How do you print with StdOut.println once at a time with equal probability!

Question

Hello everyone!
I tried finding this in the FAQ, but nothing really came close to my unique situation. I am trying to write a method before the main method to report to the user that their guess is too high, in a game where the computer picks a number from 0 to 1000.
I have four different statements to let the user know that the guess is too high, here is the code:
public static void reportTooHigh() {
StdOut.println("Wow come on.. too high!");
StdOut.println("Too high buster.");
StdOut.println("Too high, LOL.");
StdOut.println("WOOWWAAAWEEWAAHH.. too high!");     When I use this method in my main method by typing ProgramName.reportTooHigh(), it prints out all of the statements. Any suggestions on how to get them to print out one at a time with equal probability?
Thanks!
Edited by: OvechkinRulez on Apr 27, 2008 4:06 PM
Edited by: OvechkinRulez on Apr 27, 2008 4:06 PM
Edited by: OvechkinRulez on Apr 27, 2008 4:07 PM

Answer 1

OvechkinRulez wrote:
Flounder, I tried using an if statement but for some reason it didn't work for me. It still printed out all of the statements. Can you give me a head start, I am sure I can figure out the rest. Do you pick a value from 0 to 1, and then if its below .25 you print out one thing, below .5 but above .25 you print out the other, etc.?If you use the Random class you can get a number from 0 inclusive to 4 exclusive (ie 0,1,2 or 3). If 0 print the first message, if 1 print the second message, etc. Or as pointed out already use the switch statement.