HELP with lineage.sql

I need help with the discoverer lineage.sql that allows hyper drill from V5 OWB Eul into OWB portal.
I am still on OWB 9.0.3 and seem to have a small version problem. the portal is up, and i can jump to portal reports from within the browser ok. I have created the eul definitions in disco using the bridge. the lineage work book is working but the url being generated is the wrong format for the portal.
Does anyone know how I can sort out the lineage url construction to parse the correct format?
thanks.
Richard.

WOW! Nobody knows huh?
Well I'll let you know how I fixed it. Basically change the Disco Eul complex folder definition. After working out why the Url being contructed was wrong I changed the complex formula imbeded within the EUL object to parse the correct formula. And it now works. (I also added the hyperdrill for Impact analysis)
However the 9.03 repository is essentally a single table cmpallclasses and our table is huge. After getting the url parsing sorted, the actual underlying views were not returning data in a timely manner. Looking at the base table it has a single index, a quick bit 'o' tuning and having added three indexes my impact views return in under 2 mins which I am happy with. But my portal times out and spits out the no response from server which I think is an apache setting http.conf a generic time out. I am not sure why it may be a portal issue. I have set the owbportal to 1200 as a timeout, but something else is kicking in and killing the connex does anyone have a clue?
This is a big repository, I have around 1500 mappings now. Does anyone else have a production OWB repository of any real size?
Having sorted this out on 9.03, I am going to see how much I can apply to the 9.2 variant.
Thanks.
Richard.

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Help with: java.sql.SQLIntegrityConstraintViolationException

Hi, guys
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rizza_99 wrote:
I would like to know:
1. can i delete the index without causing further database problems
2. what causes this problem and how can i avoid it.
By understanding what the application/system is supposed to be doing and the correctly creating indexes on the database that reflect the business needs.
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You certainly don't delete indexes without that understanding however.

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Hi all ..Need help with this
to_char(last_day(add_months(sysdate,-1)),'mm/dd/yyyy')
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Tom,
Something like this
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         + 1
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FROM   DUAL;Regards

Anybody can help with this SQL?

The table is simple, only 2 columns:
create table personpay(
id integer primary key,
pay number(8,2) not null);
So the original talbe looks like this:
ID PAY
1 800
2 400
3 1200
4 500
5 600
6 1900
The requirement is to use one single query(no pl/sql) to show something lile the following, in other words, for each ID, the pay is the sum of all before itself and itself. So the query result looks like this:
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5 3500
6 5400
Again, just use one sql. No pl/sql. Anybody can help with this? I really appreciate that.
thanks,

