Help with oracle sql to get all possible combinations in a table.

Question

Hello guys I have a small predicatement that has me a bit stumped. I have a table like the following.(This is a sample of my real table. I use this to explain since the original table has sensitive data.)
CREATE TABLE TEST01(
TUID VARCHAR2(50),
FUND VARCHAR2(50),
ORG  VARCHAR2(50));
Insert into TEST01 (TUID,FUND,ORG) values ('9102416AB','1XXXXX','6XXXXX');
Insert into TEST01 (TUID,FUND,ORG) values ('9102416CC','100000','67130');
Insert into TEST01 (TUID,FUND,ORG) values ('955542224','1500XX','67150');
Insert into TEST01 (TUID,FUND,ORG) values ('915522211','1000XX','67XXX');
Insert into TEST01 (TUID,FUND,ORG) values ('566653456','xxxxxx','xxxxx');
"TUID"                        "FUND"                        "ORG"                        
"9102416AB"                   "1XXXXX"                      "6XXXXX"                     
"9102416CC"                   "100000"                      "67130"                      
"955542224"                   "1500XX"                      "67150"                      
"915522211"                   "1000XX"                      "67XXX"                      
"566653456"                   "xxxxxx"                      "xxxxx"                       The "X"'s are wild card elements*( I inherit this and i cannot change the table format)* i would like to make a query like the following
select tuid from test01 where fund= '100000' and org= '67130'however what i really like to do is retrieve any records that have have those segements in them including 'X's
in other words the expected output here would be
"TUID"                        "FUND"                        "ORG"                        
"9102416AB"                   "1XXXXX"                      "6XXXXX"                     
"9102416CC"                   "100000"                      "67130"                      
"915522211"                   "1000XX"                      "67XXX"                      
"566653456"                   "xxxxxx"                      "xxxxx"  i have started to write a massive sql statement that would have like 12 like statement in it since i would have to compare the org and fund every possible way.
This is where im headed. but im wondering if there is a better way.
select * from test02
where fund = '100000' and org = '67130'
or fund like '1%' and org like '6%'
or fund like '1%' and org like '67%'
or fund like '1%' and org like '671%'
or fund like '1%' and org like '6713%'
or fund like '1%' and org like '67130'
or fund like '10%' and org like '6%'...etc
/*seems like there should be a better way..*/can anyone give me a hand coming up with this sql statement...

Answer 1

mlov83 wrote:
if i run this
select tuid,fund, org
from   test01
where '100000' like translate(fund, 'xX','%%') and '67130' like translate(org, 'xX','%%');this is what i get
"TUID"                        "FUND"                        "ORG"                        
"9102416AB"                   "1XXXXX"                      "6XXXXX"                     
"9102416CC"                   "100000"                      "67130"                      
"915522211"                   "1000XX"                      "67XXX"                      
"566653456"                   "xxxxxx"                      "xxxxx"                      
"9148859fff"                  "1XXXXXX"                     "X6XXX"                       the last item should be excluded. The second digit in "org" is a "7" Fund is wrong, too. You're looking for 6 characters ('100000'), but fund on that row is 7 characters ('1XXXXXX').
and this is sitll getting picked up.That's why you should use the _ wild-card, instead of %
select  tuid, fund, org
from    test01
where  '100000' like translate (fund, 'xX', '__')
and    '67130'  like translate (org,  'xX', '__')
;It's hard to see, but, in both calls to TRANSLATE, the 3rd argument is a string of 2 '_'s.