Help: How to use JWindow as Popup

Question

Hi there,
I am developing a program & I wanted to design it with a screen like the Mac OS (tiger?) desktop. That is menu (button bar) at the bottom of the screen (the program's screen - Not the OS).
I thought I should use a JWindow to do it.
HOW I WOULD LIKE THE POPUP TO BEHAVE:
- Only appears when a user moves the mouse towards the bottom of the screen.
- To disappear (hide) when the user clicks somewhere else on the screen [when focus is lost(?)]
- To change its position relative to the program. That is, if the program is resized etc...
I NEED YOUR HELP ON
The design issues I should take into consideration. I mean interfaces I should implement etc...
Thanks in advance.
Yours,
Me

Answer 1

Okay, sorry for the late reply, I dont go on the net much.
With the focus issues, it could be very tricky to know when exactly the Window has lost focus cause a component within the window could still have the focus, hence the window would be in focus.
One way, could be to add a common FocusListener to all the components within the window by using a recursion method, and allow this FocusListener to determine when all the elements within the window have lost focus, so as to call the window hiding function
public void addFocusListener(Component c, FocusListener fl) {
  c.addFocusListener(fl);
  if(c instanceof Container) {
     Container cn = (Container)c;
     for(int i = 0; i < cn.getComponents().length; i++) {
         addFocusListener(cn.getComponent(i), fl);
// also the focus listener could be like this
class FocusChecker implements FocusListener {
   public void focusLost(FocusEvent e) {
      Component source = (Component)e.getSource();
      if(popupWindow.isAncestorOf(source)) {
          if(!popupWindow.isFocussed()) { // check if the window has a focussed component
             moveWindowIntoHiding();  // call the method to hide to window
}This is just a general guideline. Think around this to hide the window when it looses focus
ICE