Eh, people are so "analytically minded" that can't even notice a simple join?
Counting Ordered Rows
Let’s start with a basic counting problem. Suppose we are given a list of integers, for example:
x
2
3
4
6
9
and want to enumerate all of them sequentially like this:
x      #
2      1
3      2
4      3
6      4
9      5
Enumerating rows in the increasing order is the same as counting how many rows precede a given row.
SQL enjoys success unparalleled by any rival query language. Not the last reason for such popularity might be credited to its proximity to English . Let examine the informal idea
Enumerating rows in increasing order is counting how many rows precede a given row.
carefully. Perhaps the most important is that we referred to the rows in the source table twice: first, to a given row, second, to a preceding row. Therefore, we need to join our number list with itself (fig 1.1).
Cartesian Product
Surprisingly, not many basic SQL tutorials, which are so abundant on the web today, mention Cartesian product. Cartesian product is a join operator with no join condition
select A.*, B.* from A, B
Figure 1.1: Cartesian product of the set A = {2,3,4,6,9} by itself. Counting all the elements x that are no greater than y produces the sequence number of y in the set A.
Carrying over this idea into formal SQL query is straightforward. As it is our first query in this book, let’s do it step by step. The Cartesian product itself is
select t.x x, tt.x y
from T t, T tt
Next, the triangle area below the main diagonal is
select t.x x, tt.x y
from T t, T tt
where tt.x <= t.x
Finally, we need only one column – t.x – which we group the previous result by and count
select t.x, count(*) seqNum
from T t, T tt
where tt.x <= t.x
group by t.x
What if we modify the problem slightly and ask for a list of pairs where each number is coupled with its predecessor?
x      predecessor
2
3      2
4      3
6      4
9      6
Let me provide a typical mathematician’s answer, first -- it is remarkable in a certain way. Given that we already know how to number list elements successively, it might be tempted to reduce the current problem to the previous one:
Enumerate all the numbers in the increasing order and match each sequence number seq# with predecessor seq#-1. Next!
This attitude is, undoubtedly, the most economical way of thinking, although not necessarily producing the most efficient SQL. Therefore, let’s revisit our original approach, as illustrated on fig 1.2.
Figure 1.2: Cartesian product of the set A = {2,3,4,6,9} by itself. The predecessor of y is the maximal number in a set of x that are less than y. There is no predecessor for y = 2.
This translates into the following SQL query
select t.x, max(tt.x) predecessor
from T t, T tt
where tt.x < t.x
group by t.x
Both solutions are expressed in standard SQL leveraging join and grouping with aggregation. Alternatively, instead of joining and grouping why don’t we calculate the count or max just in place as a correlated scalar subquery:
select t.x,
(select count(*) from T tt where tt.x <= t.x) seq#
from T t
group by t.x
The subquery always returns a single value; this is why it is called scalar. The tt.x <= t.x predicate connects it to the outer query; this is why it is called correlated. Arguably, leveraging correlated scalar subqueries is one the most intuitive techniques to write SQL queries.
How about counting rows that are not necessarily distinct? This is where our method breaks. It is challenging to distinguish duplicate rows by purely logical means, so that various less “pure” counting methods were devised. They all, however, require extending the SQL syntactically, which was the beginning of slipping along the ever increasing language complexity slope.
Here is how analytic SQL extension counts rows
select x, rank() over(order by x) seq# from T; -- first problem
select x, lag() over(order by x) seq# from T; -- second problem
Many people suggest that it’s not only more efficient, but more intuitive. The idea that “analytics rocks” can be challenged in many ways. The syntactic clarity has its cost: SQL programmer has to remember (or, at least, lookup) the list of analytic functions. The performance argument is not evident, since non-analytical queries are simpler construction from optimizer perspective. A shorter list of physical execution operators implies fewer query transformation rules, and less dramatic combinatorial explosion of the optimizer search space.
It might even be argued that the syntax could be better. The partition by and order by clauses have similar functionality to the group by and order by clauses in the main query block. Yet one name was reused, and the other had been chosen to have a new name. Unlike other scalar expressions, which can be placed anywhere in SQL query where scalar values are accepted, the analytics clause lives in the scope of the select clause only. I have never been able to suppress an impression that analytic extension could be designed in more natural way.

Help with Oracle SQL to strip unwanted characters

Hello,
I have 2 columns (Weight and Height) where I need to strip the alpha characters and convert them to numbers (I am required to derive additional columns where I need to present
these values in inches, cm, KG, LB, etc. (and thus the need to convert them to numbers). I am too much a novice to understand the best way to convert these columns into numbers (same precision as you see here).
See the image below for a sample of what these columns currently contain. I simply need help with the Oracle SQL code to parse/convert these vales into number. Thanks in advance for your assistance!
Dave

Hi,
In addition to
Erland Sommarskog's comment which is of course correct and this i not the forum to ask question about Oracle, I dont want to leave you without a lead :-)
The solution both in SQL Server and Oracle should based on Regular Expressions. I highly recommended NOT to use T-SQL solutions in this case, as mentioned above, unless this is a very small table and the need is very simple and include finding one point
in the string as in
SaravanaC solution (when he assume thge string format is based on 2 parts (1) Number + (2) unit type).
In Oracle there is a build in Regular Expressions option as mentioned here: http://docs.oracle.com/cd/B12037_01/appdev.101/b10795/adfns_re.htm
In SQL Server the PATINDEX is used for simple cases and there is no built in Regular Expressions, but you can add it using CLR as shown in this link http://msdn.microsoft.com/en-us/magazine/cc163473.aspx
[Personal Site] [Blog] [Facebook]

Help with oracle sql to get all possible combinations in a table.

