How to avoid priniting xml version... tag in output

Question

hi,
I'm transforming an xml using xsl using output method="text". Not it is giving the something like the following tag in the top of output file.
<?xml version='1' encoding='UTF 8'?>
How can i remove this tag from not being printed.
A solutionasap will help us to proceed without hitches in our project.
thanx
Arun
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Answer 1

Hi !
I've got the same problem, I'm using Jdeveloper build 915. My xml is like this
<?xml version="1.0" encoding="ISO-8859-1"?>
<SERVICE DISPLAYNAME="Aktiekurser" LONG_DESCRIPTION="Aktiekurser med slutkurser">
<PARAMETERS>
<STOCK NAME="STOCKTICKER" DISPLAYNAME="Aktie kod" DISPLAYTYPE="TEXT">
<UPPERLIMIT NAME="MAX" DISPLAYNAME="Max " DISPLAYTYPE="TEXT"/>
<LOWERLIMIT NAME="MIN" DISPLAYNAME="Min" DISPLAYTYPE="TEXT"/>
<CLOSE NAME="CLOSE" DISPLAYNAME="Stangningskurs" DISPLAYTYPE="CHECKBOX"/>
</STOCK>
</PARAMETERS>
</SERVICE>
and my xsl
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" >
<xsl:template match="SERVICE">
<xsl:value-of select="@LONG_DESCRIPTION"/>
<xsl:element name="TABLE">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<xsl:template match="PARAMETERS/*">
<xsl:element name="TR">
<xsl:element name="TD">
<xsl:value-of select="@DISPLAYNAME"/>
<INPUT TYPE="{@DISPLAYTYPE}" NAME="{@NAME}" />
</xsl:element>
</xsl:element>
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="/SERVICE/PARAMETERS/*/*">
<xsl:element name="TD">
<xsl:value-of select="@DISPLAYNAME"/>
<INPUT TYPE="{@DISPLAYTYPE}" NAME="{@NAME}" />
</xsl:element>
</xsl:template>
</xsl:stylesheet>
I get
<?xml version = '1.0' encoding = 'UTF-8'?>
as the first row from the xsl-transform.
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