How do I display the correct value when using SELECT_LIST_FROM_QUERY

I have an updatable report that displays the possible values for a field.
I'm using HTMLDB_ITEM.SELECT_LIST_FROM_QUERY, so obviously I have to process the record manually.
However, I need the trick to display the correct value as selected before processing the records.
I appreciate your help.
Thanks
Juan

Thank you.
So, I just need to put the field name in the second argument.
I have it working now.
Thanks again
Juan

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Since LabVIEW 5.1... 7.1.1... 2009, 2010
依恩与LabVIEW
LVVILIB.blogspot.com
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How do I display the correct value when using SELECT_LIST_FROM_QUERY

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