Hello guys I have a small predicatement that has me a bit stumped. I have a table like the following.(This is a sample of my real table. I use this to explain since the original table has sensitive data.)
CREATE TABLE TEST01(
TUID VARCHAR2(50),
FUND VARCHAR2(50),
ORG VARCHAR2(50));
Insert into TEST01 (TUID,FUND,ORG) values ('9102416AB','1XXXXX','6XXXXX');
Insert into TEST01 (TUID,FUND,ORG) values ('9102416CC','100000','67130');
Insert into TEST01 (TUID,FUND,ORG) values ('955542224','1500XX','67150');
Insert into TEST01 (TUID,FUND,ORG) values ('915522211','1000XX','67XXX');
Insert into TEST01 (TUID,FUND,ORG) values ('566653456','xxxxxx','xxxxx');
"TUID"                        "FUND"                        "ORG"
"9102416AB"                   "1XXXXX"                      "6XXXXX"
"9102416CC"                   "100000"                      "67130"
"955542224"                   "1500XX"                      "67150"
"915522211"                   "1000XX"                      "67XXX"
"566653456"                   "xxxxxx"                      "xxxxx"                       The "X"'s are wild card elements*( I inherit this and i cannot change the table format)* i would like to make a query like the following
select tuid from test01 where fund= '100000' and org= '67130'however what i really like to do is retrieve any records that have have those segements in them including 'X's
in other words the expected output here would be
"TUID"                        "FUND"                        "ORG"
"9102416AB"                   "1XXXXX"                      "6XXXXX"
"9102416CC"                   "100000"                      "67130"
"915522211"                   "1000XX"                      "67XXX"
"566653456"                   "xxxxxx"                      "xxxxx" i have started to write a massive sql statement that would have like 12 like statement in it since i would have to compare the org and fund every possible way.
This is where im headed. but im wondering if there is a better way.
select * from test02
where fund = '100000' and org = '67130'
or fund like '1%' and org like '6%'
or fund like '1%' and org like '67%'
or fund like '1%' and org like '671%'
or fund like '1%' and org like '6713%'
or fund like '1%' and org like '67130'
or fund like '10%' and org like '6%'...etc
/*seems like there should be a better way..*/can anyone give me a hand coming up with this sql statement...

mlov83 wrote:
if i run this
select tuid,fund, org
from   test01
where '100000' like translate(fund, 'xX','%%') and '67130' like translate(org, 'xX','%%');this is what i get
"TUID"                        "FUND"                        "ORG"
"9102416AB"                   "1XXXXX"                      "6XXXXX"
"9102416CC"                   "100000"                      "67130"
"915522211"                   "1000XX"                      "67XXX"
"566653456"                   "xxxxxx"                      "xxxxx"
"9148859fff"                  "1XXXXXX"                     "X6XXX"                       the last item should be excluded. The second digit in "org" is a "7" Fund is wrong, too. You're looking for 6 characters ('100000'), but fund on that row is 7 characters ('1XXXXXX').
and this is sitll getting picked up.That's why you should use the _ wild-card, instead of %
select tuid, fund, org
from    test01
where '100000' like translate (fund, 'xX', '__')
and    '67130' like translate (org, 'xX', '__')
;It's hard to see, but, in both calls to TRANSLATE, the 3rd argument is a string of 2 '_'s.

Help with dynamic SQL

Hello,
I have the following function that works ok:
CREATE OR REPLACE FUNCTION Get_Partition_Name (sTable VARCHAR2, iImportIndex INTEGER)
RETURN VARCHAR2 IS
cursor c is select A.partition_name from (select table_name, partition_name,
extractvalue (
dbms_xmlgen.
getxmltype (
'select high_value from all_tab_partitions where table_name='''
|| table_name
|| ''' and table_owner = '''
|| table_owner
|| ''' and partition_name = '''
|| partition_name
|| ''''),
'//text()') import_value from all_tab_partitions) A where table_name = sTable and A.import_value = iImportIndex;
sPartitionName VARCHAR(20);
err_num NUMBER;
BEGIN
open c;
fetch c into sPartitionName;
IF c%ISOPEN THEN
CLOSE c;
END IF;
RETURN sPartitionName;
EXCEPTION
WHEN OTHERS THEN
err_num := SQLCODE;
--save error in log table
LOG.SAVELINE(SQLCODE, SQLERRM);
END Get_Partition_Name;
I am trying to replace the cursor statement with dynamic SQL, something like (see below) but it doesn't work any more; I think I am missing some quotes.
CREATE OR REPLACE FUNCTION Get_Partition_Name (sTable VARCHAR2, iImportIndex INTEGER)
RETURN VARCHAR2 IS
TYPE t1 IS REF CURSOR;
c t1;
sSql VARCHAR2(500);
sPartitionName VARCHAR(20);
err_num NUMBER;
BEGIN
sSql := 'select A.partition_name from (select table_name, partition_name,
extractvalue (
dbms_xmlgen.
getxmltype (
''select high_value from all_tab_partitions where table_name=''''
|| table_name
|| '''' and table_owner = ''''
|| table_owner
|| '''' and partition_name = ''''
|| partition_name
|| ''''''),
''//text()'') import_value from all_tab_partitions) A where table_name = :a and A.import_value = :b';
OPEN c FOR sSql USING sTable, iImportIndex;
fetch c into sPartitionName;
IF c%ISOPEN THEN
CLOSE c;
END IF;
RETURN sPartitionName;
EXCEPTION
WHEN OTHERS THEN
err_num := SQLCODE;
--save error in log table
LOG.SAVELINE(SQLCODE, SQLERRM);
END Get_Partition_Name;
Please advise,
Regards,
M.R.

