How Level Cause Works?

I tried to figure out how "connect by level" clause works, but I am not able to come up how it works.
As a try-out, I created a table with 3 column "from_date" date type, "to_date" date type and "user_name" varchar type.
It has 2 rows:
FROM_DATE   TO_DATE     USER_NAME
15-OCT-09   18-OCT-09   thomas
25-OCT-09   30-OCT-09   janeUpon executing the following SQL:
select distinct level - 1 + from_dt "Day", user_name
from my_table
connect by level < (to_date - from_date + 1)
order by user_name;
     LEVEL DAY       USER_NAME
         1 25-OCT-09 jane
         2 26-OCT-09 jane
         3 27-OCT-09 jane
         4 28-OCT-09 jane
         5 29-OCT-09 jane
         1 15-OCT-09 thomas
         2 16-OCT-09 thomas
         3 17-OCT-09 thomas
[This is exact presentation that I am looking for]But, if DISTINCT is ommitted, query returns many rows as follows:
     LEVEL DAY       USER_NAME
         5 29-OCT-09 jane
         4 28-OCT-09 jane
         3 27-OCT-09 jane
         5 29-OCT-09 jane
         4 28-OCT-09 jane
         2 26-OCT-09 jane
         5 29-OCT-09 jane
         4 28-OCT-09 jane
         5 29-OCT-09 jane
         3 27-OCT-09 jane
         4 28-OCT-09 jane
         5 29-OCT-09 jane
         2 26-OCT-09 jane
         4 28-OCT-09 jane
         5 29-OCT-09 jane
         3 27-OCT-09 jane
         4 28-OCT-09 jane
         5 29-OCT-09 jane
         1 25-OCT-09 jane
         4 28-OCT-09 jane
         5 29-OCT-09 jane
         3 27-OCT-09 jane
         4 28-OCT-09 jane
         2 16-OCT-09 thomas
         3 17-OCT-09 thomas
         3 17-OCT-09 thomas
         3 17-OCT-09 thomas
         3 17-OCT-09 thomas
         2 16-OCT-09 thomas
         1 15-OCT-09 thomasSo, how do I eliminate duplicacies in level column within same
user_name without using DISTINCT (as it requiers sorting).
And my production db has many many rows the table that I have to work on and my application invokes
this query many times. So, its unimaginable for me think of resource usage by way of using DISTINCT.
Does any expert have a workaround for this? I'd like to eliminate GROUP BY, DISTINCT clause and use
and alternative light-weight clasue instead.
Regards,
...

Do you know that there's a specific forum for this kind of questions?
PL/SQL
Werner

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