How do I pass the exact datetime parameter in a procedure.

Question

How do I pass the exact datetime parameter in a procedure.
Hi All,
I have a datetime problem which is driving me crazy.
I need pass a datetime field as a parameter in an oracle procedure exactly as below with timestamp.
Example: '6/01/2005 5:25:24 AM'
SQL > exec myprod(‘value1’,’value2’,’value3’, to_date('6/01/2005 5:25:24 AM','dd-mm-yyyy hh24:mi:ss'));
I get an error “INVALID MONTH”
Next Changed to_date to to_char
SQL > exec myprod(‘value1’,’value2’,’value3’, to_char('6/01/2005 5:25:24 AM','dd-mm-yyyy hh24:mi:ss'));
I get a different error, “INVALID NUMBER”
Next pass the datetime as it is.
SQL > exec myprod(‘value1’,’value2’,’value3’, '6/01/2005 5:25:24 AM');
I get an error “INVALID MONTH”
Here is the my procedure.
CREATE OR REPLACE PROCEDURE myprod (
p_value1 varchar2,
p_value2 varchar2,
p_value3 varchar2 ,
p_value4 date )
IS
filehandler UTL_FILE.FILE_TYPE;
va_currentdate DATE;
BEGIN
SELECT sysdate
     INTO va_currentdate
FROM dual;
END;
Do you know any solutions for this problem.
Thanks

Answer 1

What is your NLS_DATE_FORMAT value?
There seem to be some implicit data conversions in your arguments.
SQL> select parameter,value from nls_session_parameters where parameter like '%DATE%';
PARAMETER                                                    VALUE
NLS_DATE_FORMAT                                              YYYY-MM-DD HH24:MI:SS
NLS_DATE_LANGUAGE                                            AMERICAN
SQL> select to_date('6/01/2005 5:25:24 AM','dd-mm-yyyy hh24:mi:ss') from dual;
select to_date('6/01/2005 5:25:24 AM','dd-mm-yyyy hh24:mi:ss') from dual
ERROR at line 1:
ORA-01830: date format picture ends before converting entire input string
SQL> select to_date('6/01/2005 5:25:24 AM','dd-mm-yyyy hh:mi:ss am') from dual;
TO_DATE('6/01/20055
2005-01-06 05:25:24