Help with UL navigation list

Hello all, I need some help with a left navigation menu I
have created, you can see the code below:
the problem I have is when I am putting a link to the UL it
doesn't work ( probably because I have a background image in my
CSS) i was wondering if I can do it with another way..
css code
.treemenu {
margin : 0px 20px;
padding : 10px;
list-style : none;
width : 200px;
.treemenu ul {
list-style : none;
margin : 0px 5px;
padding : 0px 5px;
.treemenu li {
display : inline;
.treemenu a {
display : block;
padding-left : 0px;
text-decoration : none;
.treemenu .treeopen {
background-image : url('../img/open.gif');
background-repeat : no-repeat;
background-position : left;
.treemenu .treeclosed {
background-image : url('../img/closed.gif');
background-repeat : no-repeat;
background-position : left;
UL

Similar Messages

I need help with the navigation menu please?

I have been working my way through your six part printed instructions and I am styling the header and navigation menu. The bullet points disappeared which was correct and the tabs moved to the right, as they should, but one tab sits underneath another tab and all tabs are covered up by my main heading. This is dreamweaver CS6.
It looks a bit of a mess!

I have moved this to the main Dreamweaver forum, as the other forum is intended to deal with the Getting Started video tutorial.
The best way to get help with layout problems is to upload the files to a website and post the URL in the forum. Someone can then look at the code, and identify the problem. Judging from your description, it sounds as though the Document window is narrow, which would result in the final menu tab dropping down to the next row. Try turning on Live view or previewing the page in a browser. Design view gives only an approximate idea of the final layout. Live view renders the page as it should look in a browser.

Help with sorting a list

Hi,
can anyone help me with sorting of a list by date?
I have like 5 objects in the list, 4 are string and one is list.
I want to sort them by Date..
How can I do that?
I don't know if I can use CompateTo?? I am new to programing, I would appreciate if anyone can explain with sample code.
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ASH_2007 wrote:
Hey thanks for your response, but there is a little problem with what I said earlier.
Actually my List is a type of record (it's called Employee record)
Here what exactly I have:
for Iint i=0; i< employeeRecord.getList().size(); i++)
EmployeeRecord emp = employeeRecord.getList().get(i);
//so if I can not hold my date information in an object, coz it's says type mismatch
//I am not sure how can I do this?
}Can you please help with sample code?
Thanks tonsEither cast or learn about generics. Also, use an Iterator or a foreach loop, NOT get(i).
[Collections tutorial|http://java.sun.com/docs/books/tutorial/collections/]
[Generics intro|http://java.sun.com/j2se/1.5.0/docs/guide/language/generics.html]
[Generics tutorial|http://java.sun.com/j2se/1.5/pdf/generics-tutorial.pdf]
Foreach

I need help with circular linked list

Hi,
I need help with my code. when I run it I only get the 3 showing and this is what Im supposed to ouput
-> 9 -> 3 -> 7
empty false
9
empty false
3
-> 7
empty false
Can someone take a look at it and tell me what I'm doing wrong. I could nto figure it out.
Thanks.This is my code
/ A circular linked list class with a dummy tail
public class CLL{
     CLLNode tail;
     public CLL( ){
          tail = new CLLNode(0,null); // node to be dummy tail
          tail.next = tail;
     public String toString( ){
     // fill this in. It should print in a format like
     // -> 3 -> 5 -> 7
if(tail==null)return "( )";
CLLNode temp = tail.next;
String retval = "-> ";
     for(int i = 0; i < -999; i++)
do{
retval = (retval + temp.toString() + " ");
temp = temp.next;
}while(temp!=tail.next);
retval+= "";}
return retval;
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     public void addAtTail(int num){
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     if (tail == null)
               tail.data = num;
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               tail = n;
     public void addAtHead(int num){
     // fill in here
     if(tail == null)
          CLLNode l = new CLLNode(num, null);
          l.next = tail;
          tail =l;
     if(tail!=null)
          CLLNode l = new CLLNode(num, null);
          tail.next = l;
          l.next = tail;
          tail = l;
     public int removeHead( ){
     // fill in here
     int num;
     if(tail.next!= null)
          tail = tail.next.next;
          //removeHead(tail.next);
          tail.next.next = tail.next;
     return tail.next.data;
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          cll.addAtTail(9);
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          cll.addAtTail(7);
          System.out.println(cll);
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          System.out.println(cll.removeHead( ));
          System.out.println("empty " + cll.isEmpty( ));
          System.out.println(cll.removeHead( ));
          System.out.println(cll);
          System.out.println("empty " + cll.isEmpty( ));
class CLLNode{
     int data;
     CLLNode next;
     public CLLNode(int dta, CLLNode nxt){
          data = dta;
          next = nxt;
}

I'm not going thru all the code to just "fix it for you". But I do see one glaringly obvious mistake:
for(int i = 0; i < -999; i++)That says:
1) Initialize i to 0
2) while i is less than -999, do something
Since it is initially 0, it will never enter that loop body.

