How do I get elevated privileges in terminal

I am trying to use terminal for serial access in trying to run the command /dev/tty I get permission denied
so I then run sudo su and authenticate and still get then same thing. I am not sure what to do.
2.6 GHz Intel Core i7
OSX 10.10.3

You don't need to sudo su, just sudo /dev/tty
According to the man page,
The most common reason for stat(2) to return "permission denied" is if you are running
an automounter and one of the directories in your PATH is on a machine that is currently unreachable.

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Hello Everyone ;
Hello Everyone ;
When installing oracle i did not create oper account.
now i am checking my personal database;
SQL> show user;
USER is "SYS"
SQL> select * from system_privilege_map where name like '%SYS%';
PRIVILEGE NAME      PROPERTY
-3    ALTERSYSTEM    0
-4    AUDIT SYSTEM 0
-83    SYSDBA        0
-84    SYSOPER 0
SQL> select count(*) from session_privs;
COUNT(*)
166
>> Connecting as sysoper
I   can connect SYS /as SYSOPER but this session has only 3 privilegs - why ?
SQL> conn /as sysoper
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COUNT(*)
3
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PRIVILEGE NAME PROPERTY
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-4 AUDIT SYSTEM 0
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PRIVILEGE
CREATE SESSION
RESTRICTED SESSION
SYSOPER
SQL> show user;
USER is "PUBLIC"
SQL> shut immediate;
Database closed.
Database dismounted.
ORACLE instance shut down.
Even i did NOT create oper account for sys user then how can i get all sysoper privilege for public user.

Thanks for quick response;
http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:2659418700346202574
sysoper is another role, if you connect as sysoper, you'll be in a schema "public" a
i am getting confused from given link and your answer.
because system is displaying USER is "PUBLIC" .
when i review (See $ORACLE_HOME/rdbms/lib/config.c in your installation).
/* SS_DBA_GRP defines the UNIX group ID for sqldba adminstrative access. */
/* Refer to the Installation and User's Guide for further information. */
#define SS_DBA_GRP "dba"
#define SS_OPER_GRP "dba"
char *ss_dba_grp[] = {SS_DBA_GRP, SS_OPER_GRP};
~
I am sorry for comparing both replies.
please clarify little more.

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You don't need to sudo su, just sudo /dev/tty
According to the man page,
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Database(s)
8.0.5 on Sun Solaris 5.5
8.1.7.4 on Sun Solaris 5.8
9.0.1.3 on Sun Solaris 5.8 (where my OEM repository resides)
Oracle Enterprise manager
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You do not have enough privileges to perform this
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object privileges to create, edit, or drop database objects
or objects outside of your schema
Although this is probably not an OEM issue, Im hoping you can point me in the right direction. How can I manage when Im logged in as SYS SYSDBA if that does not provide enough privilege?

I misunderstood. You were actually trying to connect as sys as sysdba.
You are quite right as sys there should be nothing stopping you.
Since you were not able to create a user and as sys you should have been able to do it,
this begs the question: how are you connecting?
If you are on the oracle server, try this:
Login as oracle (or su - oracle)
sqlplus /nolog
connect internal as sysdba; (internal is an alias for sys)
create user XXXXXX default tablespace users temporary tablespace temp identified by XXXXXX;
That should work, then you should be also able to connect directly as sys:
connect sys/******[@service] as sysdba;
create user XXXXXX default tablespace users temporary tablespace temp identified by XXXXXX;
Hopefully, that is a bit more helpful.
William
I did not clearly state what I am doing. I am performing (attempting to) all operations in the OEM GUI. I am connected as "SYS as SYSDBA".
The "Create Like" operation is performed by right mouse clicking (Windows OEM) on an existing user that have some grants already applied to them.
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William, thanks for the information that you have provided. It appears that the "as sys there should be nothing stopping you" feature (which is what I want) actually exists in these cases.

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You are coming in using the default shell. I prefer bash and set my passwd file to such.
If you have set your root environment the way you like it you can do a su - root and that will send you in just like you were logging in as root at the terminal.
oh my fingers... so tired after all that typing.
should have just written
"man su".....

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Ok, figured it out. Each of the "[..." actually needs to be prefixed with an (non-printable) ESCAPE character, ASCII code #27.
Since they're non-printable they cannot be displayed in this forum. :-p
I just wrote a little tool that writes a code-27 char in front of every "[" and that works.
//File 'issue-make.c'
//Create a usable 'issue' file (place it at /etc/issue) from various weirdly formatted text files.
//It accepts [... or [[... or ^[... escape sequences.
//By Jindur for bbs.archlinux.org. (Use/modify/hack/distribute/as you wish, just don't sell it.. as if lol).
//Maybe you don't want single [ to be recognized as ESC sequence. Delete the code lines then i guess.
#include <stdio.h>
int main(int argc, char *argv[])
char buf[256], buf2[256];
int n, n2;
FILE *f, *f2;
int just_converted = 0;
if (argc < 2)
printf("This tool converts escape sequences ^[.. [[.. and [.. into real escape sequences.\n");
printf("Enter filename of an ascii art file you wish to convert into a usable 'issue' file.\n");
printf("This will overwrite an existing 'issue' file in the current directory.\n");
printf("Example: issue-make my-cool-art.txt\n");
return 1;
f = fopen(argv[1], "r");
if (!f)
printf("Error: Could not open input file for reading.\n");
return 2;
f2 = fopen("issue", "w");
if (!f2)
printf("Error: Could not open 'issue' file for writing.\n");
return 3;
while (fgets(buf, 256, f))
n = -1;
n2 = -1;
do {
n++;
n2++;
//case 1: sequence ^[...
if (buf[n] == '^' && buf[n + 1] == '[')
n++;
buf2[n2] = 27;
just_converted = -1;
//case 2/3: sequence [ or [[
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just_converted = -1;
else
buf2[n2] = 27;
n2++;
buf2[n2] = '[';
just_converted = -1;
else
buf2[n2] = buf[n];
just_converted = 0;
} while (buf[n]);
fprintf(f2, "%s", buf2);
fclose (f2);
fclose (f);
return 0;
Use 'gcc' to compile.
Last edited by Jindur (2013-06-10 17:01:44)

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How do I get elevated privileges in terminal

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