Help Needed on Hierarchial Tree
Hello All
Can any one tell me how I can check wheather a selected node is a parent node,
child node or both parent/child node.please help
Thanks in advance
Reni P G
I would try Get_Tree_Node_Parent and check if there is any parent, or maybe better Get_Tree_Node_Property in combination with NODE_DEPTH (Returns the nesting level of the hierarchical tree node.)
DS
Similar Messages
-
Help needed on hierarchy in reporting
Hi All,
We have a requirement to create variable selection at the first three node levels of a hierarchy in the report. The user should be given the option to directly enter the customer number instead of selecting the hierarchy node from the drop down.
1
2
3
4
4
2
3
4
3
4
3
2
3
3
The requirement is to have 3 variables in the selection screen
Variable for Node 1, Variable for Node 2 and Variable for Node 3. The user should be able to enter the value directly at any of
the 3 node levels and view the output. I have already checked the option of hierarchy node variables but I am not able to
choose on the node for the variable at each level.
Please provide your suggestions.
Thanks,
BiyazHi,
I would solve this by creating the hierarchy-nodes as navigatonal-attributes to 0customer.
You can set a generic DataSource onto the H-Table and check the proper nodes by programming.
Select the desired hierarchy, check the node level and assign the node to the InfoObject for the node-level.
You only have to take care with link nodes.
Thus you will be able to select in the desired way.
hope that helps
Sven -
Hi All,
Please help me with an issue of my tree.
My tree populates its nodes dynamically from an
ArrayCollection which is fed through http request-response from
servlets. Each click on a node would open its children. Then the
user can click any child node from which its immediate children
would be populated and so on. The issue is, when i click the last
node for the first time, it is not selected and the selection goes
back to the parent node itself. if i click any other node before
the last node, or after the first time click, this issue is not
there. Also if i click the open icon next to the node, it responds
correctly. The problem, i guess is only with the list property of
the tree, which does not get selected when i click the last node
for the first time.
Please help me find a solution.
Thanks in advance,
ManojHi there
Try clicking Edit > Preferences > Project > Start and End.
I'm guessing the option labeled "Auto Play" is not enabled.
Cheers... Rick
Helpful and Handy Links
Captivate Wish Form/Bug Reporting Form
Adobe Certified Captivate Training
SorcerStone Blog
Captivate eBooks -
Hi,
I need to display the parent child nodes in the hierarchical manner and i need to list the user under their hier name in the same hierarchical structure. table structures are all as follows.
user table:
* userid name*
100 john
101 shaddy
102 sandy
103 Kalinich
104 king
105 Teresa
106 Clinia
user hier table :
userid hier name
100 node1
101 node2
102 node1
103 node2
104 parent
105 node4
106 node
hier table:
id hier name parent_id
1 parent
2 node 1
3 node1 2
4 node2 2
5 node3 1
6 node4 5
7 node5 5
o/p :
104 king
106 clinia
100 john
102 sandy
103 Kalinich
101 shaddy
105 terresa
even we dont have entry in user hier and user table for node3 we need to display them child users under the "parent" hier name and need to ignore the child nodes which dont have users under them i.e) need to ignore node5 in the output. below is the query which I have tried.
SELECT NAME,u.name
FROM user_hier n,hier u,user a
WHERE a.user_id (+) = u.user_id
AND u.name (+) = n.name
START WITH n.name = 'parent'
CONNECT BY PRIOR n.node_id= n.parent_node_id;
Help me on this.
