How do I get the list index for the selected list item

Question

How can I obtain the list index for the currently selected
element in a list item? I'm trying to move the label and value
from on list box to another by using the add_list_element built-
in and it requires the list index.
Thanks for your help...

Answer 1

Hi,
You can`t get the Index for the selected item..
you can get the Value of then Tlist using :Block.ListName .
maybe theis code will help you..
PROCEDURE pr_PasarElementos(ls_Origen           varchar2,                    ls_destino          varchar2,          cValor                    varchar2 default null) IS
     nCont_Orig     number := 0;
     nCont_Dest     number := 0;
begin
nCont_Orig := GET_LIST_ELEMENT_COUNT(ls_Origen);          nCont_Dest := GET_LIST_ELEMENT_COUNT(ls_destino);
     Add_List_Element(ls_destino,nCont_Dest+1,cValor,cValor);
     for rec_Orig in 1..nCont_Orig loop
     if GET_LIST_ELEMENT_VALUE(ls_Origen,rec_Orig) = cValor then
     delete_list_element(ls_Origen,rec_Orig);
     end if;
     end loop;
end;
you can call the procedure with :
pr_pasarElementos('control.ls_activos','control.ls_inactivos',:CONTROL.ls_activos);
here I`m working with the Value equal to the Label... you would need to look for the Label of the origin (ls_Origen) list using the Value (cValor) you already have.
I hope this help you.