Getting the coordinates of 1 bufferedimage inside another buffered image

Question

hi, i'm kinda new to this.
is there a way to get the starting x and y coordinates of 1 bufferedimage inside another bufferedimage
let's say this is bufferedimage 1
http://img293.imageshack.us/i/oracle.png/
and this is bufferedimage2
http://img38.imageshack.us/i/buffered2.png/
i would like a method to return the x and y coordinates of image1 inside image2
is there anyway to approach this?
or was there a prewritten method?
thanks

Answer 1

bep -
The problem is that the two rectangles have points in common. When the CWIMAQVision.RegionsToMask is done, it sets any point that is in any region to a non-zero value, and all other points to 0. So, when the CWIMAQVision.Label is done, it sees one big rectangle of non-zero values, and labels that (and so the CWIMAQVision.Quantify sees the one rectangle as well).
The easiest way around this problem (if the rectangles must have points in common) is to only make one region active at a time, so CWIMAQVision.RegionsToMask will only use that region to create the mask image, and then call CWIMAQVision.Quantify twice. So, the code would look like this:
Set pMaskImage = New CWIMAQImage
pMaskImage.Type = cwimaqImageTypeU8
Me.CWIMAQViewer1.R
egions(1).Active = True
Me.CWIMAQViewer1.Regions(2).Active = False
Me.CWIMAQVision1.RegionsToMask pMaskImage, Me.CWIMAQViewer1.Regions
Me.CWIMAQVision1.Label pMaskImage, pMaskImage, avgPixelVal
Me.CWIMAQVision1.Quantify Me.CWIMAQViewer1.Image, globalReport, regionsReport, pMaskImage
dblROImean = regionsReport.Item(1).Mean
Me.CWIMAQViewer1.Regions(1).Active = False
Me.CWIMAQViewer1.Regions(2).Active = True
Me.CWIMAQVision1.RegionsToMask pMaskImage, Me.CWIMAQViewer1.Regions
Me.CWIMAQVision1.Label pMaskImage, pMaskImage, avgPixelVal
Me.CWIMAQVision1.Quantify Me.CWIMAQViewer1.Image, globalReport, regionsReport, pMaskImage
dblSurrROImean = regionsReport.Item(1).Mean
Let me know if this gives you problems.
Greg Stoll
IMAQ R & D
National Instruments
Greg Stoll
LabVIEW R&D