Thanks in advance
Edited by: Vi on Apr 30, 2012 6:10 AMNo you haven't. Either post create table statements or set up your data with a WITH clause, something like the following example:
with USER_TABLE as (
select 100 userid, 'john' name from dual union all
select 101 userid, 'shaddy' name from dual union all
select 102 userid, 'sandy' name from dual union all
select 103 userid, 'Kalinich' name from dual union all
select 104 userid, 'king' name from dual union all
select 105 userid, 'Teresa' name from dual union all
select 106 userid, 'Clinia' name from dual
select * from USER_TABLE
USERID NAME
100 john
101 shaddy
102 sandy
103 Kalinich
104 king
105 Teresa
106 Clinia
7 rows selected. -
Update sql help needed for hierarchy table
I am trying update the gross qty field based on each unit qty. This is how the table looks.
slevel | manager | seller |unit_qty | gross qty
0 | mary | mary | 1 | 1
.1 | mary | lynn| 3 | null
.1 | mary | betty | 2 | null
.1 | mary | alice | 2 | null
..2 | alice | susan | 1 | null
.1 | mary | amy | 4 | null
I would the table to look like this after the update, with the values
slevel | manager| seller | unit_qty | gross qty
0 | mary | mary | 1 | 1
.1 | mary | lynn| 3 | 3*1 ={color:#ff0000}3{color}
.1 | mary | betty | 2 | 2*1 ={color:#ff0000}2{color}
.1 | mary | alice | 2 | {color:#008000}2*1{color} ={color:#ff0000}2{color}
..2 | alice | susan | {color:#0000ff}1{color} | {color:#008000}2*1{color}{color:#0000ff}*1{color} ={color:#ff0000}2{color}
.1 | mary | amy | 4 | 4*1 = {color:#ff0000}4
{color}
This is the sql statement I tried to use without sucess.
update table set gross_qty = unit_qty * ({color:#ff0000}select gross_qty from table{color}
{color:#ff0000}where manager=seller{color})
where slevel >0Perhaps the old EXP (SUM (LN (n))) trick for calculating the product.
Oracle Database 10g Express Edition Release 10.2.0.1.0 - Production
SQL> CREATE TABLE seller (
2 manager VARCHAR2 (5),
3 seller VARCHAR2 (5),
4 unit_qty NUMBER,
5 gross_qty NUMBER);
Table created.
SQL> INSERT INTO seller (manager, seller, unit_qty) VALUES (NULL, 'mary', 1);
1 row created.
SQL> INSERT INTO seller (manager, seller, unit_qty) VALUES ('mary', 'lynn', 3);
1 row created.
SQL> INSERT INTO seller (manager, seller, unit_qty) VALUES ('mary', 'betty', 2);
1 row created.
SQL> INSERT INTO seller (manager, seller, unit_qty) VALUES ('mary', 'alice', 2);
1 row created.
SQL> INSERT INTO seller (manager, seller, unit_qty) VALUES ('alice', 'susan', 1);
1 row created.
SQL> INSERT INTO seller (manager, seller, unit_qty) VALUES ('mary', 'amy', 4);
1 row created.
SQL> COMMIT;
Commit complete.
SQL> SELECT manager, seller, unit_qty, gross_qty
2 FROM seller;
MANAG SELLE UNIT_QTY GROSS_QTY
mary 1
mary lynn 3
mary betty 2
mary alice 2
alice susan 1
mary amy 4
6 rows selected.
SQL> UPDATE seller s1
2 SET s1.gross_qty = (SELECT EXP (SUM (LN (s2.unit_qty)))
3 FROM seller s2
4 START WITH s2.seller = s1.seller
5 CONNECT BY s2.seller = PRIOR s2.manager);
6 rows updated.
SQL> SELECT manager, seller, unit_qty, gross_qty
2 FROM seller;
MANAG SELLE UNIT_QTY GROSS_QTY
mary 1 1
mary lynn 3 3
mary betty 2 2
mary alice 2 2
alice susan 1 2
mary amy 4 4
6 rows selected.
SQL> -
Help needed in constructing a tree
Help needed in constructing a tree. I was wondering if some one can suggest me how to add messages in the second column for both the parent node and child elements.
I was able to create a tree succefully, but want to add some description in the second column for the first column elements, for both parent and child elements.
Please suggest me how to add the arrays to second column for parent and child nodes.
Solved!
