How do I enable Instead of Trigger feature

Tried compiling Intead of Trigger on my Oracle 8.1.5 server and got a feature not enabled error. is there a way to enable this feature without doing a re-install?
R.

Does your trigger already exist? If so, just reenable it, then recompile.
EX. alter trigger jay_trg enable;
alter trigger jay_trg compile;
If your trigger doesn't already exist, and you're getting an "enable" error, I'm not sure. I just tried creating an instead-of trigger on a view, and it worked fine. The only roles granted to the user was connect and resource. Hope that helps.

Similar Messages

Instead of Trigger Problems

Good morning and thanks in advance for the help. I'm new to oracle and sql in general, so bear with me if my create statements are wrong. I am using Oracle 11g.
I am trying to create a trigger to do an update on a timesheet view in APEX. The view draws from the assignment table and needs to store the data in the timesheet table.
CREATE TABLE assignment (
   assignment_id   number
   employee_id   number
   project_id   number)
CREATE TABLE timesheet (
   timesheet_id number
   assignment_id number
   week_start_date date
   hours   number)
INSERT ALL
INTO assignment (employee_id, project_id) VALUES (1, 1)
INTO assignment (employee_id, project_id) VALUES (1, 2)
INTO assignment (employee_id, project_id) VALUES (2, 1)
INTO assignment (employee_id, project_id) VALUES (3, 2)
CREATE OR REPLACE FOR VIEW timesheet_view AS
SELECT *
FROM (SELECT A.assignment_id, project_id, employee_id, week_start_date, hours
      FROM timesheet T
      RIGHT OUTER JOIN assignment A
        ON T.assignment_id = A.assignment_id)
PIVOT (MAX(hours) FOR week_start_date IN (to_date('06/03/2013', 'MM/DD/YYYY') AS "06/03/2013",
to_date('06/10/2013', 'MM/DD/YYYY') AS "06/10/2013",
to_date('06/17/2013', 'MM/DD/YYYY') AS "06/17/2013",
to_date('06/24/2013', 'MM/DD/YYYY') AS "06/24/2013")
The view has many more columns since this needs to track weeks until they decide to stop using the app.
The view thus looks like this:
assignment_id project_id employee_id 06/03/2013 06/10/2013 06/17/2013 06/24/2013
1                      1                1                 25               15              15              15
2                      2                1                 15               25              25              -
3                      1                2                 40               40              40              40
4                      2                3                 40               -                40              -
So my question is, how do I create a trigger to insert into the timesheet table? I know how to create an instead of trigger, but what I don't know how to do is reference the column names for the date and then take the data that has been updated in each and store that in the timesheet table with the column name going in the week_start_date column and the value from the row at that column going into the hours column. I'd love to be able to do it dynamically since adding a line to the trigger for every single date would be quite unruly.
Any help is greatly appreciated.

Yuck. But you are hardcoding dates as columns into the view, so you'll have to change the view sometime anyway? Could you not generate columns based on the MODEL clause?
Alternatively, have you considered adding a hidden (from the front end) column (weekno) for each date column to your view, but hiding it; in that column you could hardcode the date for the following column?
assignment_id project_id employee_id week1dt         06/03/2013 week2dt          week3dt       06/10/2013 etc.
1                      1                1                06/10/2013    125             06/17/2013      06/10/2013    15
edit: I was just wondering about an alternative: if you could prepend the week date (eg "06/03/2013") to the hours data for the row/column (e.g. "06/03/2013,40") then substring the hours (split on ",") in the APEX view, but you would have the weekdate to be able to use in your table update. Just a thought; I've no experience with APEX.

T440s: How to enable the Windows eDrive feature?

