How To check validity of XML File

can any one tell me how to find whether an XML file is valid or not before beginning to parse the XML file
Thanks in advance

Xerces will do that for qou, if you activate validation (and, of course, a DTD is specified in the file). Read the documentation of Xerces at xml.apache.org

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Newbie help please: "Validation of XML file failed."

Hopefully my question is short and easy.
I'm a developer and haven't used FrameMaker before. However for unforeseen reasons, I've inherited our technical help documentation constructed in FrameMaker which I've never used. Unfortunately I'm under a very tight deadline and I'm attempting to update our already existing and fairly extensive application help files.
However, I'm getting a "Validation of XML file failed" error for 90% of our .xml help docs. I opened our .book file in FrameMaker fairly easily, and can see all of our .xml files. However the variables already embedded in the documents aren't being recognized and seem to be causing the above error. I've located our variable definition files (xml) in the concepts folder, but FrameMaker doesn't seem to recognize them. Any suggestions on what I can check or how I can get FM to refer to the variable definitions? I'm working with a new installation of FM, is there some setup I overlooked?
Many thanks,
dana.

Sheila and Rick,
Thank you both so much for your offer of help. My apologies for not replying earlier. Other 'emergencies' and priorities at work took me in other directions. It turns out another solution has been found for the time being. But thank you again for your replies. They say a lot about this community and its support. :)
Thanks again,
dana.

How to retrieve value from xml file

hi all,
can somebody pls tell me how to retrieve value from xml file using SAXParser.
I want to retrieve value of only one tag and have to perform some validation with that value.
it's urgent .
pls help me out
thnx in adv.
ritu

hi shanu,
the pbm is solved, now i m able to access XXX no. in action class & i m able to validate it. The only thing which i want to know is it ok to declare static ArrayList as i have done in this code. i mean will it affect the performance or functionality of the system.
pls have a look at the following code snippet.
public class XMLValidator {
static ArrayList strXXX = new ArrayList();
public void validate(){
factory.setValidating(true);
parser = factory.newSAXParser();
//all factory code is here only
parser.parse(xmlURI, new XMLErrorHandler());
public void setXXX(String pstrXXX){
strUpn.add(pstrXXX);
public ArrayList getXXX(){
return strXXX;
class XMLErrorHandler extends DefaultHandler {
String tagName = "";
String tagValue = "";
String applicationRefNo = "";
String XXXValue ="";
String XXXNo = "";
XMLValidator objXmlValidator = new XMLValidator();
public void startElement(String uri, String name, String qName, Attributes atts) {
tagName = qName;
public void characters(char ch[], int start, int length) {
if ("Reference".equals(tagName)) {
tagValue = new String(ch, start, length).trim();
if (tagValue.length() > 0) {
RefNo = new String(ch, start, length);
if ("XXX".equals(tagName)) {
XXXValue = new String(ch, start, length).trim();
if (XXXValue.length() > 0) {
XXXNo = new String(ch, start, length);
public void endElement(String uri, String localName, String qName) throws SAXException {
if(qName.equalsIgnoreCase("XXX")) {
objXmlValidator.setXXX(XXXNo);
thnx & Regards,
ritu

How can (parse) i use XML file with missing EndTag

hi,
i have an application which writes an "XML file".
another application should read that XML file, build an DOM and
access the nodes with xpath.
my problem. if the first application is not finished there are tags
missing. e.g. </xml>. but the seconds application cannot wait until the first application finishes it task.
if i now read the XML file the parser cannot load it because the end tags are missing.
my question:
how can i deactivate the check or how can i read the XML file and access it via XPath (my application is using at the moment XPath to access the nodes and i dont want to change that)
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alex

As far as I know, you can't do this - xml must be well formed (this is sort of a bedrock of xml). There may be some work around's, but I'm not aware of any - and they would most likely be hacks.

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Hi All,
How do I FTP an xml file that is validated against a schema on the ftp adapter with out the namespace attribute being added to the first and second element of the XML file.
For example the xml looks like this when I transfer the file.
<XML_Event xmlns="http://xmlns.oracle.com/PlannedEventSTORMRequestProcess/STORM">
<Event_Begin xmlns="">
<XML_File_Header>
<Originating_System>xxx</Originating_System>
<ID>387</ID>
</XML_File_Header>
</Event_Begin>
</XML_Event>
However I want it to be….
<XML_Event>
<Event_Begin>
<XML_File_Header>
<Originating_System>xxx</Originating_System>
<ID>387</ID>
</XML_File_Header>
</Event_Begin>
</XML_Event>
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Cheers

Here is an example that will try to reach the given size in steps of 4 in quality.
var saveFile = File(Folder.desktop + "/test");
var fileSize = 70;
try{
tmpFile = File(saveFile+".jpg");
for(var z =100;z>5;z -=4){
SaveForWeb(tmpFile,z);
var chkFile = File(saveFile+".jpg");
//$.writeln(tmpFile + " qual = " + z + " Size = " +(chkFile.length/1024).toFixed(2) + "k" );
if((chkFile.length/1024).toFixed(2) < (fileSize +1)) break;
tmpFile.remove();
if(!tmpFile.exists) SaveForWeb(tmpFile,5);
}catch(e){$.writeln(e + " - " + e.line);}
function SaveForWeb(saveFile,jpegQuality) {
var sfwOptions = new ExportOptionsSaveForWeb();
   sfwOptions.format = SaveDocumentType.JPEG;
   sfwOptions.includeProfile = false;
   sfwOptions.interlaced = 0;
   sfwOptions.optimized = true;
   sfwOptions.quality = Number(jpegQuality);
activeDocument.exportDocument(saveFile, ExportType.SAVEFORWEB, sfwOptions);