Working with "tabbed navigation list" widths

I have created a list of type "tabbed navigation list" and added it to a page. I modified the "template" for the page adding a bottom border to the table for the tabbed navigation list.
http://htmldb.oracle.com/pls/otn/f?p=36420:1:
How would I control the width of this tab navigation list?
I would like to make the width extend to 100% of the page, however, I'm unable to control the width either by setting the region width or the template width for the tabbed navigation list.
Thank you!

Hello,
Your Region Template is a table and collapsing down. Remove the region template or change it so the table has width="100%" or change it to Report Region 100% Template if your using one of the builtin themes.
Carl
Message was edited by:
Carl Backstrom

Need help with a navigation bar

I am new to Dreamweaver,working on my first page. This is my first post too, so I hope that I am doing this correctly. I created a set of navigation bars last night. It is a vertical bar with 9 items. It looked great except the items were not centered in the sidebar. I was experimenting tonight and now 8 of the "items"/titles have disappeared. The list is basically gone except for the one title. When I look in the code view all the items are listed. I hate to delete the page and start over. Does anyone have any ideas?

It sounds like you're using CSS to make a list of links turn into a navigation bar. If so, is there a problem with you're CSS?
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Nick

Need help with drop down list in parameters

Hi All,
I have the following data set:
DEPT1     DEPT2     DEPT3 DEPT4
Commissioner's Office     Finance     Accounting     Accounts Payable
Commissioner's Office     Finance     Accounting     Fiscal Analysis & Repo
Commissioner's Office     Finance     Accounting
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Commissioner's Office     Planning,Asset Mgt     Asset Management     Mobility & Congestion
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Thanks

Hi
First of all you need to be using Discoverer 10g or 11g Plus not 9.0.4. Assuming you have the right version you need to present the parameters in the correct order. You can change the order on the parameters screen by selecting Tools | Parameters from the toolbar. You then use the Move Up and Move Down buttons to place them in the right order so that DEPT1 is offered first, followed by DEPT2, then DEPT3 and then DEPT4.
Next, you need to check the radion button on the bottom of the right-hand side that allows linking of parameters then you make DEPT2 dependent upon DEPT1, with DEPT3 dependent upon DEPT2 and so on.
While this works without hierarchies it works best when you have a hierarchy in place and even better when there is a composite index on the 4 items.
Best wishes
Michael

Need help with page navigation

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This is the code that DW put in there:
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$pageNum_rs_results = 0;
if (isset($_GET['pageNum_rs_results'])) {
$pageNum_rs_results = $_GET['pageNum_rs_results'];
$startRow_rs_results = $pageNum_rs_results * $maxRows_rs_results;
$queryString_rs_results = "";
if (!empty($_SERVER['QUERY_STRING'])) {
$params = explode("&", $_SERVER['QUERY_STRING']);
$newParams = array();
foreach ($params as $param) {
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if (count($newParams) != 0) {
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$query_limit_rs_results = sprintf("%s LIMIT %d, %d", $query_rs_results, $startRow_rs_results, $maxRows_rs_results);
$rs_results = mysql_query($query_limit_rs_results, $dqdb) or die(mysql_error());
$row_rs_results = mysql_fetch_assoc($rs_results);
if (isset($_GET['totalRows_rs_results'])) {
$totalRows_rs_results = $_GET['totalRows_rs_results'];
} else {
$all_rs_results = mysql_query($query_rs_results);
$totalRows_rs_results = mysql_num_rows($all_rs_results);
$totalPages_rs_results = ceil($totalRows_rs_results/$maxRows_rs_results)-1;
TIA!

