Getting the coordinates of an overlayed rectangle or point

I have drawn a rectangle or point on an image using the Tools and I now want to get the coordinates of the rectangle or point I have just drawn. How do I do this?

bep -
To do this, use the Regions property on the CWIMAQViewer object, and assign it into a variable of the type of the ROI (in this case, a rectangle). Here's an example:
Dim rect As CWIMAQRectangle
Set rect = CWIMAQViewer1.Regions(1)
The rect variable should now contain the dimensions of the rectangle drawn.
Let me know if you have problems with this. Thanks!
Greg Stoll
IMAQ R & D
National Instruments
Greg Stoll
LabVIEW R&D

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hi, i'm kinda new to this.
is there a way to get the starting x and y coordinates of 1 bufferedimage inside another bufferedimage
let's say this is bufferedimage 1
http://img293.imageshack.us/i/oracle.png/
and this is bufferedimage2
http://img38.imageshack.us/i/buffered2.png/
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bep -
The problem is that the two rectangles have points in common. When the CWIMAQVision.RegionsToMask is done, it sets any point that is in any region to a non-zero value, and all other points to 0. So, when the CWIMAQVision.Label is done, it sees one big rectangle of non-zero values, and labels that (and so the CWIMAQVision.Quantify sees the one rectangle as well).
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Set pMaskImage = New CWIMAQImage
pMaskImage.Type = cwimaqImageTypeU8
Me.CWIMAQViewer1.R
egions(1).Active = True
Me.CWIMAQViewer1.Regions(2).Active = False
Me.CWIMAQVision1.RegionsToMask pMaskImage, Me.CWIMAQViewer1.Regions
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Me.CWIMAQVision1.Quantify Me.CWIMAQViewer1.Image, globalReport, regionsReport, pMaskImage
dblROImean = regionsReport.Item(1).Mean
Me.CWIMAQViewer1.Regions(1).Active = False
Me.CWIMAQViewer1.Regions(2).Active = True
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Me.CWIMAQVision1.Label pMaskImage, pMaskImage, avgPixelVal
Me.CWIMAQVision1.Quantify Me.CWIMAQViewer1.Image, globalReport, regionsReport, pMaskImage
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Greg Stoll
IMAQ R & D
National Instruments
Greg Stoll
LabVIEW R&D

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I am using Illustrator CS5. Better solutions in c# language.

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Dim myApp As New Illustrator.Application
Dim myDoc As Illustrator.Document
myDoc = myApp.ActiveDocument
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Can you tell me whether you have a 32bit or 64bit system. You can find out in the following way
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Method 1: View System window in Control Panel
Click Start, type system in the Start Search box, and then click system in the Programs list.
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hi,
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I completely misunderstood your question. As I read it again it seems clear and straight-forward. I'm sorry. Let's see if this is closer.
import java.awt.*;
import java.awt.event.*;
import java.awt.geom.*;
import java.awt.image.BufferedImage;
import java.io.*;
import java.net.*;
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        panel.add(restore);
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        new CropImage();
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        image = bi;
        setSize();
        clip = new GeneralPath();
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        Point[] p = cropPanel.corners;
        int w = p[2].x - p[0].x;
        int h = p[1].y - p[3].y;
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        Graphics2D g2 = cropped.createGraphics();
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        int y = (int)(start.y + side * Math.sin(theta + Math.PI/4));
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        x = (int)(start.x + side * Math.cos(theta - Math.PI/4));
        y = (int)(start.y + side * Math.sin(theta - Math.PI/4));
        corners[3] = new Point(x, y);             // top
        cropPanel.setClip(corners);
}

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Hi,
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Getting the coordinates of an overlayed rectangle or point

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