How to check the element in xml file by xpath

hi all,
* How to check the element in xml file by xpath
for the following XML file,
* I want to check whether
the element (sage) is present or not in the following xml file XPATH expression...
* I have tried by the following expression ,
NodeList result = (NodeList) xpath.evaluate("//*:student/*:sage/text()",xml_dom,XPathConstants.STRING);
System.out.println(result.item(0).getLocalName()); * I want to get the Element sage as String value....
but i am not able to get the element,why that ??? and How to do that ???
MyXML File :
<x:student>
<x:sname>aaa</x:sname>
<x:sage>26</x:sage>
</x:student>
Thanks,
JavaImran

<code>* Thanks for reply....
* </code><code>In </code>
<code>x:student element x represents the namespace...thats why i put *:student in my expression....
"//*[local-name() = 'student']/*[local-name() = 'sage']/text()"* By the above code , i am not able to get the sage as string from
</code> resul.item(0).getLocalName() method.......?
* How to get that as string format ?

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