I've put some echo statements into my code to figure out what it is doing and I can see why I'm getting the results I'm getting, but I don't know how to fix it.
Here's a description of my site. A user has a select form where they can select records matching their critiera. There are over 30 attributes that can be selected. None of them can be selected and that results in every record in the database being displayed. Any combination of the attributes can be selected and that results in the set of records that match that criteria.
There is one caveat. One of the attributes has multiple possible values. Any given record will only have one value for that attribute, but the selection critiera may include multiple values of that attribute. So in the middle of the string of "<value = > and <value = >", I have "and (<value = > OR <value = > OR....) and <value=>". You can see the actual select statement I have built in a previous discussion I started.
I'm not a sophisticated php programmer or DW user for that matter, so I don't know how to build an array to capture my record data and then read the array to display the page. It would be simpler if the selection critiera wasn't so complex - I have found several snippets of code that work well with simple select statements, but I have not been able to adjust them to work with this kind of selection possibility.
So what I see happening is that after the first mysql statement correctly retrieves the results set, the code to set the select statement is executed again. But at this second time through, the $_POST values from my form are no longer set to correctly build the select statement. I thought I might save the select statement and use some if/else logic to circumvent this, but all variables seem to be getting reset when the logic goes back up to the top of the code.
I hope I'm describing this clearly enough to generate some helpful responses.
TIA!

Help with copying SP List data to SQL Server

I need to read some data from a SP list and copy it to a table in SQL Server.
Visual Studio BIDS 2013. SharePoint 2010. Planning to migrate to 2013 this year. I tried to use the
SP Data source/destination adapter with SSIS, but learned that I can't with Visual Studio 2013. I'm really looking for any way to read data from a SP list and import it into a SQL database (SQL 2014). Haven't found anything online that has worked for me the
way they say it should (such as OData connection in SSIS). Maybe it's version issues.
Does anyone have a solid step-by step to do this? I am not a C# developer...

Hi,
According to your description, my understanding is that you want to read SharePoint list data and copy it to SQL Server table.
Hatim's option is a way to achieve it manually.
If you want to do it automatically, I suggest you can create a console application to read SharePoint list using CAML Query and Client Object Model, Then use SqlConnection object to connect database, then you can insert record using SqlCommand object.
Here are some detailed code demos for your reference:
http://www.codeproject.com/Articles/399156/SharePoint-Client-Object-Model-Introduction
https://msdn.microsoft.com/en-us/library/ms233812.aspx
Thanks
Best Regards
Forum Support
Please remember to mark the replies as answers if they help and unmark them if they provide no help. If you have feedback for TechNet Subscriber Support, contact
[email protected]
Jerry Guo
TechNet Community Support

Help with Library link lists ..

Hi ,
I am working with Scott Mazur on a incorporating 8.1.7 in our code bace for our next product release. I am having problems with defining the library link list needed for builds. In the documentation it makes referance to $ORACLE_HOME/precomp/demo/proc which I cannot find. I have installed the 8.1.7 on 3 platforms (Solaris, AIX and NT ) and none of the system have this information. Can you please point me to where I may find some help in this area. We are in a critical path right now so I would appreciate any help you could give me. The sooner the better.
Thank you for your time and help ,
Cheryl Pollock
Lockheed Martin Global Telecommunications .
Formtek
Pittsburgh office .
(412) 937-4970
null

You actually shouldn't try to get the library link lists directly. Rather, you should use the $ORACLE_HOME/rdbms/demo/demo_rdbms.mk makefile like this:
make -f $ORACLE_HOME/rdbms/demo/demo_rdbms.mk build EXE=yourexecutable OBJS="object list"
where yourexecutable is the name for your executable and the OBJS= includes a quoted list of all your object and library files.
null

Recommendations/help with 'Add Contact List'

hello,
i've run into a bit of a problem, need some expert advice
before i lose my mind :)...
i am trying to allow registered users to have a friend list.
my problems:
1) user is viewing their friend list and only their friends
user_id shows up rather than their friends username...
Here is the SQL i have as of now:
SELECT userTable.user_id, userTable.username,
friendTable.user_id, friendTable.them_user_id
FROM userTable JOIN friendTable ON userTable.user_id =
friendTable.user_id
WHERE userTable.username = var1($_SESSION['MM_Username']
2) when users click 'add friend' button (which is an insert
form with 3 hidden fields, user_id, friend_id, MM_insertform), my
code doesn't check if they are already friends with that person...
not a huge deal, but i'd like to have this feature if i can...
i'd be thankful for any advice, help, etc... thank you!