I would like to enable the eDrive feature on my T440s to encrypt my hard drive. How can I do this?
In order to do so,I enabled "OS optimized defaults" in the bios settingsLoaded them and saved themDid a clean install of Windows 8.1 and removed all partitions during this processInstalled all Lenovo driversInstalled all Windows updatesTried to turn on bit lockerAccording to [1] "If everything is eDrive compliant you won’t be asked whether or you want to encrypt all or part of the drive". However, I am asked whether I want to encrypt all or part of the drive!! So my questions is, what is wrong? How can I enable the eDrive feature? [1] http://www.anandtech.com/show/6891/

lax20531
This process below worked for me to enable the eDrive and configure HW-mode BitLocker. Would you please try it and let me know if it works for you? If you have any questions about these steps, let me know.
EDIT 1/9/2014 - these steps still may not work and should be ignored for now.
Backup your personal data, because we are getting ready to wipe the SSD to enable the eDrive function
Create the USB Recovery Drive
Boot the USB Recovery Drive
Select your language and keyboard layout, as prompted
click on "Troubleshoot"
click on "Reset your PC"
click on "Next", and the target operating system, as prompted
At the screen about "Do you want to repartition the drives on your PC?", click on "Yes, repartition the drives" <-- IMPORTANT because eDrive is only enabled when the partitions are recreated.
Click on "Just remove my files"
Click on "Reset"
The PC will be restored with the contents of the USB Recovery Drive. This will take several minutes, and the PC will reboot itself. When the process is complete, you will be at the Win8 setup screen "Region and Language", just like when you unboxed your PC and booted it for the first time.
Go through Win8 setup, connect to network, create your account, etc
Open Device Manager
Expand the category "IDE ATA/ATAPI Controllers"
Double-click on "Intel 8 Series Chipset Family SATA AHCI Controller"
Click on the "Driver" tab
Click on "Update Driver"
Click on "Browse my computer for driver software"
Click on "Let me pick from a list of device drivers on my computer"
Click on "Standard SATA ACHI Controller" and then click on "Next" <-- IMPORTANT since eDrive won't work with the Intel driver. You must use the Microsoft standard driver instead.
Click on "Close", then click on "Close" again. Reboot as prompted.
Open Control Panel -> System and Security -> Windows Update -> Check for Updates
Download and install all available Important and Optional updates <-- IMPORTANT because Win8 itself has some bug about BitLocker. It is fixed in one of the updates, but I'm not sure which one.
Repeat steps 23 and 24 until no more Windows Updates are available
Open Control Panel -> System and Security -> BitLocker Drive Encryption
Click on "Turn on BitLocker"
Save the recovery key as prompted, then click "Next". If you saved the recovery key on a USB drive, be sure to remove the USB drive before continuing.
Click on "Continue" to run the the BitLocker system check
Reboot as prompted
BitLocker should now be running the HW mode
To confirm it: open a command prompt as administrator, then run "manage-bde.exe -status". The Encryption Method should be listed as "Hardware Encryption"

How can I retrieve the condition in an update or delete using instead of trigger

I have 2 tables, on which a view is created. To distinguish the tables within the view trigger, a column "source" had been added in the view creation. I want to be able to delete row(s) in table t1 or table t2 through the view, depending on a condition. The problem is that I don't know how I can get back the delete condition IN the INSTEAD of trigger :
CREATE TABLE t1(m NUMBER, n VARCHAR2(10), o date);
CREATE TABLE t2(a NUMBER, b VARCHAR2(10), c date);
-- The view is created based on the 2 tables.
CREATE OR REPLACE VIEW vt12 AS
SELECT 't1' source, m, n, o
FROM t1
UNION
SELECT 't2' source, a, b, c
FROM t2;
-- The trigger will fire whenever INSERT is performed on the tables through the view
create or replace trigger tvt12 instead of insert or delete on vt12
begin
if inserting then
if :new.source = 't1' then
insert into t1 values (:new.m, :new.n, :new.o);
else
-- will insert a default value of -1 for the fourth column "d"
insert into t2(a,b,c,d) values (:new.m, :new.n, :new.o, -1);
end if;
elsif deleting then
-- We don't know the condition for the deletion, so all rows from the
-- table from which the current row is coming will be deleted
if :old.source = 't1' then
delete t1;
else
delete t2;
end if;
end if;
end;
show error
insert into vt12 values ('t1',1,'1',sysdate);
insert into vt12 values ('t2',2,'2',sysdate+1);
insert into vt12 values ('t1',3,'3',sysdate+2);
insert into vt12 values ('t2',4,'4',sysdate+3);
insert into vt12 values ('t1',5,'5',sysdate+4);
insert into vt12 values ('t2',6,'6',sysdate+5);
commit;
select * from vt12;
select * from t1;
select * from t2;
delete vt12 where m = 1;
commit;
select * from vt12;
select * from t1;
select * from t2;
When I execute this script, the delete statement seems to recognize that the condition is affecting a row in table t1, and therefore deletes all rows from the table, as specified in the delete statement of the trigger... But, what I want to do is ONLY to delete the row affected by the original condition. So my question is to know how I can get back the original condition for the delete, and still use it in the trigger, that will be executed INSTEAD of the delete statement.. I checked in the doc, and everywhere an example of INSTEAD OF trigger can be found, but it's always and only using an INSTEAD OF INSERT trigger, which doesn't need a condition.
Can anyone help ?
null