Assuming the requirement is to find the partition in the supplied table with the supplied high value and the issue is that dba/all_tab_partitions.high_value is a long, one alternative along the same lines as you've done already is as follows. (I've just used a cursor rather than a function for simplicity of demo).
SQL> var r refcursor
SQL> set autoprint on
SQL> declare
2   ctx dbms_xmlgen.ctxhandle;
3   v_table_name VARCHAR2(40) := 'LOGMNR_USER$';
4   v_value      NUMBER       := 100;
5 begin
6   ctx := DBMS_XMLGEN.NEWCONTEXT
7          ('select table_name
8            ,      partition_name
9            ,      high_value hi_val
10            from   dba_tab_partitions
11            where table_name     = :table_name');
12   dbms_xmlgen.setbindvalue(ctx,'TABLE_NAME',v_table_name);
13   open:r for
14   with x as
15   (select xmltype(dbms_xmlgen.getxml(ctx)) myxml
16    from   dual)
17   select extractvalue(x.object_value,'/ROW/TABLE_NAME') table_name
18   ,      extractvalue(x.object_value,'/ROW/PARTITION_NAME') partition_name
19   ,      extractvalue(x.object_value,'/ROW/HI_VAL') hi_val
20   from   x
21   ,      TABLE(XMLSEQUENCE(EXTRACT(x.myxml,'/ROWSET/ROW'))) x
22   where extractvalue(x.object_value,'/ROW/HI_VAL') = v_value;
23 end;
24 /
PL/SQL procedure successfully completed.
TABLE_NAME
PARTITION_NAME
HI_VAL
LOGMNR_USER$
P_LESSTHAN100
100
SQL> I'm sure there are other ways as well. Especially with XML functionality, there's normally many ways to skin a cat.

Please help with an sql to show more than one records into single row for each student

From the following data I would like to create an sql to get the information as the following layout
studentid, firstTerm, EnglishMark1,ScienceMark1,MathsMark1, Secondterm,EnglishMark2,ScienceMark2,MathsMark2,
ThirdTerm,EnglishMark3,ScienceMark3,MathsMark3 // As single rows for each student
Example
1 First, 30,40,20,Sec,30,40,20, simillarly next row for next row for another sudent. Please help to generate the sql for the same.
Please help it would be very appreciate.
With Thanks
Pol
polachan

create table yourdata (studentid int, term varchar(10), section varchar(50), Mark int)
insert into yourdata values
(1,'First','Math',20),(1,'First','English',30),(1,'First','Science',40),
(2,'First','Math',20),(2,'First','English',30),(2,'First','Science',40),
(3,'First','Math',20),(3,'First','English',30),(3,'First','Science',40),
(1,'Sec','Math',20),(1,'Sec','English',30),(1,'Sec','Science',40),
(2,'Sec','Math',20),(2,'Sec','English',30),(2,'Sec','Science',40),
(3,'Sec','Math',20),(3,'Sec','English',30),(3,'Sec','Science',40)
Select studentid
,max(case when term='First' and section='English' Then Mark End) as EnglishMark1
,max(case when term='First' and section='Science' Then Mark End) as ScienceMark1
,max(case when term='First' and section='Math' Then Mark End) as MathMark1
,max(case when term='Sec' and section='English' Then Mark End) as EnglishMark2
,max(case when term='Sec' and section='Science' Then Mark End) as ScienceMark2
,max(case when term='Sec' and section='Math' Then Mark End) as MathMark2
,max(case when term='Third' and section='English' Then Mark End) as EnglishMark3
,max(case when term='Third' and section='Science' Then Mark End) as ScienceMark3
,max(case when term='Third' and section='Math' Then Mark End) as MathMark3
From yourdata
Group by studentid
drop table yourdata

Help with structuring SQL databases for multiple photo galleries..help!?!