> 1) user is viewing their friend list and only their
friends user_id =
shows up=20
> rather than their friends username...
> Here is the SQL i have as of now:
> SELECT userTable.user_id, userTable.username,
friendTable.user_id,=20
> friendTable.them_user_id
> FROM userTable JOIN friendTable ON userTable.user_id =3D
=
friendTable.user_id
> WHERE userTable.username =3D
var1($_SESSION['MM_Username']
what happens if you include friendTable.username in the SQL
statement?
>=20
> 2) when users click 'add friend' button (which is an
insert form with =
3 hidden=20
> fields, user_id, friend_id, MM_insertform), my code
doesn't check if =
they are=20
> already friends with that person... not a huge deal, but
i'd like to =
have this=20
> feature if i can...
There is a built in server behavior for Check Username that
will check =
for an existing user name. You might be able to modify that
to meet =
your needs. Keep in mind that modified code will work but
disappear =
from the Bindings/Server Behaviors panel.
--=20
Nancy Gill
Adobe Community Expert
Author: Dreamweaver 8 e-book for the DMX Zone
Co-Author: Dreamweaver MX: Instant Troubleshooter (August,
2003)
Technical Editor: Dreamweaver CS3: The Missing Manual,
DMX 2004: The Complete Reference, DMX 2004: A Beginner's
Guide
Mastering Macromedia Contribute
Technical Reviewer: Dynamic Dreamweaver MX/DMX: Advanced PHP
Web =
Development

Help with an access list please

Hi guys, i have an access list applied inbound to an interface on a router at the edge of our LAN.Our LAN subnet is 10.10.x.x and the incoming subnet is 10.13.x.x both with a 16 bit mask. The ACL is applied inbound to the interface that the the 10.13.x.x subnet come in on. I want to only allow them to go to our internal webserver to run a corporate web app, resolve dns for this web server with our dns servers, and have full access to a server on the other side of our WAN for another 32 bit app they are running. Here is my ACL:(you will notice i have also configured a single ip full access in for us to use when we are on site)
access-list 101 permit ip 10.10.0.0 0.0.255.255 any
access-list 101 permit ip host 10.13.1.254 any
access-list 101 permit udp 10.13.0.0 0.0.255.255 host 10.10.10.1 eq domain
access-list 101 permit udp 10.13.0.0 0.0.255.255 host 10.10.10.2 eq domain
access-list 101 permit tcp 10.13.0.0 0.0.255.255 host 10.10.10.2 eq domain
access-list 101 permit tcp 10.13.0.0 0.0.255.255 host 10.10.10.1 eq domain
access-list 101 permit ip 10.13.0.0 0.0.255.255 host 192.168.9.1
access-list 101 permit tcp 10.13.0.0 0.0.255.255 host 10.10.10.24 eq www
access-list 101 deny ip 10.13.0.0 0.0.255.255 10.0.0.0 0.255.255.255
access-list 101 deny ip 10.13.0.0 0.0.255.255 172.16.100.0 0.0.0.255
access-list 101 deny ip any any
From the 10.13.x.x network this works like a charm but here is the key: i want to be able to remote admin their machines but cant. Even though the ACL is applied inbound only i cant get to their subnet, even with the first permit statement i still cant get to their subnet. I am assuming its allowing me in but the problem is lying with the return traffic. Is their a way for me to deny them access as in the list but for me to remote their subnet?
Any help you could offer would be appreciated.

I agree with you that the first line in the access list is incorrect. Coming in that interface the source address should never be 10.10.0.0. But if he follows your first suggestion then any IP packet from 10.13.anything to anything will be permitted and none of the other statements in the access list will have any effect.
And I have a serious issue with what he appears to suggest which is that he will take his laptop (with a 10.10.x.x address), connect it into a remote subnet, and expect it to work. Unless he has IP mobility configured, he may be able to send packets out, but responses to 10.10.x.x will be sent to the 10.10.0.0 subnet and will not get to his laptop. He needs to rething this logic.
I do agree with your second suggestion that:
access-list 101 permit tcp 10.13.0.0 0.0.255.255 eq 5900 10.10.0.0 0.0.255.255
should allow the remote administration to work (assuming that 5900 is the correct port and assuming that it uses tcp not udp).
HTH
Rick

I need help with drop down lists

I have a form that does not have lots of space and I want to use drop down lists to fill in specific information that describes site conditions. The problem I have is that the drop down list is only set up for a single line and that is not enough space for what I want in the drop down list. In other words, I have items that are several sentences. I have seen some descriptions of creating a drop down list that then fills in a text box that has multiple lines. Unfortunately, that is not an ideal solution for me. I just want the drop down list to select a single phrase. Here is an example of what I want to be able to select in the drop down.
The water heater spilled flue gases in excess of 5 minutes under worst case conditions. The combusiton testing was completed with in 30 days of the invoice submittal.
The form does not allow me to create a field that goes all the way across the page so it needs to look something like this:
The water heater spilled flue gases in excess of 5 minutes
under worst case conditions. The combusiton testing was
completed with in 30 days of the invoice submittal.
Any help is greatly appriciated.