I've never faced this case myself, but from the documentation it would seem that the INSTEAD OF DELETE is also a FOR EACH ROW trigger. Therefore, you don't really have to worry about the actual "where" clause of the original "delete" operation: Oracle has it all parsed for you, so you just need to redirect, in turn, each view record being deleted to the appropriate table.
In extenso: for your
delete vt12 where m = 1;
=> the INSTEAD OF trigger fires once for all records in vt12 where m=1, and I would guess that you trigger code should look like:
begin
delete from t1 where m = :old.m and n = :old.n and o = :old.o;
delete from t2 where a = :old.m and b = :old.n and c = :old.o;
end;
It's a bit of overkill compared to the "where" clause of the original "delete" statement, but it should do the job...
BTW, if by any luck you do have some primary key on tables t1 and t2 (say: columns o and c respectively), then obviously you can make the thing simpler:
begin
delete from t1 where o = :old.o;
delete from t2 where c = :old.o;
end;
HTH - Didier

How do I enable the feature that allows you to left-click and drag cursor left to be same as back button?

how do I enable the feature that allows you to left-click and drag cursor left to be same as back button?

Do you mean something like clippings?
*Clippings: https://addons.mozilla.org/firefox/addon/clippings/

How to create ADF BC components like EO from "View with INSTEAD OF trigger

I have a "View with INSTEAD OF trigger" on a external schema. is it possible to create ADF EO on top of this view in my local schema?. If possible, then is it possible to insert/update that external table using ADF standard data controls and Application module?. I'm trying to see if it's possible with standard ADF controls without calling pl/sql API to insert/update that external table. any ideas are appreciated.
Regards,
Surya

http://stegemanoracle.wordpress.com/2006/03/15/using-updatable-views-with-adf/

How can I enable blocked flash plugin on firefox?

A couple of days ago, my computer (mac OS X 10.4.11 PPC) suddenly seemed to stop recognizing that I had flash installed and wouldn't play anything requiring flash - instead a message came telling me to install it.
I uninstalled flash and the installed the latest version for my computer from the adobe website (which is 10.1.102.64).
Computer still thinks flash isn't installed and when I checked plugins I discovered firefox has blocked it telling me the version of flash I want to use is too old (even though the version I've downloaded is the latest I can use with my computer).
How can I enable the plugin on firefox so I can use flash? The 'enable' button on the plugin has been greyed out so I can't press it.
Please help - I'm rubbish with computers so please give any advice in very simple language! ( i have firefox 3.0.4)

hello this should not have happened - mozilla recently uses the blocklist feature to notify users about the outdated flash plugin but not block it.
you'd have to trigger a manual update of the blocklist and hope that this time the correct version is retrieved.
go to tools > web-developers > error console & copy the following line into the code field & hit evaluate:
''Components.classes['@mozilla.org/extensions/blocklist;1'].getService(Components.interfaces.nsITimerCallback).notify(null);''
sorry for the computer gibberish. afterwards restart the browser & see if you can enable the plugin in the addons manager again.

