GROUP BY PROBLEM IN QUERY

Question

HI ALL,
MY TABLES ARE
1. PRTRINCE FIEDS ARE: SHOP,TIMESAVED,TIMETAKEN,EMPNO
2. PRMAINCM : UNIT, STDHOURS
NOW I WANT TO DO THE FOLLOWING THING
I WANT TO CALCULATE THE % FOR EACH SHOP AND SHOW ACCORDING TO SHOP
I MEAN
SELECT A.SHOP,SUM(A.TIMETAKEN),SUM(A.TIMESAVED)
, SUM(A.TIMESAVED)*100/COUNT(A.EMPNO)*B.STDHOURS FROM
PRTRINCE A, PRMAINCM B WHERE
A.SHOP=B.UNIT
GROUP BY A.SHOP
BUT IT DOES NOT WORK AS IT SAYS COUNT(A.EMPNO)*B.STDHOURS NOT A GROUP BY EXPRESSION
SUGGEST SOME QUERY THAT CAN SOLVE MY PROBLEM
REGARDS
ABHI.

Answer 1

Hi Abhi,
Include B.STDHOURS in your group by clause and check.
SELECT A.SHOP,
       SUM(A.TIMETAKEN),
       SUM(A.TIMESAVED),
       SUM(A.TIMESAVED)*100/COUNT(A.EMPNO) * B.STDHOURS
FROM PRTRINCE A, PRMAINCM B
WHERE A.SHOP=B.UNIT
GROUP BY A.SHOP, B.STDHOURS
Tip: use proper brackets in your script as per your requirement:
select 5 * 100 / 10 * 4 from dual
=>200
select 5 * 100 / (10 * 4) from dual
=>12.5Slight modifications in the script: included disctinct for count(empno)
with PRTRINCE as (
select 'A' as SHOP, 10 as TIMESAVED, 50 as TIMETAKEN, 1 as EMPNO from dual union all
select 'A' as SHOP, 15 as TIMESAVED, 45 as TIMETAKEN, 2 as EMPNO from dual union all
select 'A' as SHOP, 5 as TIMESAVED, 60 as TIMETAKEN, 2 as EMPNO from dual union all
select 'A' as SHOP, 15 as TIMESAVED, 45 as TIMETAKEN, 2 as EMPNO from dual union all
select 'B' as SHOP, 12 as TIMESAVED, 48 as TIMETAKEN, 3 as EMPNO from dual
PRMAINCM as
select 'A' as UNIT, '8' as STDHOURS from dual union
select 'B' as UNIT, '10' as STDHOURS from dual
SELECT A.SHOP,
       SUM(A.TIMETAKEN) TIMETAKEN,
       SUM(A.TIMESAVED) TIMESAVED,
       (SUM(A.TIMESAVED)*100/COUNT(distinct A.EMPNO) * B.STDHOURS) XYZ
FROM PRTRINCE A, PRMAINCM B
WHERE A.SHOP=B.UNIT
GROUP BY A.SHOP, B.STDHOURS
SHOP     TIMETAKEN     TIMESAVED     XYZ
A     200     45     18000
B     48     12     12000Regards
Imran
Edited by: Imran Soudagar on Apr 13, 2010 10:35 AM; modified script with sample data