Hello can you please advise how to split a multiple VCF card (that includes 1000s of indivudual cards)
hello
i am using MCbackup on my iphone4 and did backup all my contacts into 1 single VCF card (consisting of 1000s individual vcf cards)
can you please advise how to split a multiple VCF card (that includes 1000s of indivudual cards) in order to save them in outlook 2007 as backup thanks
This is more related to Office issue, I’d like to suggest you post this issue to Office forum.
Here is the link: http://support.microsoft.com/gp/gp_newsgroups_master
***Don't forget to mark helpful or answer***
**Note:(My posts are provided “AS IS” without warranty of any kind)
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Hello,
Can you please advise me as to the recommended system requirements for Adobe CC for Photoshop, Illustrator, InDesign, and Dreamweaver (all 4 programs). I'm hoping this is summarized somewhere rather than making me look up and compare all four. I'll be using a windows based PC, and will need a graphics card that can support at least two monitors.Hi julir
check this System requirements | Photoshop
why photoshop demand?cause photoshop having 3D feature, it mean need high spec,,so if you can run photoshop cc to run ai,indd and dw is posibilty
regards
Deto -
having been with orange for many years I was dissappointed with the merge into EE and purchased a seperate contract but when I asked orange to ask apple to unlock my old iphone 4 they refused and said I have to be a CURRENT ACCOUNT HOLDER FOR A PERIOD OF GREATER THAN 6 MONTH before they will unlock it !!!!
Terms of conditions of a contract will trump anything that the user will be able to do on his own. I would reccomend you wait out the time period have the device unlocked and move on.
My apologies
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I was running Firefox 5 and have been able to protect it against new versions, but now I am not being warned that there is a new version being snuck in without telling me about it.
The problem is that I work in a virtual call center from home, and the new version is creating problems I never had before.
Is there a way you can supply me with a link to FF5, and how do I protect it against new versions being installed on my machine. This is extremely important as I earn my living from the call center.
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Any assistance would be appreciated been trolling the net for ages no success.
I apologise, I had overlooked that; it should be possible, though.
Quote from
FAQ | Adobe Creative Suite
Owners of a CS5 or CS5.5 suite edition qualify for upgrade pricing to a CS6 suite edition. Owners of an individual CS5 or CS5.5 product qualify for upgrade pricing on that CS6 product. Any version earlier than CS5 will not be eligible for upgrade pricing. -
I bought a used iphone from a friend and I am not able to use it in Ethiopia. It is carrier blocked. Can you please help how could I unlock my iphone 4?.
Unlikely as you do not meet there requirements for unlocking.
Have your friend the provided the phone contact them. Based on your statements I am concluding he was or still is an AT&T customer, that is one of the requirements of getting the device unlocked. -
My email has been working fin. however In the last day or so when i open my email or send an email it comes up with,
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Declan JacksonTry going into Settings > Mail, Contacts, Calendars and select that email account and try re-typing in the account's username and password
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trying to download indesign for mac, photoshop and illustrator trial which i require immediately but your website is crashing/saying there is an error. Can you please advise when this will be rectified?
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Hi haydenr,
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Hello,
Avery...
https://discussions.apple.com/thread/2588943?start=0&tstart=0
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Hello,
I'm having problems on the Lightroom CC App,as it seem's that when I open the Develop heading at the top of the screen,there is message that comes,which says this section is disabled and I need to renew my membership.My membership is up to date regarding payments etc.I use the student/ teacher version of the CC as I'm a student.Can anybody please advise what the problems seem's to be and what can i do to access the develop and other facilities on Lightroom?
Many Thank's
J:)
Ps Is this a common problem on the Student/teaching version of CC?This is an indication that Lightroom is not connected to your subscription. Verify that your are logged into the Creative Cloud desktop app, or try logging out and back in again to refresh your subscription information: Sign out, Sign in | Creative Cloud Desktop app.
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Can anyone please advise how I 'enable' extensions in Safari 5.0.6. on an iBook G 4?
Hi, can anyone please advise me how I 'enable' extensions in Safari 5.0.6. I have an iBook G4?
