How to Build a VI that generates a random number between 1 and 80 ....Help!!!!

Build a VI that generates a random number between 1 and 80
Divides the random number by a number specified in the front panel.
If the inputted number is zero, the VI program should turn on a LED in the front-panel to indicate a divide by zero error.
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Go to Solution.

One quick question Edward, was the answer just in time for your monday morning class.
Ton
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Re: Generating a random number between 1-10;

How do I generate a number between 1-20? I saw how to on this forum once, but I can't find it, and I don't have much time to look. Sorry for any inconvinience. What I want to do is assign to the variable x the random number.
Thanks.
Virum

Random rnd = new Random();
int x = rnd.nextInt(20)+1;

How to generate n random dates between 2 time periods

Hi,
I'm trying to write a method that generates n random dates between 2
time periods. For example, lets say I want to generate n random dates
between Jan 1 2003 and Jan 15 2003. I'm not sure how to go about
doing the random date generation. Can someone provide some direction
on how to do this?
The method signature should look like this.
public String[] generateRandomDates(String date1,String date2,int n){
// date1 and date2 come in the format of mmddyyyyhh24miss.
// n is the number of random dates to generate.
return dateArray;
Thanks.
Peter

first take a look at the API concerning a source of randomness (Random might be a good guess), then take a look at stuff concerning dates (Date might be cool, maybe you will find some links from there).
Who wrote this stupid assignment?

How can you generate a random number?

Say I have a timer, and I need it to choose a random number between 100 and 1000. How would I do that?
timer.delay(***RANDOM***);Thanks!

I have this, and it's working for me:
int j = rand.nextInt(500);
But I actually want it to generate a random number between 100 and 500, not 0 and 500. How could I do this?
~Dac

How to build a form that traps all the IP adresses of the systems connected

HELLO EVERYBODY,
This is Paritosh Sharma,Actually I wanna know How to build a form that traps all the IP adresses of the systems connected.It's really Urgent

6i on the web or client server? Webutil is not certified against 6i so if it's web I'm not sure, but I think it's in D2KWUtil for client-server.

How generate a random number that is between 0 and 15! (0-15)

how generate a random number that is between 0 and 15 ??? (0-15)
pls tell me, thx!!!!!!!!!!!!!!!!!

import java.util.Random;
Random r = new Random();
int mynumber = r.nextInt()%16;
For (2^1)-1 number use:
-> int mynumber = r.nextInt()&15; // speedup

Is it possible to use booleans to build a VI that uses buttons to switch between screens (3 only) while the other screens disappear?

As a beginner, I need help figuring out how to build a simply VI that uses boolean logic to switch between three different screens. I need a "Home" screen, the next screen which has a button to go back "Home" and a third screen which has two buttons to go "Home" and "Previous Screen". Can someone help me with a simple block diagram?

Hi,
Or put the data in three tab controls. The tabs itself are hidden. The
program switches between the tab sheet if one of the buttons is pressed.
The buttons are best not copied, e.g. the same buttons are used in every tab
sheet (buttons hover above the tab, a black shadow will apear). If the first
sheet is shown, button 2 and 3 are hidden, sheet two: only button 3 is
hidden, sheet three no button is hidden.
Showing the tabs allows the user to choose the views directlly. The button
logic is not needed anymore. But you'll have to live with a simple tab
sheet, instead of a fancy button system!
Regards,
Wiebe.
"Jason R" wrote in message
news:[email protected]...
> Another solution if you want to avoid property-node hell...
>
> Divide your screen into 1/4ths. That is, make your FP 4x larger than
> your desktop.
>
> Place screen 1 on the upper left quadrant.
> Place screen 2 on the upper right quadrant.
> Place screen 3 on the lower left quadrant.
> Screen 4 (lower right quadrant) is unused.
>
> Disable the ability to scroll at run time.
>
> As the user clicks buttons, use the properties of this vi to move what
> the user can see on the front panel.
>
> Cheating? yep. Easier? yep.
>
> Hope this helps! =)
>
> btw - be sure not to update the FP controls when they are not visible,
> or this will eat processor cycles.
>
> Sincerely,
> Jason G Richmond
> Project Engineer II and LVAAD Instructor
> VI Engineering
> [email protected] (domain should be vieng.com (no A's))
>
>
> missileman wrote:
> > Is it possible to use booleans to build a VI that uses buttons to
> > switch between screens (3 only) while the other screens disappear?
> >
> > As a beginner, I need help figuring out how to build a simply VI that
> > uses boolean logic to switch between three different screens. I need a
> > "Home" screen, the next screen which has a button to go back "Home"
> > and a third screen which has two buttons to go "Home" and "Previous
> > Screen". Can someone help me with a simple block diagram?
>
>

How to generate a random number with at least 6 digits?

Hi all,
All is in the question. :-)
I would like to generate a random number but the function "random
number" in Labview isn't accurate enough.
Do you know an algorithm to generate a random number of 6 or more
digit?
Thanks,
PF

Hi PF,
It's simple. Use 2 random number functions in the same process. Now you
should have 2 distinct random numbers that have the same accuracy. Let's say
LV gives accuracy up to the thousandth (0.XXX), now if you divide one number
by 1000 and then add to the other number you should then have something like
0.XXXXXX. Actually, LV random number function can give up to about 17 digits
(decimal). If you are looking for more digits (>17 digits), the idea above
may not work, then the last thing you may want try is to generate two or
three random numbers then convert all these decimal numbers to fractional
strings chop off the 0 and dot then concatinate them together. After all
it's still a random number. How many digits do you want to get? Make sure
the indicators acce
pt that many digits?
Good luck
Louis.
P-F wrote in message
news:[email protected]..
> Hi all,
>
> All is in the question. :-)
>
> I would like to generate a random number but the function "random
> number" in Labview isn't accurate enough.
>
> Do you know an algorithm to generate a random number of 6 or more
> digit?
>
> Thanks,
>
> PF

Plz help me how i remove previous id that is stuck in activation process and me not know password and id plzzzz help m,

plz help me how i remove previous id that is stuck in activation process and me not know password and id plzzzz help m

Read this: http://support.apple.com/kb/PH13695
If it is locked with your ID, then re-set the password at https://iforgot.apple.com

Generate a random number

How do you generate a random number?