Hello all,
As a new PHP/SQL developer I have found great technical assistance from both this forum and from David Powers and his wonderful books. I am at a crucial point in my web development and although I believe I know which direction I need to go, I am still uncertain and so I appeal to you all for your help, especially David Powers.
The website I am building is one which will house many photo galleries. I was able to successfully modify the code provided in David Powers’ book ‘php Solutions’ so that I got the photo galleries constructed and working in the manner I desired.
That being said, a person browsing my website will be presented with a link to see the photo galleries. There will be five (5) categories in which the photos will be separated, all based on specific styles. Now that I have the galleries working, I need to know how to structure things so that I can create a page, like a TOC (table o’ contents) that shows all photo galleries by displaying a thumbnail image or two along with the description. Perhaps I’ll limit the TOC page to only show the latest 25 galleries, arranged with the most current always on top.
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bregent,
I'm chewing this over in my head, reading up on DB's in 'phpSolutions' and I think that things are slowly materializing.
Here is the structure of the website that I have planned:
MAIN PAGE
User is presented with a link on the main page to select photo galleries (other links are also present). Clicking the link takes them to the Category Page.
CATEGORY PAGE
On this page, the User will then have 5 choices based on categories (photo style). CLicking any of these 5 links will take them to respective TOC pages.
TOC PAGE
On this page, the user is greeted with a vertical list of galleries or photosets; one to three thumbs on the left, a small block of descriptive text on the right (ideally containing date/time info to show how recent the gallery is). Newest galleries appear at the top. Eventually, when there are tens or hundreds of galleries in any given catrgory, I'll need to adopt a method for breaking up the qualntity in groups (we can pick 20 for example) that can be scrolled through using a small navbar. This will keep the TOC Pages from getting endlessly long and avoid endless scrolling. User selects a gallery on this page to view.
THUMBNAIL PAGE
On choosing a gallery, a thumbnail page is generated (I have this working already)
IMAGE PAGE
On selecting any thumbnail in the grid, the user is taken to the full-sized photo with a navbar and photo counter at the top. Navlinks allow forward and back, a link to the first image, a link to the last image and one link back to the thumbnail page. (I have this working already).
I provide this info in an effort to help understand the basic structure of my site. The description above is as close to a step-by-step illustration as possible.
Thank you!
Sincerely,
wordman

Need help with MS SQL server JDBC driver

Anyone has experience getting ACS working with SQL2005? We keep getting ‘com.adobe.adept.persist.DatabaseException: java.sql.SQLException: No suitable driver’
We’re using sqljdbc.jar and sqljdbc4.jar that downloaded from Microsoft website. We added this to every library folder under tomcat, JRE and SDK but it did not help. Any suggestion will be helpful.
Thanks-

Hi,
We have ACS with SQL Server 2005 Std correctly working.
We have this settings:
############ SQL Server Connection ############
com.adobe.adept.persist.sql.driverClass=com.microsoft.sqlserver.jdbc.SQLServerDriver
com.adobe.adept.persist.sql.connection=jdbc:sqlserver://ip-addressSQL:PortSQL;databaseName =Adept
com.adobe.adept.persist.sql.dialect=microsoft
com.adobe.adept.persist.sql.user=userSQL
com.adobe.adept.persist.sql.password=passSQL
Wi use Microsoft SQL Server JDBC Driver 3.0 downloaded from Microsoft website (http://www.microsoft.com/download/en/details.aspx?id=21599)
Good luck,