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thall3Try Safari > Preferences > Extensions
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Can you please explain how this query is fetching the rows?
here is a query to find the top 3 salaries. But the thing is that i am now able to understand how its working to get the correct data :How the data in the alias table P1 and P2 getting compared. Can you please explain in some steps.
SELECT MIN(P1.SAL) FROM PSAL P1, PSAL P2
WHERE P1.SAL >= P2.SAL
GROUP BY P2.SAL
HAVING COUNT (DISTINCT P1.SAL) <=3 ;
here is the data i used :
SQL> select * from psal;
NAME SAL
able 1000
baker 900
charles 900
delta 800
eddy 700
fred 700
george 700
george 700
Regards,
Renu... Please help me in understanding the query.
Your query looks like anything but a Top-N query.
If you run it in steps and analyze the output at the end of each step, then you should be able to understand what it does.
Given below is some brief information on the same:
test@ora>
test@ora> --
test@ora> -- Query 1 - using the non-equi (theta) join
test@ora> --
test@ora> with psal as (
2 select 'able' as name, 1000 as sal from dual union all
3 select 'baker', 900 from dual union all
4 select 'charles', 900 from dual union all
5 select 'delta', 800 from dual union all
6 select 'eddy', 700 from dual union all
7 select 'fred', 700 from dual union all
8 select 'george', 700 from dual union all
9 select 'george', 700 from dual)
10 --
11 SELECT p1.sal AS p1_sal, p1.NAME AS p1_name, p2.sal AS p2_sal,
12 p2.NAME AS p2_name
13 FROM psal p1, psal p2
14 WHERE p1.sal >= p2.sal;
P1_SAL P1_NAME P2_SAL P2_NAME
1000 able 1000 able
1000 able 900 baker
1000 able 900 charles
1000 able 800 delta
1000 able 700 eddy
1000 able 700 fred
1000 able 700 george
1000 able 700 george
900 baker 900 baker
900 baker 900 charles
900 baker 800 delta
900 baker 700 eddy
900 baker 700 fred
900 baker 700 george
900 baker 700 george
900 charles 900 baker
900 charles 900 charles
900 charles 800 delta
900 charles 700 eddy
900 charles 700 fred
900 charles 700 george
900 charles 700 george
800 delta 800 delta
800 delta 700 eddy
800 delta 700 fred
800 delta 700 george
800 delta 700 george
700 eddy 700 eddy
700 eddy 700 fred
700 eddy 700 george
700 eddy 700 george
700 fred 700 eddy
700 fred 700 fred
700 fred 700 george
700 fred 700 george
700 george 700 eddy
700 george 700 fred
700 george 700 george
700 george 700 george
700 george 700 eddy
700 george 700 fred
700 george 700 george
700 george 700 george
43 rows selected.
test@ora>
test@ora>This query joins PSAL with itself using a non equi-join. Take each row of PSAL p1 and see how it compares with PSAL p2. You'll see that:
- Row 1 with sal 1000 is >= to all sal values of p2, so it occurs 8 times
- Row 2 with sal 900 is >= to 9 sal values of p2, so it occurs 7 times
- Row 3: 7 times again... and so on.
- So, total no. of rows are: 8 + 7 + 7 + 5 + 4 + 4 + 4 + 4 = 43
test@ora>
test@ora> --
test@ora> -- Query 2 - add the GROUP BY
test@ora> --
test@ora> with psal as (
2 select 'able' as name, 1000 as sal from dual union all
3 select 'baker', 900 from dual union all
4 select 'charles', 900 from dual union all
5 select 'delta', 800 from dual union all
6 select 'eddy', 700 from dual union all
7 select 'fred', 700 from dual union all
8 select 'george', 700 from dual union all
9 select 'george', 700 from dual)
10 --
11 SELECT p2.sal AS p2_sal,
12 COUNT(*) as cnt,
13 COUNT(p1.sal) as cnt_p1_sal,
14 COUNT(DISTINCT p1.sal) as cnt_dist_p1_sal,
15 MIN(p1.sal) as min_p1_sal,
16 MAX(p1.sal) as max_p1_sal
17 FROM psal p1, psal p2
18 WHERE p1.sal >= p2.sal
19 GROUP BY p2.sal;
P2_SAL CNT CNT_P1_SAL CNT_DIST_P1_SAL MIN_P1_SAL MAX_P1_SAL
700 32 32 4 700 1000
800 4 4 3 800 1000
900 6 6 2 900 1000
1000 1 1 1 1000 1000
test@ora>
test@ora>Now, if you group by p2.sal in the output of query 1, and check the number of distinct p1.sal, min of p1.sal etc. you see that for p2.sal values - 800, 900 and 1000, there are 3 or less p1.sal values associated.