Go to Solution.
Attachments:
Tree_fix.vi 15 KBThe Child Text parameter is the one you are searching for. It accepts a 1D string array for the following columns.
hope this helps,
Norbert
CEO: What exactly is stopping us from doing this?
Expert: Geometry
Marketing Manager: Just ignore it. -
Hi Community,
I have Vision Database and I need Help regarding HRMS Hierarchy.
I am trying to fetch HRMS Hierarchy by front end and also by back end,
but i couldn't able to find it.
So please if any one know then help me.
Thanks and Regards,
Vishal WagholeCheck these -
Re: Organization hierarchy Report
Re: I need to get the organization Hierarchies
urgent...on organization and their hierarchies.
Re: Help with hierarchical query
https://forums.oracle.com/thread/search.jspa?peopleEnabled=true&userID=&containerType=&container=&q=organization+hierarc…
Cheers,
Vignesh -
Hierarchy tree with XML attributes in jsp
hi,
i need to build a hierarchy tree. data(parent and child) should be read from xml file. data is attributes of nodes in xml. i need to write the JSP code for above functionality. please help me. thanks in advance.Check this link for further details.
http://www.dpawson.co.uk/xsl/sect4/N10301.html
http://www.devx.com/getHelpOn/Article/11874
The solution is based on XSLT approach. That can be still converted in other server side technologies.
Regards,
Vikrant. -
How to create a hierarchy Tree
Oracle Forms 6i
Hai All
Could Any Tell me the steps to create a hierarchy tree in oracle forms
My table is employee_master and fields are
Empcode number ,
Empname varchar,
deptcode number,
gradecode number and etc
Here i need to create a tree with Deptcode in that every employees are seperated by grade code
Thanks In Advance
Srikkanth.MDear,
If you get any problem while creating tree, will help you step by step.....
Thank you, -
Need to expand tree by passing treeId thr URL not by clicking manually.
Sub: Need to expand tree by passing Id thr URL.
Hi,
Here i have Library.java and ajaxTree.jsf files (collected from Jboss richfaces)
There is having a list of artist .
If u click on a particular artistname then the respective albums(with their checkboxes) will expand and show like a treenode.
just look at d url : "http://localhost:8080/richfaces-demo-3.2.1.GA/richfaces/tree.jsf?c=tree&albumIds=1001,1002,1005,1008,1009,1010&client=0"
I m passing album Ids and clientId in url browser and receiving in d Library.java.
I need to expand the required client tree to show albums without clicking on artistname rather by passing the clientId from Url.
I thnk one EventHandling class( PostbackPhaseListener.java ) is responsible for expanding but I m unable to understand.
How can I do it.
Plz help asap.
/###############ajaxTree.jsf##########Start##############/
<ui:composition xmlns="http://www.w3.org/1999/xhtml"
xmlns:ui="http://java.sun.com/jsf/facelets"
xmlns:h="http://java.sun.com/jsf/html"
xmlns:f="http://java.sun.com/jsf/core"
xmlns:a4j="http://richfaces.org/a4j"
xmlns:rich="http://richfaces.org/rich"
xmlns:c="http://java.sun.com/jstl/core">
<p>This tree uses "ajax" switch type, note that for collapse/expand operations it will be Ajax request to the server. You may see short delay in this case.</p>
<h:form>
<rich:tree style="width:300px" value="#{library.data}" var="item" nodeFace="#{item.type}">
<rich:treeNode type="artist" >
<h:outputText value="#{item.name}" />
</rich:treeNode>
<rich:treeNode type="album" >