Help with T-SQL query

I have 3 hierarchical tables. [Parent] ->[Child1]->[Child2]
I have [Xref] table which stores the documents associated with these three tables. In the [Xref] table, the column “TypeID” defines to which table the document is associated with.
Below is the table structure with some sample data.
Question: Given parented I want to get all the documents associated with parent as well its children. My sql query uses Union and its working fine. But Is there any other simple way to re-write this query?
(Note that this is just an example, the actual hierarchy is pretty long so my SQL is getting little messy and I want simplify it.)
TYPES
TypeID TypeName
1 Parent
2 Child1
3 Child2
TABLE - PARENT
ParentID
1
2
3
TABLE - CHILD1
Child1ID ParentID
1 1
2 1
3 2
TABLE - CHILD2
Child2ID Child1ID
1 1
2 1
3 2
4 2
XREF
DocumentID TypeID LocatorID
1 1 1
2 1 2
3 1 3
4 2 1
5 2 2
6 2 3
7 3 1
8 3 2
9 3 3
10 3 4
SELECT DocumentID FROM XREF X
JOIN Parent P ON P.ParentID = x.LocatorID AND TypeID = 1 -- Parent
WHERE P.ParentID = @ParentID
UNION
SELECT DocumentID FROM XREF X
JOIN Child1 C1 ON C1.Child1ID = x.LocatorID AND TypeID = 2 -- Child1
JOIN Parent P ON P.ParnetID = C1.ParentID
WHERE P.ParentID = @ParentID
UNION
SELECT DocumentID FROM XREF X
JOIN Child2 C2 ON C2.Child1ID = x.LocatorID AND TypeID = 3 -- Child2
JOIN Child1 C1 ON C1.Child1ID = c2.Child1ID
JOIN Parent P ON P.ParnetID = C1.ParentID
WHERE P.ParentID = @ParentID

Can you child span multiple levels? If yes, best way would be to use CTE
see
http://technet.microsoft.com/en-us/library/ms186243(v=sql.105).aspx
Please Mark This As Answer if it helps to solve the issue Visakh ---------------------------- http://visakhm.blogspot.com/ https://www.facebook.com/VmBlogs

Newbie - help with a SQL query for a bar chart - Originally posted in APEX

I originally posted this in the APEX forum but someone there suggested this is more of a SQL question. Anyone out there who can provide some assistance?
Hi,
I'm a new user on APEX with no real SQL knowledge and I'm trying to build a dashboard with charts into an existing APEX application. Based on another application, I have come up with the following SQL code:
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, count (decode(PROJECT_STATUS,'1',PROJECT_ID))"Active"
, count (decode(PROJECT_STATUS,'2',PROJECT_ID))"Complete"
, count (decode(PROJECT_STATUS,'3',PROJECT_ID))"On Hold"
, count (decode(PROJECT_STATUS,'4',PROJECT_ID))"Pipeline"
, count (decode(PROJECT_STATUS,'5',PROJECT_ID))"Pending Review"
from GRAPO_PROHEADTRK
where (PROJECT_STATUS='1' or PROJECT_STATUS='2' or PROJECT_STATUS='3' or PROJECT_STATUS='4' or PROJECT_STATUS='5' or PROJECT_STATUS='6')
group by CATEGORY
Order by COUNT(PROJECT_ID) DESC
The code from the other app was:
select null link
, FUNCTIONAL_AREA label
, count (decode(PROJECT_STATUS,'Active',PROJECT_ID))"Active"
, count (decode(PROJECT_STATUS,'Complete',PROJECT_ID))"Complete"
, count (decode(PROJECT_STATUS,'On Hold',PROJECT_ID)) "On Hold"
, count (decode(PROJECT_STATUS,'Recurring',PROJECT_ID))"Recurring"
, count (decode(PROJECT_STATUS,'Pipeline',PROJECT_ID))"Pipeline"
, count (decode(PROJECT_STATUS,'Not Approved',PROJECT_ID))"Not Approved"
from PM_V2
where LOB='S2S' and (FUNCTIONAL_AREA='Accounts Payable' or FUNCTIONAL_AREA='Expense' or FUNCTIONAL_AREA='Procurement' or FUNCTIONAL_AREA='Fixed Assets')
group by FUNCTIONAL_AREA
Order by COUNT(PROJECT_ID) DESC
I'm getting a "Failed to parse SQL query!" error when I try to run validation.
Is this enough info for some assistance? Any help would really be appreciated.
Thanks,
Rachel