Currently, I cannot copy and paste using the icons in the toolbar. How do I enable this?

I am trying to make edits to a website for our company. Currently, I cannot copy and paste using the icons in the toolbar. Instead, I have to use control+c and control+v which doesn't always work. How do I enable the feature to be able to use the icons?

Are those toolbar buttons grayed?
Do the entries in the Edit menu look enabled if there is text selected or text on the clipboard?
Start Firefox in <u>[[Safe Mode]]</u> to check if one of the extensions is causing the problem (switch to the DEFAULT theme: Firefox (Tools) > Add-ons > Appearance/Themes).
* Don't make any changes on the Safe mode start window.
* https://support.mozilla.com/kb/Safe+Mode
* https://support.mozilla.com/kb/Troubleshooting+extensions+and+themes

How do you enable 'Create Content' button on 'Add Content' page?

How do you enable ‘Create Content’ button on ‘Add Content’ page?
There is new functionality to a ‘Layout’ type personalization page like ‘Sales Dashboard’.
Bug 4503123 INCONSISTENT WAY OF ADDING USER-DEFINED REGIONS ON WYSIWYG PAGE:
There’s no way to add custom content to a configurable page.
Add a “Create Content” button and let the user create a piece of content that extends to a region he creates.
It says: Fixed->11.5.10.3CU
In Oracle® Application Framework Personalization Guide Release 11i Part No. B25439-02 it says:
p 4-5
If you personalize a non-configurable page (a page that does not have the necessary metadata to personalize its layout) or when you run your application in Accessibility mode (profile option Self Service Accessibility Features (ICX_ACCESSIBILITY_FEATURES) is set to Standard Accessibility), you will not see the Page Layout Personalization page, as shown below. Instead, you will see the Page Hierarchy Personalization page, page 4-12, where you can perform the same personalization functions, using a descriptive tabular user interface.
It tried this and can’t get it to display.
Has anyone run accross this before?

user587952,
Can you describe your issue in detail forgetting those references for the time being. What exactly are you trying to do?
Check this from the dev guide:
In order to be able to take full advantage of page layout personalization capabilities, it is important when you create your configurable page, to use flexibleLayout and flexibleContent regions at all levels when you create the page hierarchy structure under your page layout region. In Oracle Applications, this is required, as it is the coding standard.
--Shiv

Problem in creating Entity for view which has "INSTEAD OF " trigger

Hi ,
I have an entity based on a Non updatable Database view (DB_VIEW).this database view has an INSTEAD OF trigger which validates
and save data into a table.
And I have a BC4J view based on this entity.
Problem :
When I try to insert a record using bc4j view object,I get following error
ORA-22816: unsupported feature with RETURNING clause
Query sent by view Object is :
BEGIN INSERT INTO DB_VIEW(COLUMN1,COLUMN2,COLUMN3) VALUES (:1,:2,:3) RETURNING ROWID INTO
:4; END;
I am not able to insert any record in that view.
I tried removing rowID from my BC4J entity and View but problem is that in Databae view there is no
column which can be set as a primary key other then ROWID.

I had the same problem.
Oracle 9.2 sadly does not support the RETURNING clause for database views with INSTEAD OF triggers.
Here is Steves Solution:
1. Create a custom entity def impl class for your entity on the Java panel
2. override the isUseReturningClause() and return false
That should work in 9.0.3.4, 9.0.4 build 1419, and 9.0.5.1 production.
from How to disable generation of RETURNING clause?
Hth, Markus