<h:selectBooleanCheckbox value="#{item.selected}"/>
<h:outputText value="#{item.title}" />
</rich:treeNode>
</rich:tree>
<h:commandButton value="Update" />
</h:form>
</ui:composition>
/###############ajaxTree.jsf##########End##############/
/************************Library.java*********Start****************/
package org.richfaces.demo.tree;
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.Iterator;
import java.util.List;
import java.util.Map;
import java.util.StringTokenizer;
import javax.servlet.http.HttpServletRequest;
import javax.faces.context.FacesContext;
import org.richfaces.model.TreeNode;
public class Library implements TreeNode {
private static final long serialVersionUID = -3530085227471752526L;
private Map artists = null;
private Object state1;
private Object state2;
private Map getArtists() {
if (this.artists==null) {
initData();
return this.artists;
public void addArtist(Artist artist) {
addChild(Long.toString(artist.getId()), artist);
public void addChild(Object identifier, TreeNode child) {
getArtists().put(identifier, child);
child.setParent(this);
public TreeNode getChild(Object id) {
return (TreeNode) getArtists().get(id);
public Iterator getChildren() {
return getArtists().entrySet().iterator();
public Object getData() {
return this;
public TreeNode getParent() {
return null;
public boolean isLeaf() {
return getArtists().isEmpty();
public void removeChild(Object id) {
getArtists().remove(id);
public void setData(Object data) {
public void setParent(TreeNode parent) {
public String getType() {
return "library";
private long nextId = 0;
private long getNextId() {
return nextId++;
private Map albumCache = new HashMap();
private Map artistCache = new HashMap();
private Artist getArtistByName(String name, Library library) {
Artist artist = (Artist)artistCache.get(name);
if (artist==null) {
artist = new Artist(getNextId());
artist.setName(name);
artistCache.put(name, artist);
library.addArtist(artist);
return artist;
private Album getAlbumByTitle(String title, Artist artist) {
Album album = (Album)albumCache.get(title);
if (album==null) {
album = new Album(getNextId());
album.setTitle(title);
albumCache.put(title, album);
artist.addAlbum(album);
return album;
private void initData() {
artists = new HashMap();
InputStream is = this.getClass().getClassLoader().getResourceAsStream("org/richfaces/demo/tree/data.txt");
ByteArrayOutputStream os = new ByteArrayOutputStream();
byte[] rb = new byte[1024];
int read;
HttpServletRequest request = (HttpServletRequest)FacesContext.getCurrentInstance().getExternalContext().getRequest();
// System.out.println("request.getParameter(param) "+request.getParameter("param"));
//System.out.println("request.getParameter(client) "+request.getParameter("client"));
//System.out.println("request.getParameter() "+request.getParameter("c"));
try {
do {
read = is.read(rb);
if (read>0) {
os.write(rb, 0, read);
} while (read>0);
String buf = os.toString();
StringTokenizer toc1 = new StringTokenizer(buf,"\n");
String str1 = request.getParameter("albumIds");
int clientId1 =Integer.parseInt( request.getParameter("client"));
while (toc1.hasMoreTokens()) {
String str = toc1.nextToken();
StringTokenizer toc2 = new StringTokenizer(str, "\t");
String artistName = toc2.nextToken();
String albumTitle = toc2.nextToken();
String songTitle = toc2.nextToken();
toc2.nextToken();
toc2.nextToken();
String albumYear = toc2.nextToken();
