  8              ,last_value(id ignore nulls) over (order by rn) as id
  9              ,to_number(regexp_substr(range,'[0-9]+',1,1)) as lower_range
10              ,to_number(regexp_substr(range,'[0-9]+',1,2)) as higher_range
11        from (
12              select rownum as rn
13                    ,regexp_substr(id,'[^,]+',1, rownum) as parts
14                    ,regexp_replace(regexp_substr(id,'[^,]+',1, rownum),'([0-9]+[A-Z])?.*','\1') as id
15                    ,regexp_replace(regexp_substr(id,'[^,]+',1, rownum),'([0-9]+[A-Z])?(.*)','\2') as range
16              from tip
17              connect by regexp_substr(id,'[^,]+',1, rownum) is not null
18             )
19  --     ) x
20  --     join (select rownum rn from dual connect by rownum <= 99999) y
21* --     on (y.rn <= (x.higher_range-x.lower_range)+1)
SQL> /
        RN PARTS               ID         LOWER_RANGE HIGHER_RANGE
         1 4Z1-4               4Z                   1            4
         2 6-9                 4Z                   6            9
         3 7B1-4               7B                   1            4
         4 6-9                 7B                   6            9... and the final bit you've already seen.