Have Trouble understanding the runnable interface

Question

Hi
I am new to java programming. I have trouble understanding threading concepts.When I run the below code,Thread3 runs first. I need a small clarification here- I created two thread objects
Thread thread1=new Thread(new RunnableThread(),"thread1");
Thread thread2=new Thread(new RunnableThread(),"thread2");
As soon as I create these objects -Will the constructor with the string argument in the "RunnableThread" class gets invoked. If so why doesn't System.out.println(runner.getName()); get invoked for the above objects. what is the sequence of execution for the below program.
/*************CODE****************************/
class RunnableThread implements Runnable
     Thread runner;
     public RunnableThread()
     public RunnableThread(String threadName)
          runner=new Thread(this,threadName);          //Create a new Thread.
          System.out.println(runner.getName());
          runner.start();          //Start Thread
     public void run()
          //Display info about this particular Thread
          System.out.println(Thread.currentThread());
public class RunnableExample
     public static void main(String argv[])
          Thread thread1=new Thread(new RunnableThread(),"thread1");
          Thread thread2=new Thread(new RunnableThread(),"thread2");
          RunnableThread thread3=new RunnableThread("thread3");
          //start the threads
          thread1.start();
          thread2.start();
          try
               //delay for one second
               Thread.currentThread().sleep(1000);
          catch (InterruptedException e)
          //Display info about the main thread
          System.out.println(Thread.currentThread());
}

Answer 1

srinivasaditya wrote:
Hi
I am new to java programming. I have trouble understanding threading concepts.I'd consider it to be an advanced area.
When I run the below code,Thread3 runs first. I need a small clarification here- I created two thread objects
Thread thread1=new Thread(new RunnableThread(),"thread1");
Thread thread2=new Thread(new RunnableThread(),"thread2");No, this is wrong. You don't need your RunnableThread. Runnable and Thread are enough. Your wrapper offers nothing of value.
>
As soon as I create these objects -Will the constructor with the string argument in the "RunnableThread" class gets invoked. If so why doesn't System.out.println(runner.getName()); get invoked for the above objects. what is the sequence of execution for the below program.did you run it and see? Whatever happens, that's the truth.
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