Artist artist = getArtistByName(artistName,this);
Album album = getAlbumByTitle(albumTitle, artist);
String portfolios[] = new String[100];
Integer portfoliosId[] = new Integer[100];
int i = 0;
StringTokenizer st = new StringTokenizer(str1, ",");
while (st.hasMoreTokens()) {
portfolios[i] = st.nextToken();
if((songTitle.equals(portfolios))&&(!(songTitle == ""))){
//System.out.println("ifff");
album.setSelected(true);
i++;
album.setYear(new Integer(albumYear));
} catch (IOException e) {
throw new RuntimeException(e);
public Object getState1() {
return state1;
public void setState1(Object state1) {
this.state1 = state1;
public Object getState2() {
return state2;
public void setState2(Object state2) {
this.state2 = state2;
public void walk(TreeNode node, List<TreeNode> appendTo, Class<? extends TreeNode> type) {
if (type.isInstance(node)){
appendTo.add(node);
Iterator<Map.Entry<Object, TreeNode>> iterator = node.getChildren();
System.out.println("walk node.getChildren() "+node.getChildren());
while(iterator.hasNext()) {
walk(iterator.next().getValue(), appendTo, type);
public ArrayList getLibraryAsList(){
ArrayList appendTo = new ArrayList();
System.out.println("getLibraryAsList appendTo "+appendTo);
walk(this, appendTo, Song.class);
return appendTo;
/************************Library.java*********End****************/
/************************PostbackPhaseListener.java*********Start****************/
package org.richfaces.treemodeladaptor;
import java.util.Map;
import javax.faces.context.ExternalContext;
import javax.faces.context.FacesContext;
import javax.faces.event.PhaseEvent;
import javax.faces.event.PhaseId;
import javax.faces.event.PhaseListener;
public class PostbackPhaseListener implements PhaseListener {
public static final String POSTBACK_ATTRIBUTE_NAME = PostbackPhaseListener.class.getName();
public void afterPhase(PhaseEvent event) {
public void beforePhase(PhaseEvent event) {
FacesContext facesContext = event.getFacesContext();
Map requestMap = facesContext.getExternalContext().getRequestMap();
requestMap.put(POSTBACK_ATTRIBUTE_NAME, Boolean.TRUE);
public PhaseId getPhaseId() {
return PhaseId.APPLY_REQUEST_VALUES;
public static boolean isPostback() {
FacesContext facesContext = FacesContext.getCurrentInstance();
if (facesContext != null) {
ExternalContext externalContext = facesContext.getExternalContext();
if (externalContext != null) {
return Boolean.TRUE.equals(
externalContext.getRequestMap().get(POSTBACK_ATTRIBUTE_NAME));
return false;
/************************PostbackPhaseListener.java*********End****************/
Edited by: rajesh_forum on Sep 17, 2008 6:13 AM
Edited by: rajesh_forum on Sep 17, 2008 6:18 AMHi
Can somebody please look into this?
Thanks
Raj
Edited by: RajICWeb on Aug 9, 2009 4:38 AM -
Help needed in tuning this query
This is the SQL i would like to tune for performace...
The table structure is given below.
The table has about 2 million rows.
From the second day onwards only around 10% of records will be between Load_Start_Time and Load_End_Time. Among these around 50% will have THAMES_URN_WITH_ROLE_SUFFIX as 'TP%'. At present there are unique and primary key indexes on THAMES_URN_WITH_ROLE_SUFFIX .
I'm sure that we need a b-tree index on STG_UPDATE_DATE_TIME as it is the column with good selectivity.
I'm primarily concerned about the substr, instr and reverese on THAMES_URN_WITH_ROLE_SUFFIX.
Also pls. let me know if the order of predicates is right.
Thanks in advance.