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I have a 2nd gen iPod Touch and synced apps and music with iTunes and everything was mostly great. The only problem was the slowness of iTunes so I started using MediaMonkey instead to transfer music. I also downloaded apps exclusively through wifi, so I never bothered to sync my iPod with iTunes for months. Then I upgraded the harddrive, did a clean install of Windows, and sold my old harddrive. It was not possible to sync my iPod anymore and I didn't care because MediaMonkey/Wifi worked perfectly for my needs ...
Until I installed firmware 3.1! Now MediaMonkey crashes and I can't add/remove songs from my iPod. So I was going to wipe my iPod and give the new version of iTunes another try, but now I am worried about losing all the apps I've downloaded over wifi. I've logged into iTunes and I cannot find a record of apps that I have downloaded/purchased. *Which brings me to my question: How can I enable synch without losing my apps?* I'm particularly worried about the apps that were free when I got them but they now cost money.
Thank you for your time,
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The "File -> Transfer Purchases" option didnt work at first, but then I clicked around and managed to get this new computer image added to the new Home Sharing feature. Now all my iPod apps have been transferred to my local iTunes apps folder, thank you Julian!
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My iPad 2 is disabled. I know the passcode and apple id. How do I enable it?

My iPad 2 16Gb has been disabled because the wrong passcode was entered too many times. Since purchasing the iPad I never purchased anything from the Apple Store and after a couple years my passcode got misplaced.
A friend of mine in the church where I attend tried to help me and went to iTunes, erased the iPad and downloaded the new software. When it was time to activate the iPad, it demanded my apple id and original passcode at the time of purchase.
I searched and found it in my wallet but the last three characters were uncertain. The salesman used an "up-arrow r" for "R" and counted it as two characters; so the passcode only had 7 characters instead of 8. I thought the up-arrow was a "p" and it could have been capital or common. Then the "r" might have been a "k" because the way I wrote it. After many combinations, I ran out of tries and the iPad was disabled. Eventually I realized it was a "R" but too late.
I visited the Apple Support in my country and they were unable to do anything about it even though I had the right apple id and passcode. The security questions were the problem.
The first security question was my birth date and I was getting that wrong. Why, I don't know. How could I get that wrong. Not even my wife's birth date works. I began to question whether the salesman went through any security questions with us at all.
How do I enable the iPad knowing my apple id and passcode at the time of purchase?

You're facing Find My iPhone Activation Lock, and you will not be able to use you're iPad without knowing the Apple ID and Password used to originally activate it. If you don't remember your password, try: https://iforgot.apple.com/password/verify/appleid

Instead of trigger on geometry

Hello
I am trying to setup an environment to access oracle spatial data in AutoDesk Map 3D 2007 using OSE (Oracle Spatial Extension). For this i created a base schema containing a spatial table and I created another schema containing autodesk metadata tables and created a view of the spatial data in the base schema. The view is granted ALL permissions on the spatial table by base schema
The reason for creating view is to accomodate virtual columns like ADMPLAYER, ADMPOBJECTTYPE etc. Now i created an instead of trigger so that when user updates any attribute, creates or deletes any data in the view, it automatically modifies the original tables.
The insert and delete works fine.Even update for attributes works fine, but fails when i update a geometry.
How can i put a condition in the trigger to check if geometry is updated? so i update it accordingly? I tried SDO_EQUAL function by passing old and new geometry values but it fails stating that i can use this operator only if spatial index exist. In my setup the view and original table are in different schemas.
How can i check if geometry is updated in the trigger?
Regards
sam