Hi, Rachel,
user10774102 wrote:
I originally posted this in the APEX forum but someone there suggested this is more of a SQL question. Anyone out there who can provide some assistance?
Hi,
I'm a new user on APEX with no real SQL knowledge and I'm trying to build a dashboard with charts into an existing APEX application. Based on another application, I have come up with the following SQL code:
select null link
, CATEGORY label
, count (decode(PROJECT_STATUS,'1',PROJECT_ID))"Active"
, count (decode(PROJECT_STATUS,'2',PROJECT_ID))"Complete"
, count (decode(PROJECT_STATUS,'3',PROJECT_ID))"On Hold"
, count (decode(PROJECT_STATUS,'4',PROJECT_ID))"Pipeline"
, count (decode(PROJECT_STATUS,'5',PROJECT_ID))"Pending Review"
from GRAPO_PROHEADTRK
where (PROJECT_STATUS='1' or PROJECT_STATUS='2' or PROJECT_STATUS='3' or PROJECT_STATUS='4' or PROJECT_STATUS='5' or PROJECT_STATUS='6')
group by CATEGORY
Order by COUNT(PROJECT_ID) DESCIs there a problem with the code above?
It's curious that the WHERE clause includes "PROJECT_STATUS='6'", but there is no pivoted column for project_status='6', like there is for '1' through '5'. That's not necessarily a mistake, and it wouldn't raise an error in any case.
Instead of
where (PROJECT_STATUS='1' or PROJECT_STATUS='2' or PROJECT_STATUS='3' or PROJECT_STATUS='4' or PROJECT_STATUS='5' or PROJECT_STATUS='6')you could say
where PROJECT_STATUS IN ('1', '2', '3', '4', '5', '6')but that probably has nothing to do with your current problem.
The code from the other app was:
select null link
, FUNCTIONAL_AREA label
, count (decode(PROJECT_STATUS,'Active',PROJECT_ID))"Active"
, count (decode(PROJECT_STATUS,'Complete',PROJECT_ID))"Complete"
, count (decode(PROJECT_STATUS,'On Hold',PROJECT_ID)) "On Hold"
, count (decode(PROJECT_STATUS,'Recurring',PROJECT_ID))"Recurring"
, count (decode(PROJECT_STATUS,'Pipeline',PROJECT_ID))"Pipeline"
, count (decode(PROJECT_STATUS,'Not Approved',PROJECT_ID))"Not Approved"
from PM_V2
where LOB='S2S' and (FUNCTIONAL_AREA='Accounts Payable' or FUNCTIONAL_AREA='Expense' or FUNCTIONAL_AREA='Procurement' or FUNCTIONAL_AREA='Fixed Assets')
group by FUNCTIONAL_AREA
Order by COUNT(PROJECT_ID) DESC
I'm getting a "Failed to parse SQL query!" error when I try to run validation.Is that an Apex error message? Sorry, I don't know anything about Apex.
If you can't get a more specific error message from Apex, then try debugging this statement in SQL*Plus. When you get it fixed, then you can copy it back into Apex.
If this is a SQL problem, then you should be able to re-create the problem in pure SQL.
If you can't re-create the problem in pure SQL, then it's probably an Apex problem, and belongs in the Apex forum, not here.
I don't see anything obviously wrong with your code, but I can't tell if, for example, you spelled a column name wrong, or if something has the wrong data type
Is this enough info for some assistance? Any help would really be appreciated.It wiould be better if you posted a completE script that people could run to re-create the problem, and to test their ideas.
Whenever you have a problem, please post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) from all tables involved.
Also post the results you want from that data, and an explanation of how you get those results from that data, with specific examples.
Always say which version of Oracle (and any other software, such as Apex) you're using.