Thanks for responding.
I have three items that are very similar in length and text for each drop down. There are 9 drop downs right now. I am using the drop downs to fill in a form that is used by several people and I want to keep things as simple as possible. Associated with the drop down already is a check box. When the check box is checked, it fills in a text box with a score (1 point, 5 points, etc). That score then tallys for a total with all the other scores in another text box. Using a drop box to fill in a text box is just getting to busy and than I have to distinguish each drop down item so it is clear which text you are selecting.

Help with Dynamic Dropdown List

Hi everyone,
I'm completely new to this, so I hope you will excuse my lack of knowledge.
I need to add a dropdown menu on a page. The dropdown will display a list of all the state names in the U.S. When the person selects a particular state, the access numbers for that state should appear next to it.
I'm using Dreamweaver CS4. I was given a Excel spreadsheet with all of the information on it.
It would be easiest for me if I can use ASP to handle this, since I already have it setup on my machine as a local server to test it.
But, I can't seem to wrap my head around how to go about this.
Any help would be much appreciated.
Thanks!
Meb

Can you tell me if the following statements are correct?
- I need to make 2 xml documents. One for a list of states and one for cities and their phone numbers.
- I need to add a form to a page in DW.
- I need to add 2 Spry Regions to the form, one for the states dropdown list and one for the cities and phone numbers.
- I need to create two Spry Data Sets using the XML data sets I created earlier and insert them in their corresponding regions.
- And I need to analyze the code from iPHP's example and somehow link all the stuff together.
Am I even close to correct?
Thanks again,
Meb
1.) What does the source code from the example look like? Are there 2 xml documents?
2.) Is there a form on the example? Do you want a form on your page?
3.) How many Spry Regions are in the example?
4.) What does the source code from the example suggest?
5.) yes! View source code as previously advised. All of your other questions will be answered once you've done this! See a pattern forming here? You ask a bunch of questions, the answer is to view the source code. You say you've done that and will continue to do so, yet you still ask questions that can be answered by viewing the source code. The result is a lot of redundant discussion.

Need Help with hijacked contact lists

Hello all, I am new here, so please forgive me if I'm posting to the wrong board...didn't really see anything more appropriate. I have a problem with a hijacked contact list:
I have three email accounts being forwarded to my BB Curve 8530. Two from Yahoo and one from AOL. In each of these accounts (when accessed directly from yahoo.com or aol.com) have different contacts. Not all of these contacts are in my BB contact list. The other day, one of my yahoo accounts was somehow hacked, and resulted in one of those spam "drugs for sale" emails being sent to people in my contact list. Well, when I investigated, I discovered that actually, someone who is not even in that particular accounts contact list, but another account. How is this possible?
If that is confusing, here's a better summary (using fake email addresses):
[email protected] sent a bogus email message to [email protected]
but, [email protected] is not in [email protected]'s address book. it is in [email protected] [email protected] is not listed in my BB device's contact list.
The only thing I can think os is somehow the BB was hacked, and someone was able to go through all linked contact lists, and send an email across all connected accounts.
How was this able to happen? what can I do to stop it?
thanks!
Lee

This is the Welcome and Introductions section, so Greetings, and welcome!
The 8500 model section would be perfect for your questions,so we'll get it move there.
Meanwhile,
leevalon wrote:
The only thing I can think os is somehow the BB was hacked, and someone was able to go through all linked contact lists, and send an email across all connected accounts.
Sorry, not possible... UNLESS you gave your BlackBerry to someone to use for a while, during which time they spammed all your contacts. Did you?
Do you have a Security password set on the device? If you are afraid of the above happening, setting the password will just that impossible.
But it wasn't hacked.
1. If any post helps you please click the below the post(s) that helped you.
2. Please resolve your thread by marking the post "Solution?" which solved it for you!
3. Install free BlackBerry Protect today for backups of contacts and data.
4. Guide to Unlocking your BlackBerry & Unlock Codes
Join our BBM Channels (Beta)
BlackBerry Support Forums Channel
PIN: C0001B7B4 Display/Scan Bar Code
Knowledge Base Updates
PIN: C0005A9AA Display/Scan Bar Code

Help with UL navigation list

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