Help needed in a Query

Question

I have a table TAB that has two colums. COL1 and COL2. Both are composite Primary key.
The data is as
COL1 COL2
1 C
2 C
3 C
4 G
5 G
1 G
3 G
6 G
7 G
I need to find out those COL1 values whose COL2 values are C and G. Ex
COL1 COL2
1 C
3 C
1 G
3 G
So i need the following op
COL1
1
3
Please help me to solve this query.
Regards.
Message was edited by:
SID

Answer 1

and what have you tried ????
SQL> With t As
  2    (
  3    Select 1 c1, 'C' c2 From DUAL Union All
  4    Select 2,     'C'   From DUAL Union All
  5    Select 3,     'C'   From DUAL Union All
  6    Select 4,     'G'   From DUAL Union All
  7    Select 5,     'G'   From DUAL Union All
  8    Select 1,     'G'   From DUAL Union All
  9    Select 3,     'G'   From DUAL Union All
10    Select 6,     'G'   From DUAL Union All
11    Select 7,     'G'   From DUAL
12    )
13    Select t.c1, t.c2
14    From
15    t,
16    (
17    Select c1, c2
18    From t
19    Where c2 = 'C'
20    ) c,
21    (Select c1, c2
22     From t
23     Where c2 = 'G'
24     ) g
25  Where t.c1 = c.c1
26  And   t.c1 = g.c1
27  --And   c.c2 = g.c2;
        C1 C2
         1 C
         1 G
         3 C
         3 G
SQL>
/*using analytical functons*/
SQL>
SQL> With t As
  2    (
  3    Select 1 c1, 'C' c2 From DUAL Union All
  4    Select 2,     'C'   From DUAL Union All
  5    Select 3,     'C'   From DUAL Union All
  6    Select 4,     'G'   From DUAL Union All
  7    Select 5,     'G'   From DUAL Union All
  8    Select 1,     'G'   From DUAL Union All
  9    Select 3,     'G'   From DUAL Union All
10    Select 6,     'G'   From DUAL Union All
11    Select 7,     'G'   From DUAL
12    )
13   select c1, c2
14         from ( select c1,c2, case when c2 = 'C' then count(decode(c2,'G',1)) over (partition by c1)
15                                    when c2 = 'G' then count(decode(c2,'C',1)) over (partition by c1)
16                               else 0 end count                           
18                from t
19            )
20      where Count != 0
21  /
        C1 C2
         1 C
         1 G
         3 C
         3 GMessage was edited by:
Nicloei W