SELECT TPD_STG_TL_SF_LEGAL_OWNER.THAMES_URN, TPD_STG_TL_SF_LEGAL_OWNER.UPDATE_SOURCE, TPD_STG_TL_SF_LEGAL_OWNER.SOURCE_EXTRACT_DATE_TIME, TPD_STG_TL_SF_LEGAL_OWNER.LEGAL_OWNERSHIP_ISSUE_IND, TPD_STG_TL_SF_LEGAL_OWNER.CONTACTABLE_INDICATOR, TPD_STG_TL_SF_LEGAL_OWNER.ADMIN_CONTROL_INDICATOR, TPD_STG_TL_SF_LEGAL_OWNER.BANKRUPTCY_INDICATOR, TPD_STG_TL_SF_LEGAL_OWNER.ASSIGNED_INDICATOR, TPD_STG_TL_SF_LEGAL_OWNER.IN_TRUST_INDICATOR, TPD_STG_TL_SF_LEGAL_OWNER.DIVORCE_CASE_INDICATOR, TPD_STG_TL_SF_LEGAL_OWNER.POA_COP_INDICATOR, TPD_STG_TL_SF_LEGAL_OWNER.CLEANSING_STATUS, TPD_STG_TL_SF_LEGAL_OWNER.CATEGORY
FROM
TPD_STG_TL_SF_LEGAL_OWNER
WHERE
((TPD_STG_TL_SF_LEGAL_OWNER.STG_UPDATE_DATE_TIME > '$$Load_Start_Time'
AND
TPD_STG_TL_SF_LEGAL_OWNER.STG_UPDATE_DATE_TIME <= '$$Load_End_Time')
OR
(TPD_STG_TL_SF_LEGAL_OWNER.TPDB_PROCESSED_IDENTIFIER != 'Y') )
AND
SUBSTR(TPD_STG_TL_SF_LEGAL_OWNER.THAMES_URN_WITH_ROLE_SUFFIX,1,2)='TP'
AND
SUBSTR(REVERSE( TPD_STG_TL_SF_LEGAL_OWNER.THAMES_URN_WITH_ROLE_SUFFIX),INSTR(REVERSE( TPD_STG_TL_SF_LEGAL_OWNER.THAMES_URN_WITH_ROLE_SUFFIX),'-',1)-1,1)!='S'
========================================
CREATE TABLE TPD_STG_TL_SF_LEGAL_OWNER
THAMES_URN VARCHAR2(35 BYTE) NOT NULL,
UPDATE_SOURCE VARCHAR2(3 BYTE),
SOURCE_EXTRACT_DATE_TIME DATE,
LEGAL_OWNERSHIP_ISSUE_IND CHAR(1 BYTE),
CONTACTABLE_INDICATOR CHAR(1 BYTE),
ADMIN_CONTROL_INDICATOR CHAR(1 BYTE),
BANKRUPTCY_INDICATOR CHAR(1 BYTE),
ASSIGNED_INDICATOR CHAR(1 BYTE),
IN_TRUST_INDICATOR CHAR(1 BYTE),
DIVORCE_CASE_INDICATOR CHAR(1 BYTE),
POA_COP_INDICATOR CHAR(1 BYTE),
THAMES_URN_WITH_ROLE_SUFFIX VARCHAR2(39 BYTE),
THAMES_LEGAL_OWNERSHIP_IND CHAR(1 BYTE),
PRODUCT_HOLDING_ROLE_TYPE VARCHAR2(21 BYTE),
OWNERSHIP_SPLIT_PERCENTAGE NUMBER(3),
SOURCE_SYSTEM VARCHAR2(3 BYTE),
TITLE VARCHAR2(50 BYTE),
FIRST_NAME VARCHAR2(50 BYTE),
MIDDLE_INITIAL VARCHAR2(50 BYTE),
SURNAME VARCHAR2(50 BYTE),
GENDER CHAR(1 BYTE),
BIRTH_DATE DATE,
DEATH_INDICATOR CHAR(1 BYTE),
DEATH_RECORD_DATE DATE,
NATIONAL_INSURANCE_NUMBER VARCHAR2(9 BYTE),
GONE_AWAY_INDICATOR CHAR(1 BYTE),
ADDRESS_LINE_1 VARCHAR2(50 BYTE),
ADDRESS_LINE_2 VARCHAR2(50 BYTE),
ADDRESS_LINE_3 VARCHAR2(50 BYTE),
ADDRESS_LINE_4 VARCHAR2(50 BYTE),
ADDRESS_LINE_5 VARCHAR2(50 BYTE),
POST_CODE VARCHAR2(12 BYTE),
COUNTRY VARCHAR2(50 BYTE),
OVERSEAS_ADDRESS_INDICATOR CHAR(1 BYTE),
ORGANISATION_NAME VARCHAR2(50 BYTE),
TPDB_PROCESSED_IDENTIFIER CHAR(2 BYTE),
CLEANSING_STATUS VARCHAR2(30 BYTE),
CATEGORY VARCHAR2(50 BYTE),
SCHEME_NAME VARCHAR2(50 BYTE),
STG_CREATE_DATE_TIME DATE,
STG_UPDATE_DATE_TIME DATE,
LAST_UPDATED_DATE_TIME DATE
TABLESPACE TPDBS01A_DATA
PCTUSED 0
PCTFREE 10
INITRANS 1
MAXTRANS 255
STORAGE (
INITIAL 128K
NEXT 128K
MINEXTENTS 1
MAXEXTENTS 2147483645
PCTINCREASE 0
BUFFER_POOL DEFAULT
LOGGING
NOCOMPRESS
NOCACHE
NOPARALLEL
MONITORING;
CREATE UNIQUE INDEX TPD_STG_TL_SF_LEGAL_OWNER_PK ON TPD_STG_TL_SF_LEGAL_OWNER
(THAMES_URN_WITH_ROLE_SUFFIX)
LOGGING
TABLESPACE TPDBS01A_DATA
PCTFREE 10
INITRANS 2
MAXTRANS 255
