How 2 create a Jtext box and Jcombobox with database connectivity

Question

import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import java.sql.*;
public class StockReport1 extends Frame implements ActionListener
JLabel l1,l2,l3;
JTextField t1,t2,t3;
JPanel p1,p2;
JButton b2,b4,b5;
static Connection cn;
static Statement st;
static ResultSet rs;
public StockReport1()
l1=new JLabel("Name");
l2=new JLabel("Age");
l3=new JLabel("Native");
t1=new JTextField(20);
t2=new JTextField(20);
t3=new JTextField(20);
p1=new JPanel();
p2=new JPanel();
p1.add(l1);
p1.add(t1);
p1.add(l2);
p1.add(t2);
p1.add(l3);
p1.add(t3);
b2=new JButton("Exit");
b4=new JButton("Next");
b5=new JButton("Previous");
b2.addActionListener(this);
b4.addActionListener(this);
b5.addActionListener(this);
p2.add(b2);
p2.add(b4);
p2.add(b5);
p1.setLayout(new GridLayout(3,1));
p2.setLayout(new GridLayout(1,6));
add(p1);
add(p2);
setSize(500,500);
setVisible(true);
setLayout(new FlowLayout(FlowLayout.LEFT,30,40));
addWindowListener(new WindowAdapter() {
               public void windowClosing(WindowEvent e) {
                    System.exit(0);}});
public void actionPerformed(ActionEvent ae)
try
if(ae.getSource()==b2)
System.exit(0);
if(ae.getSource()==b4)
if(rs.isLast()==false)
rs.next();
display();
else
rs.last();
display();
if(ae.getSource()==b5)
if(rs.isFirst()==false)
rs.previous();
display();
else
rs.first();
display();
catch(SQLException se)
se.printStackTrace();
public static void main(String arg[])
new StockReport1();
public void display()
try
String s1=rs.getString(1);
String s2=rs.getString(2);
String s3=rs.getString(3);
t1.setText(s1);
t2.setText(s2);
t3.setText(s3);
catch(SQLException se)
se.printStackTrace();
}

Answer 1

don't mix up with awt and swing, use JFrame instead of Frame.
in display method just set the value of the result set to the textfields.
or put all the data into arraylist after each next button click just read the value and put into textfields