How I can create a XML file from java Aplication

How I can create a XML file from java Aplication
whith have a the following structure
<users>
<user>
<login>anyName</login>
<password>xxxx</password>
</user>
</users>
the password label must be encripted
accept any suggestion

Let us assume you have all the data from the jsp form in an java bean object..
Now you want a xml file. This can be acheived in 2 ways
1. Write it into a file using java.io classes. Say you have a class with name
write("<name>"+obj.getName+</name>);
bingo you have a flat file with the xml
2. Use data binding to do the trick
will recommend JiBx and Castor for the 2nd option
Regards,
Rajagopal

How to Read and Generate XML file from java code.

hi guys,
how to read the xml file (Condition :we know only DTD or Shema only).
How to Generate the new xml file ?(using Shema )
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Pleas with code or any URL

Using XMLbeans you can generate Java objects from an XSD schema (perhaps DTDs aswell)
Then you can create an instance of the Document object and ask it to write itself.
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matfud

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Good morning,
How could I generate an XML file from a report? Please note that I am using version 4.0B
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Billy Vital

Hi,
In the Class CL_XML_DOCUMENT,
we have a method EXPORT_TO_FILE to download an XML file.

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I get following error when unmarshal xml:
[java] org.xml.sax.SAXParseException: An invalid XML character (Unicode: 0x15) was found in the element content of the document.
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Thanks

These sort of error usually occur when you're using a different character encoding to read the file than the one you wrote it with. Perhaps if you were to post the problem section of the file and/or the code that created it in the first place.

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Hi All,
I have a scenario like this . I have one xml file with key value pairs of ( name , URL ) . I have retrieved contents from XML file , now I want to parse these contents and store in a bean object.
How to parse Contents of XML file??
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Rajendra.

Hi All,
I have a scenario like this . I have one xml file with key value pairs of ( name , URL ) . I have retrieved contents from XML file , now I want to parse these contents and store in a bean object.
How to parse Contents of XML file??
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I have written a program (DOM Parser) that parses data from a XMl File. I would like to create an individual file with the corresponding name for each set of data parsed from the xml document. If the parsed output is Single, Double, Triple, I would like to create an individual xml file (Single.xml, Double.xml, Triple.xml)with those corresponding names. How do I create the xml files and give each file the name of my parsed data output? Thanks in advance for your help.
import java.io.IOException;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;
public class MyDomParser {
public static void main(String[] args) {
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
try {
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse("ENtemplate.xml");
doc.normalize();
NodeList rootNodes = doc.getElementsByTagName("templates");
Node rootNode = rootNodes.item(0);
Element rootElement = (Element) rootNode;
NodeList templateList = rootElement.getElementsByTagName("template");
for(int i=0; i < templateList.getLength(); i++) {
Node theTemplate = templateList.item(i);
Element templateElement = (Element) theTemplate;
System.out.println("Template" + ": " +templateElement.getAttribute("name")+ ".xml");
} catch (ParserConfigurationException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (SAXException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
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Ive posted the new code but now I'm getting a FileAlreadyExistException error. How do I handle this exception error correctly in my code?
import java.io.IOException;
import java.nio.file.FileAlreadyExistsException;
import java.nio.file.Files;
import java.nio.file.Paths;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;
public class MyDomParser {
public static void main(String[] args) {
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
try {
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse("ENtemplate.xml");
doc.normalize();
NodeList rootNodes = doc.getElementsByTagName("templates");
Node rootNode = rootNodes.item(0);
Element rootElement = (Element) rootNode;
NodeList templateList = rootElement.getElementsByTagName("template");
for(int i=0; i < templateList.getLength(); i++) {
Node theTemplate = templateList.item(i);
Element templateElement = (Element) theTemplate;
System.out.println(templateElement.getAttribute("name")+ ".xml");
for(int i=0; i < templateList.getLength(); i++) {
Node theTemplate = templateList.item(i);
Element templateElement = (Element) theTemplate;
String fileName = templateElement.getAttribute("name") + ".xml";
Files.createFile(Paths.get(fileName));
System.out.println("File" + ":" + fileName + ".xml created");
} catch (ParserConfigurationException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (SAXException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();

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regards
Nagaraju

This is a Java forum.
JavaScript is something entirely different than Java, even though the names are similar.
Try another website with forums about JavaScript.
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ET

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I have all the inputs of API in to the XML file.
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Thanks and regards
Ram Krishna Tripathi
[email protected]

Well, I've used it (or rather: tried it); did not/could not find the many options to export at a nearly lossless conversion for HD footage (hence my disclaimer "don't know"). Here is a screenshot of the Handbrake options:
And here are the choices and settings from MPEG Streamclip:
Maybe not empirical, but enough for me to have an opinion.

How To check validity of XML File

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