Help required- Searching Particular string in column

Question

Hi,
I have a table by name temp and 2 values in the table. I'm using LIKE caluse to search a string. I'm getting output for some particular string. Please correct the below query for me.
I have given a table/data reference for you:
Create table temp(col1 varchar2(255));
insert into temp values ('Test_Scale_High');
1 row inserted
insert into temp values ('Test_Scale_High');
1 row inserted
commit;
select * from temp;
col1
Test_Scale_High
Test_Scale High
select * from temp where upper(col1) like '%TEST_SCALE%';
COL1
Test_Scale_High
Test_Scale High
select * from temp WHERE UPPER(COL1) LIKE '%TEST_SCALE_%';
COL1
Test_Scale_High
Test_Scale High
select * from temp WHERE UPPER(COL1) LIKE '%TEST_SCALE_H%';
No Row Selected
Thanks,
Santhosh.S

Answer 1

santhosh.shivaram wrote:
select * from temp;
col1
Test_Scale_High
Test_Scale High
select * from temp where upper(col1) like '%TEST_SCALE%';
COL1
Test_Scale_High
Test_Scale High
select * from temp WHERE UPPER(COL1) LIKE '%TEST_SCALE_%';
COL1
Test_Scale_High
Test_Scale High
If I understand your requirement correctly you need to escape the Wild Card '_'
Hope the following code helps:
SQL> set feedback on;
SQL> SELECT * FROM TEMP
  2  /
COL1
Test_Scale_High
Test_Scale High
2 rows selected.
SQL> SELECT *
  2    FROM temp
  3   WHERE UPPER (col1) LIKE '%TEST_SCALE%'
  4  /
COL1
Test_Scale_High
Test_Scale High
2 rows selected.
SQL> SELECT *
  2    FROM temp
  3   WHERE UPPER (col1) LIKE '%TEST_SCALE\_%' ESCAPE '\'
  4  /
COL1
Test_Scale_High
1 row selected.
SQL> SELECT *
  2    FROM temp
  3   WHERE UPPER (col1) LIKE '%TEST_SCALE_H%'
  4  /
COL1
Test_Scale_High
Test_Scale High
2 rows selected.
SQL> SELECT *
  2    FROM temp
  3   WHERE UPPER (col1) LIKE '%TEST_SCALE\_H%' ESCAPE '\'
  4  /
COL1
Test_Scale_High
1 row selected.
SQL>Regards,
Jo
Edited by: Joice John : Added 2 Sample Codes