Help me for get this with array

I have a 2D array of integer number. I need compare each element of array and determine if this number is greater than 0.8; if number is greater than 0.8 I must remain the number, else if the number is less than 0.8 I must replace the element for a cero "0".
I would like thet you do suggestions for this. Help. I think use search 1D Array, but my array is 2D....Thanks

tyk007 wrote:
My advice would be similar to the brute force method mentioned with nested FOR loops, though I would tend to using the In Place Element structure and using the indices of the FOR loops to specify the index that needs checking. This also limits memory allocation if the 2D array is particularly large.
While the in place element is a good suggestion there is no benefit or advantage to using the loop index instead of using auto indexing. Is there a reason you believe this is a better approach?
Mark Yedinak
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Wreck of the Edmund Fitzgerald - Gordon Lightfoot

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How to do like this with array?

How to do like this with array?
I have 2 constants array put in main while loop ( array1{6,6}; array2{4,4} ). Those arrays will be come the input data for st in the small while loop inside.
The input data look like : [6,6],[4,4],[6,6],[4,4]...... I have to put input data to result array[8]. The method is:
input data result data
[6,6] --------------------------------------------> [6,6,0,0,0,0,0,0]
[4,4] --------------------------------------------> [6,6,4,4,0,0,0,0] ( this period, just add each element in new array)
[6,6] --------------------------------------------> [6,6,4,4,6,6,0,0]
[4,4] --------------------------------------------> [6,6,4,4,6,6,4,4]
[6,6,4,4,6,6,4,4] ( 1st period )
When the las index of result data array is filled in, I have to collapse the result data array to be this array:
----------> collapse: [6,4,6,4,0,0,0,0] ( take the average of 2 continuous element add to new result data array)
Next input data
[6,6] --------------------------------------------> [6,4,6,4,6,0,0,0]
[4,4] --------------------------------------------> [6,4,6,4,6,4,0,0] ( this period, add the average of 2 continuous elements in new array )
[6,6] --------------------------------------------> [6,4,6,4,6,4,6,0]
[4,4] --------------------------------------------> [6,4,6,4,6,4,6,4]
[6,4,6,4,6,4,6,4] ( 2 nd period)
----------> 2nd collapse [5,5,5,5,0,0,0,0] ( take the average of 2 continous element add to new result data array)
Next input data
[6,6] ....wait until input data has 4 elements
[4,4] -------------------------------------------------------------------------------------> [5,5,5,5,5,0,0,0]
[6,6] ....wait until input data has 4 elements
[4,4] -------------------------------------------------------------------------------------> [5,5,5,5,5,5,0,0]
[6,6] ....wait until input data has 4 elements
[4,4] -------------------------------------------------------------------------------------> [5,5,5,5,5,5,5,0]
[6,6] ....wait until input data has 4 elements
[4,4] -------------------------------------------------------------------------------------> [5,5,5,5,5,5,5,5]
[5,5,5,5,5,5,5,5] ( third period )
----------> 3rd collapse [5,5,5,5,0,0,0,0]
This wayl to make the tren graph.I made an VI to do that , but it's not yet correct.
Attachments:
tryyyyyyy.vi ‏39 KB
trend_mode.JPG ‏49 KB

Frankly, I don't understand your problem description or your VI.
In the description, the output array has a fixed size of 8 elements, is this correct? In this case you should initialize an array of 8 elements and do all operations "in place". I don't udnerstand the purpose of all the other code.
There are a lof of things that don't make any sense at all.
The second largest loop has no purpose, because it iterates only once per call
Sometimes you are concatenating an empty array to an existing array. This makes no difference.
Why is some of your data EXT representation???
What's up with complicated constructs such as that small loop shown in the picture. I show a somewhat simpler alternative.
Anyway, I have a hard time understanding your description. What should happen at the end? Do you have a link to a website that describes the algorithm? Does the algorithm have a name?
Message Edited by altenbach on 01-10-2008 09:55 AM
LabVIEW Champion . Do more with less code and in less time .
Attachments:
Simplify.png ‏5 KB

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