Hello Luc
Thanks for your suggestion . I checked this for SDO_Geometry and it worked... Please find below the trigger
CREATE OR REPLACE TRIGGER TEMP_BEF_IUD INSTEAD OF INSERT OR UPDATE OR DELETE ON V_TEMP
FOR EACH ROW
BEGIN
--When inserting a new record in the view..this part of the trigger will get fired
IF INSERTING THEN
     INSERT INTO test.TEMP(TEMPID, NAMEID,     UNITSURFACE, ) VALUES (:NEW.TEMPID, :NEW.NAMEID, :NEW.UNITSURFACE);
END IF;
--When deleting an existing record...this part of the trigger will be fired
IF DELETING THEN
DELETE FROM test.TEMP WHERE TEMPID=:OLD.TEMPID;
END IF;
--When updating existing data, this part of the trigger will be fired. When updating it checks for each field to
--determine which field is actually updated and then it fires update statement..accordingly.
IF UPDATING THEN
--Checking each field for update
     IF :OLD.TEMPid <> :NEW.TEMPid THEN
     RAISE_APPLICATION_ERROR(-20005,'TEMPID cannot be updated.This IS SYSTEM generated ID....
     EXCEPTION CODE: '||SQLCODE||' EXCEPTION MSG: '||SQLERRM);
     END IF;
     IF :OLD.NAMEID <> :NEW.NAMEID THEN
     UPDATE test.TEMP SET NAMEID = :NEW.NAMEID WHERE TEMPid=:OLD.TEMPid;
     END IF;
     IF UPDATING('UNITSURFACE') THEN
     UPDATE test.emirate SET UNITSURFACE = :NEW.UNITSURFACE WHERE TEMPid=:OLD.TEMPid;
     END IF;
END IF;
END TEMP_BEF_IUD;
/

INSTEAD OF TRIGGER (UPDATE): new.field null or not set

When using an instead of trigger for an update on a view, you can "relate" the updates to the (another) base table(s).
to perform the update statement you have the use the ":new.field" notation.
Is there a way to determine if the field value is included in the update statement that causes the trigger to be fired?
I know you can check this value and see if it's null but this is not the same as "not used in the set clauses". It can be explicitly set to null : SET field = NULL
which can be used like SET FIELD = :new.field
but what if it is not "used" in the update statement at all.?
Here is a (simplified example)
CREATE OR REPLACE VIEW TATB
As
SELECT TA.FIELD1, TA.FIELD2, TB.FIELD3, TB.FIELD4
FROM TABLEA TA, TABLEB TB
WHERE TA.ID = TB.ID
THIS is an update statement
UPDATE TATB
SET FIELD1='JOS', FIELD2='FONS'
this could be another one
UPDATE TATB
SET FIELD1='JOS', FIELD2='FONS' FIELD3 = NULL
HOW can the distinction be checked (in the body of the instead of trigger) that in update statement 1, the new.field3 is not set at all and in the second one the new.field3 is explicitly set to null
tx
Luc

I found after re-reading the documentation that when using an update it is possible to use the check UPDATING in concordance with the column name:
IF UPDATING('field1') THEN
END IF;
tx
Luc

Instead-of Trigger Complication.

Hi folks,
Please look at the following table to have a clear picture,
I have 2 schemas namely, A and B.
I have 2 objects also X and Y. These are tables in schema A but these same tables (with same structures and data also ) are views in schema B.
In epitome, these X and Y views in schema B refer X and Y objects in schema A.
I have a trigger in schema A wherein before the updation of X, the trigger updates table Y. This is working fine.
Now, I have to write trigger T in schema B wherein before the updation of X, the trigger updates Y. But since both X and Y are views, obviously the trigger should be an INSTEAD-OF trigger and I want ot update the table Y in schema A (because Y in schema B is a view)
In the update statement (in the trigger in schema B), my business logic does not support hardcoding schema names like the following statement is prohibited.
update table A .Y set.....
instead i should write
update table Y set.....
and the above statement should consider the table Y in schema A because in schema B Y is a view that refers table Y in schema A.
How to achieve the desired result?
first of all, is there need to write the instead-of trigger in schema B?
If so how? How to reference the table in other schema without hardcoding its name?
Please do help me.
Your favour will be deeply appreciated.
Cheers, PCZ
schema object trigger
A X,Y (tables) T
B X,Y (Views) T

What is purpose of creating views in schema B?. If it is for security reasons then the better option is to create synonym for tables in schema A. Schema A should grant privileges to schema B. Since both schemas are in the same database materialized views will not be beneficial.

How do I enable Instead of Trigger feature

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