You can also check out Math.random() which returns a
double value between [0..1)You could, depending on your needs, but if you do want ints then you're better off using nextInt from java.util.Random, as outlined by the author here:
http://java.sun.com/docs/books/effective/excursion-random.html
(and what was wrong with 125?! I thought that was a perfectly fine random number...)

Generate a random number and make it STAY after "save"

I searched around this forum and found that I can use this code to generate a random number:
//this.rawValue = Math.round(Math.random() * 1000000);
Works great. only problem is, once I practice on the "real" form and save, close, and reopen - it changes the random number every time. I need to figure out a way to make it save the 1st number it generates when someone opens the form and types info in it....then they save and close, etc.
Can anyone help me? Thanks!!

Example steps:
1. Add a hidden field to the same subform with name 'hiddenField'.
2. First time you open 'hiddenField' rawValue will be null.
3. where ever you run the code to generate random number use scenario like this.
if (hiddenField.isNull) {
this.rawValue = Math.round(Math.random() * 1000000);
}else {
this.rawValue = hiddenField.rawValue;
Hope this thelps.
SekharN

How I get random number between 1 and int number ?

how can I get random number between 1 and int number
like between 1 and 10 etc.
10x

Use the nextFloat() method of the Random class, this returns a random number between 0.0 and 1.0. To get and integer range from that multiply the return value of that method call by the integer range you need (in this case 10), and add the starting number you want returned in the range (1 in this case). The code below works for numbers 1-10.
Random r = new Random();
int x = (int)(r.nextFloat()*10) +1;

How to generate a random number within a specified tolerance and control that tolerance.

I am trying to simulate data without using a DAQ device by using a random number generator and I want to be able to control the "range" of the random number generated though. On the front pannel, the user would be able to input a nominal number, and the random number generator would generate numbers within plus or minus .003 of that nominal number. The data would then be plotted on a graph. Anyone know how to do this? Or if it's even possible?
Just for information sake, the random number is supposed to look like thickness measurements, that's why I want to simulate plus and minus .003 because the data could be thinner or thicker than the nominal.
Thanks in advance!!
Solved!
Go to Solution.

You can create a random number with a gaussian probability profile using two equal distributed (0...1) random numbers and applying the Box Muller transform.
I wrote one many years ago, her it is. (LabVIEW 8.0).
Message Edited by altenbach on 04-12-2010 09:13 PM
LabVIEW Champion . Do more with less code and in less time .
Attachments:
BoxMuller.vi ‏10 KB

How to create a javabean that generate random password?

May i know how to create a javabean that can generate random password?
that include character and string
and length of 10.

i created a class file for my java bean
package autogenerate;
import java.util.*;
public class GeneratePwId
private int MemId;
private String Passwd;
public GeneratePwId(){}
public String getPasswd()
return this.Passwd;
public void setPasswd()
char[] letters = { 'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H',
'J', 'K', 'L', 'M', 'N', 'P', 'R', 'T',
'U', 'V', 'W', 'X', 'Y', 'Z', 'a', 'b', 'c',
'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k',
'm', 'n', 'p', 'q', 'r', 's', 't', 'u',
'v', 'w', 'x', 'y', 'z', '0', '1', '2',
'3', '4', '5', '6', '7', '8', '9' } ;
String pwd = "" ;
while( pwd.length() < 10 )
pwd += letters[ (int)( Math.random() * letters.length ) ] ;
this.Passwd = pwd;
i successfully compile my java file. and try to test it by writing a jsp file.
here is my jsp code
<html>
<head>
<title>
Try retrieving password
</title>
</head>
<body>
<jsp:useBean class"autogenerate.GeneratePwId" id="bean0" scope="page"/>
<%=bean0.getPasswd()%>
</body>
</html>
but i encounter this error
org.apache.jasper.compiler.ParseException: /jsp/GetPasswd.jsp(7,18) Attribute class has no value
anyone can teach me how to solve this problem?
thanks a alot!

How to build an ActionForm that have "dynamic" array as its property?

Hi...
In my current project i need to create an ActionForm that has a property (array, list, or something else) that can take any number of element (dynamically).
The JSP is generated by other pageFlow (contains a dynamic rows of input), so the ActionForm must be able to take any number of input rows.
Any suggestion how to make such ActionForm?
I tried to create an actionform like in Struts (indexed property) but seemed not to work:
public List objectInputs;
public Object getObjectInput(int key)
if (objectInputs== null)
objectInputs= new ArrayList();
return objectInputs.get(key);
public void setObjectInput(int key, Object objectInput)
if (objectInputs== null)
objectInputs= new ArrayList();
this.objectInputs.set(key,objectInput);
Thx in advance :)

Hi
You should check
http://dev2dev.bea.com/blog/rvimala/archive/2006/11/working_with_ar.html
This has a sample on how to use arrays within formbean.
Vimala-

How to Build a VI that generates a random number between 1 and 80 ....Help!!!!

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