STORAGE (
INITIAL 128K
NEXT 128K
MINEXTENTS 1
MAXEXTENTS 2147483645
PCTINCREASE 0
BUFFER_POOL DEFAULT
NOPARALLEL;
ALTER TABLE TPD_STG_TL_SF_LEGAL_OWNER ADD (
CONSTRAINT TPD_STG_TL_SF_LEGAL_OWNER_PK
PRIMARY KEY
(THAMES_URN_WITH_ROLE_SUFFIX)
USING INDEX
TABLESPACE TPDBS01A_DATA
PCTFREE 10
INITRANS 2
MAXTRANS 255
STORAGE (
INITIAL 128K
NEXT 128K
MINEXTENTS 1
MAXEXTENTS 2147483645
PCTINCREASE 0
));> If indexes don't help, is the only way to gain REAL
performance gain on this type of query is to
partition the table
If a Full Table Scan on a table takes "too long" (and
this is purely subjective - "too long" is different
for every problem) and indexes can't help, and we
need <100% of the rows, and if partitioning will give
us the performance we desire, is it OK do it ? Also
would STG_UPDATE_DATE_TIME be the best column to do a
index partion ?
For this type of query, partitioning on STG_UPDATE_DATE_TIME would be good.
However, partitioning is not done just for one query. It has to fit in your total design. For example, if you are also doing queries with a predicate like <column with a local unique index but not the partition key> = <constant>, it would have to visit all partitions instead of just one, and those queries would take much longer to execute. You can make the index global, but there all kind of maintenance issues with that. In short: be careful about partitioning and think it through first.
> But is it a good option to partition tables with
total no. of rows between 2 million and 5 million ? I
thought partitioning is better done for tables > 20
million.
Please throw some light on that.
Generally, partitioning is done on bigger tables, yes. But it is not about some specific number of rows. You partition a table when all forecasted use of the table is known, so you can make a good judgement which usages will benefit, which ones won't be affected and which ones are likely to suffer. When the benefits outweigh the disadvantages, you partition...
Above I had an example about queries that are going to suffer. Partitioning is beneficial for example when once in some period you'd have to delete A LOT of old rows. Or when you have some data warehousing queries that need like 10% of only the most recent data in a huge table.
The decision is yours.
Regards,
Rob. -
Help in dynamically changing tree
Plz help me in fluctuating tree at runtime.
and i also want to popup a menu when a node is right cliked.
Thanks.1)fluctuating tree...what???
2) Create a JPopUpMenu or a subclass. Add a mouselistener to the JTree.
In this listener you handle rightMouseClick.
When you detect such an mouse action open the popup with popup.show()
If you need the selected component call JTree.getLastSelectedPathComponent().
If you want to check if it is null use this: JTree.getSelectionModel().isSelectionEmpty(). So you can prevent nullpointers, cause selection can be empty
You can write a method for your popup to give it the selected component.
