Help with duplicate results

Question

Hi,
I need help desperately. The following is an example of the data that I have.
I have two tables one name Customers and the other named Orders. The tables have the following attributes
CUSTOMER
CustomerNum, CustomerName, OrderNum
ORDER
OrderNum, OrderDesc, CustomerNum
Bare in mind that the CustomerNum can have multiple customers attached to it, example a whole family (I know bad database design but it's too late to change) Let's use the following info for the tables respectively
CUSTOMER
0001 Sharon Bigbsy 1234
0001 Dale Bigbsy 1235
0001 Omar Bigbsy 1236
ORDERS
1234 Chips 0001
1235 Gatorade 0001
1236 Candy 0001
The query i'm using is select Customer.CustomerNum, Customer.CustomerName, Orders.OrderDesc from CUSTOMER, ORDERS where CUSTOMER.CustomerNum = ORDER.CustomerNum
The results are as follows
0001 Sharon Bigbsy Chips 1234
0001 Sharon Bigbsy Gatorade 1235
0001 Sharon Bigbsy Candy 1236
0001 Dale Bigbsy Chips 1234
0001 Dale Bigbsy Gatorade 1235
0001 Dale Bigbsy Candy 1236
0001 Omar Bigbsy Chips 1234
0001 Omar Bigbsy Gatorade 1235
0001 Omar Bigbsy Candy 1236
It's giving all the orders place to each customer name but I need only the following
0001 Sharon Bigbsy Chips 1234
0001 Dale Bigbsy Gatorade 1235
0001 Omar Bigbsy Candy 1236
I'm using SQL in MS Access 2003. Please disregard the abnormalities of the tables, it's someone else's work I inherited with over 6000 entried.
Any help will be greatly appreciated

Answer 1

I know only Oracle solution for this.
select CustomerNum,
       CustomerName,
       OrderDesc
from(  select Customer.CustomerNum CustomerNum,
              Customer.CustomerName CustomerName,
              Orders.OrderDesc OrderDesc,
              row_number() over (partition by
                                 Customer.CustomerNum,
                                 Customer.CustomerName
                                 order by OrderDesc) rn
       from CUSTOMER,
            ORDERS
       where CUSTOMER.CustomerNum = ORDER.CustomerNum)
where rn = 1;Cheers
Sarma.