So, the last 3 rows are the ones you are interested in, essentially. As follows:
test@ora>
test@ora> --
test@ora> -- Query 3 - GROUP BY and HAVING
test@ora> --
test@ora> with psal as (
2 select 'able' as name, 1000 as sal from dual union all
3 select 'baker', 900 from dual union all
4 select 'charles', 900 from dual union all
5 select 'delta', 800 from dual union all
6 select 'eddy', 700 from dual union all
7 select 'fred', 700 from dual union all
8 select 'george', 700 from dual union all
9 select 'george', 700 from dual)
10 --
11 SELECT p2.sal AS p2_sal,
12 COUNT(*) as cnt,
13 COUNT(p1.sal) as cnt_p1_sal,
14 COUNT(DISTINCT p1.sal) as cnt_dist_p1_sal,
15 MIN(p1.sal) as min_p1_sal,
16 MAX(p1.sal) as max_p1_sal
17 FROM psal p1, psal p2
18 WHERE p1.sal >= p2.sal
19 GROUP BY p2.sal
20 HAVING COUNT(DISTINCT p1.sal) <= 3;
P2_SAL CNT CNT_P1_SAL CNT_DIST_P1_SAL MIN_P1_SAL MAX_P1_SAL
800 4 4 3 800 1000
900 6 6 2 900 1000
1000 1 1 1 1000 1000
test@ora>
test@ora>
test@ora>That's what you are doing in that query.
The thing is - in order to find out Top-N values, you simply need to scan that one table PSAL. So, joining it to itself is not necessary.
A much simpler query is as follows:
test@ora>
test@ora>
test@ora> --
test@ora> -- Top-3 salaries - distinct or not; using ROWNUM on ORDER BY
test@ora> --
test@ora> with psal as (
2 select 'able' as name, 1000 as sal from dual union all
3 select 'baker', 900 from dual union all
4 select 'charles', 900 from dual union all
5 select 'delta', 800 from dual union all
6 select 'eddy', 700 from dual union all
7 select 'fred', 700 from dual union all
8 select 'george', 700 from dual union all
9 select 'george', 700 from dual)
10 --
11 SELECT sal
12 FROM (
13 SELECT sal
14 FROM psal
15 ORDER BY sal DESC
16 )
17 WHERE rownum <= 3;
SAL
1000
900
900
test@ora>
test@ora>
test@ora>And for Top-3 distinct salaries:
test@ora>
test@ora> --
test@ora> -- Top-3 DISTINCT salaries; using ROWNUM on ORDER BY on DISTINCT
test@ora> --
test@ora> with psal as (
2 select 'able' as name, 1000 as sal from dual union all
3 select 'baker', 900 from dual union all
4 select 'charles', 900 from dual union all
5 select 'delta', 800 from dual union all
6 select 'eddy', 700 from dual union all
7 select 'fred', 700 from dual union all
8 select 'george', 700 from dual union all
9 select 'george', 700 from dual)
10 --
11 SELECT sal
12 FROM (
13 SELECT DISTINCT sal
14 FROM psal
15 ORDER BY sal DESC
16 )
17 WHERE rownum <= 3;
SAL
1000
900
800
test@ora>
test@ora>
test@ora>You may also want to check out the RANK and DENSE_RANK analytic functions.
RANK:
http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions123.htm#SQLRF00690
DENSE_RANK:
http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions043.htm#SQLRF00633
HTH
isotope
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