Then call the .show().
Tweety -
Frm-47313 Invalid Query for Hierarchy tree
Hello. i am trying to create a hierarchy tree with the following query:
SELECT 1, level, n.name, null, hn.nde_id
FROM cerpt_nodes n, cerpt_hierarchy_nodes hn
WHERE n.id = hn.nde_id
AND hn.hir_id = 1
CONNECT BY PRIOR hn.nde_id = hn.nde_id_parent_of
START WITH hn.ntp_code='ROOT';
I check the table and column names, they are correct. I tried to create tree with scott.emp table, I have no problem. The only different is this query has nested tables and where clause. Is that I cannot use WHERE clause and nested tables? Can anybody tell me what I have done wrong? Thank you very muchI had problems with joins in the same SQL statement using the Connect Prior By statement. Try creating a view over your nested tables then create the SQL statement for the tree using the view.
I ended up having a lot of problems using the tree control. I ended up modifing my database design to accomodate the short falls of the Connect Prior By statement.
Hope this helps.
Jamie -
Building hierarchy trees (ragged hierarchy) in OBIEE
We want to build a hierarchy tree to drill into the different levels of our organization. (ragged hierarchy) In OBIEE Answers or like product is there a way to expand down the page in a tree format? I am looking for what others have done to display that UI drill down similar to how the Windows registry/file system expands. Building filters across the page will not work for us. Any thoughts would be greatly appreciated. Thanks.
Edited by: jonloring on Jun 30, 2009 12:40 PMI did read it and was helpful, but I am trying to solve a UI formating problem. All the BI products seem to go across the page with filtering, not down the page in a tree format.
-
Value help on a published CR do not show the value help as an hierarchy.
Hello experts,
we published a CR based on a Bex Query to the BW role and to BOE. The parameters on CR are based on Bex Hierchy variables. If we logon with an SAP User (with SAP_ALL) on Info View/ BI Launch Pad to execute the CR the value help shows the hierarchy correctly.
+ world
+ North Amerika
+ Western Europe
+ Asia
If we logon on to Info View / BI launch Pad with a normal SAP Enduser (without SAP_ALL) but with all needed End User Roles the value help shows a flat List....
World
North Amerika
Western Europe
Asia
We try to trace this authorization issue but we do not got any clearly results.
Maybe someone knows the needed authorization Object on BW....?
Regards MichaelHi,
the authorizations are documented in the installation guide for the SAP Integration Kit and the authorization trace should show it as well
ingo
Maybe you are looking for
-
Very new user needs help setting up a three user network plus server
Hi, I'm an owner/manager of a recruitment company in the UK and we use three mac minis in our office to run our recruitment software (on a filemaker database) internet, mail and MS Office 2008. We currently use one of the mini's as a 'server' in so m
-
Using an admittedly long in the tooth iMac--dual core, 8GB RAM, etc--this problem recently emerged. Had no trouble with Fuji RAW captures from January until about three weeks ago. I haven't tried reinstalling anything and will try Aperture tonight.
-
BAdI: Enhancements to Price Determination-Can't adjust ch_komp
Hi~! I am working on the BADI method IF_EX_ME_PO_PRICING_CUST~PROCESS_KOMP. I want to chage PO net price by BADI. IF IM_ekko-bsart = 'ZNB'. SELECT SINGLE netpr INTO ls_netpr FROM zctmm090 WHERE werks = im_ekpo-werks AND
-
Hi, Recently some of the folks I've been emailing photos to from iPhoto 6 have been unable to view the photos. Other folks using AOL have had no difficulty viewing the photos. Does anyone no what's going on here and what can be done to fix things. Th
-
Where is the sleep button on the first version of the ipad
ok I seriously need help first edition ipad screen locked told to use sleep button but cannot find this as all I am seeing is my home screen where to unlock I have pressed the start button on the side held for ten secs and nothing please please help