Newbie - need help with a SQL query for a bar chart

Hi,
I'm a new user on APEX with no real SQL knowledge and I'm trying to build a dashboard with charts into an existing APEX application. Based on another application, I have come up with the following SQL code:
select null link
, CATEGORY label
, count (decode(PROJECT_STATUS,'1',PROJECT_ID))"Active"
, count (decode(PROJECT_STATUS,'2',PROJECT_ID))"Complete"
, count (decode(PROJECT_STATUS,'3',PROJECT_ID))"On Hold"
, count (decode(PROJECT_STATUS,'4',PROJECT_ID))"Pipeline"
, count (decode(PROJECT_STATUS,'5',PROJECT_ID))"Pending Review"
from GRAPO_PROHEADTRK
where (PROJECT_STATUS='1' or PROJECT_STATUS='2' or PROJECT_STATUS='3' or PROJECT_STATUS='4' or PROJECT_STATUS='5' or PROJECT_STATUS='6')
group by CATEGORY
Order by COUNT(PROJECT_ID) DESC
The code from the other app was:
select null link
, FUNCTIONAL_AREA label
, count (decode(PROJECT_STATUS,'Active',PROJECT_ID))"Active"
, count (decode(PROJECT_STATUS,'Complete',PROJECT_ID))"Complete"
, count (decode(PROJECT_STATUS,'On Hold',PROJECT_ID)) "On Hold"
, count (decode(PROJECT_STATUS,'Recurring',PROJECT_ID))"Recurring"
, count (decode(PROJECT_STATUS,'Pipeline',PROJECT_ID))"Pipeline"
, count (decode(PROJECT_STATUS,'Not Approved',PROJECT_ID))"Not Approved"
from PM_V2
where LOB='S2S' and (FUNCTIONAL_AREA='Accounts Payable' or FUNCTIONAL_AREA='Expense' or FUNCTIONAL_AREA='Procurement' or FUNCTIONAL_AREA='Fixed Assets')
group by FUNCTIONAL_AREA
Order by COUNT(PROJECT_ID) DESC
I'm getting a "Failed to parse SQL query!" error when I try to run validation.
Is this enough info for some assistance? Any help would really be appreciated.
Thanks,
Rachel

Hello,
This is more of an SQL question, rather than specifically APEX-related. It's notable that you say: I'm a new user on APEX with no real SQL knowledgeWhich is fine (we all have to start somewhere, afterall) but it might be worth de-coupling the problem from APEX in the first instance. I'd also strongly recommend either taking a course, reading a book (e.g. http://books.google.co.uk/books?id=r5vbGgz7TFsC&printsec=frontcover&dq=Mastering+Oracle+SQL&hl=en#v=onepage&q=Mastering%20Oracle%20SQL&f=false) or looking for a basic SQL tutorial - it will save you a whole lot of heartache, I promise you. Search the oracle forums for the terms "Basic SQL Tutorial" and you should come up with a bunch of results.
Given that you've copied your query template from another, I would suggest ensuring that the actual query works first of all. Try running it in either:
* SQL Editor
* SQL*Plus
* an IDE like SQL Developer (available free from the OTN: http://www.oracle.com/technetwork/developer-tools/sql-developer/downloads/index.html ) or TOAD or similar.
You may find there are syntax errors associated with the query - it's difficult to tell without looking at your data model.
select null link
, CATEGORY label
, count (decode(PROJECT_STATUS,'1',PROJECT_ID))"Active"
, count (decode(PROJECT_STATUS,'2',PROJECT_ID))"Complete"
, count (decode(PROJECT_STATUS,'3',PROJECT_ID))"On Hold"
, count (decode(PROJECT_STATUS,'4',PROJECT_ID))"Pipeline"
, count (decode(PROJECT_STATUS,'5',PROJECT_ID))"Pending Review"
from GRAPO_PROHEADTRK
where (PROJECT_STATUS='1' or PROJECT_STATUS='2' or PROJECT_STATUS='3' or PROJECT_STATUS='4' or PROJECT_STATUS='5' or PROJECT_STATUS='6')
group by CATEGORYNote that your "order by" clause references a field called "PROJECT_ID", which exists in the old query but you've changed other similar references to "PROJECT_STATUS" - is it possible you've just missed this one? The perils of copy-paste coding I'm afraid...

Power Query for Excel - Need Help with Oracle SQL Syntax

Hello everyone,
I am new to Power Query and am not able to figure this out. I am trying to pull in data into my Excel spreadsheet using a specific Oracle SQL query. While in query editor, how do I take the Oracle.Database function and add my SQL statement?
I already know what I want, I don't want it to download all the table names. According to the help page, I should be able to do this but it does not provide a syntax example
Also, I don't understand what "optional options as nullable record" means.
Below is what function and arguments the help page notes. How do I use this?
Oracle.Database(server as text, optional options as nullable record) as table
Any help is greatly appreciated.
Thank you,
Jessica

When I try this, I get an error
DataSource.Error: Oracle: Sql.Database does not support the query option 'Query' with value '"Select * from Owner.View_Name"'. Details: null
I'm trying to download oracle data from a view into power query - Power Query navigator does not list th eviews from my source, it lists only the tables. When I try write sql statements, it throws me the above
error. This is what I tried
Oracle.Database("Source/Service",[Query="Select * from Owner.View_Name"])
Any ideas how to fix this?

HELP with lineage.sql

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