How can I add interactivity to a StringItem with appearance mode HYPERLINK

Question

Hi Everyone,
I have BB 8520 Curve Smartphone. I have installed apps like facebook and gmail on it. I found that it can show the StringItem with appearance mode HYPERLINK and BUTTON. User can directly go to it and press the optical touch button, which directly can open next form of an application without opening the command menu.
In the same way, I want StringItems with appearance mode HYPERLINK in my midlet, should invoke the command directly without opening the menu with various commands, when I press the optical touch button of the device. But actually, it opens the menu when I click on the StringItem.
On my form, I am showing 3 StringItems with appearance mode HYPERLINK, as
1. Quiz 1
2. Quiz 2
3. Quiz 3
User should be able to go to respective forms of an application directly by clicking these links [they are NOT actual web links]. When my cursor is on any of these links, and when I click the optical mouse button of the device, it is opening the menu with command "open selected quiz".
I hope you got my point. Please give me suggestions to achieve interactivity. Best Regards.

Answer 1

I had the same problem to realize a touchscreen button. I also tried to use a StringItem to show a Button or Hyperlink on the display (for my Nokia 5230 touchscreen phone).
So I create a StringItem with type Item.Button or Item.HYPERLINK and a command:
StringItem button = new StringItem(null, "Test", Item.BUTTON);
form.append(button);
Command buttonCommand = new Command("Action", Command.SCREEN, 1); The thing is, when I use button.addCommand(buttonCommand); then the command action is not directly executed when I click on that button. I have to click on the command in the menu to do that.
But when I use button.setDefaultCommand(buttonCommand); then the action is directly executed when I click on the button. That works on my Nokia and you should try that on your BB.
So the code would be like this (or the same for Item.HYPERLINK):
StringItem button = new StringItem(null, "Button", Item.BUTTON);
Command buttonCommand = new Command("Buttonclick", Command.ITEM, 1);
button.setDefaultCommand(buttonCommand);
button.setItemCommandListener(this);
public void commandAction(Command c, Item i){
      if(i == button){
            display.setCurrent(new Alert("Button", "Button clicked!", null, AlertType.INFO));
} Another solution I tried is to create my own button class that extends CustomItem and reacts on touchscreen events in the function pointerPressed(int x, int y). So I have a button class like this:
public class Button extends CustomItem {
    private String text;
    public Button(String text){
        super("");
        this.text = text;
    protected void paint(Graphics g, int w, int h){
        //.... draw button ...
        g.drawString(text, x, y, Graphics.LEFT | Graphics.TOP);
    // ... other functions
    // button click event
    protected void pointerPressed(int x, int y){
        notifyStateChanged();
}And in the calling class I use something like this:
private Button button = new Button("Test");
form.append(button);
form.setItemStateListener(this);
public void itemStateChanged(Item item){
        if (item == button){
              // button was clicked, execute your button action here
}