Help with a program please

Question

I am very new to java and working on a program for class.... The program must take a variable x and run it through a given function and the output is a number such as 8.234141... In the end i have to take that result and have two statements print to the screen telling how many digits are on the left and how many are on the right of the decimal. I have done all except the last part the hint given is to convert the double variable into a string variable and use the indexOf() method...here is my program so far. Thanks in advance for your help
import java.util.Scanner;
public class Project3 {
public static void main(String[] args)
//Declaring my variables
double x, result, result1, result2, result3;
//User input of variable 'x'
Scanner scan = new Scanner (System.in);
System.out.println("Please enter the value for x: ");
x = scan.nextDouble();
     //Calculations for final answer
result1 = (Math.abs(Math.pow(x, 3)-(3 * Math.pow(x, 4))));
result2 = result1 + (8 * Math.pow(x, 2) + 1);
result3 = Math.sqrt(result2);
System.out.println("Result is: " + result3);      
}

Answer 1

So let me get this straight... the program is supposed to receive user input, run some arbitrary formula on it, and print the results, and then say how many digits are on the left and right of the decimal?
If this is the case, I'll give you a few hints:
~~
1) To convert a double to a string , you can do something like this:
String myString = "" + myDouble; // the "" is a pair of empty quotation marks.
2) the String class contains the method indexOf(), which searches the string for another string, and returns the index. For example:
String aString = "Hello, world!";
int anIndex = aString.indexOf("w");
anIndex will be equal to the number 7 because the "w" in aString is character number 7 (the first character is number 0, the second is 1, and so on.)
3) the String class contains the method length() which returns the length of the string.
~~
Think about these things, and if you still can't figure it out, let me know.
Edited by: Arricherekk on Sep 14, 2008 12:26 PM