How to compare all columns in a SELECT with all columns in a Cursor ?

Question

Hi All,
I would like to know if something like this is possible in PL/SQL
I have a cursor CUR1 which is a SELECT * FROM T1.
And in my loop for every record found in CUR1 I am trying to retrieve its consecutive record in the table T2. Unfortunately T1 and T2 do not have a primary key so there are duplicates. But if I can compare each column of CUR1 with its respective column in T2, I can find the record. But the question is how ?
So I tried something like this, but of course this is wrong, but hope this would give you an idea of what I trying
VAR_T2 T2%ROWTYPE;
CUR_T1 IS SELECT * FROM T1
LOOP CUR_TI
SELECT * INTO VAR_T2
FROM T2 WHERE
‘ALL COLUMNS OF T2’ = ALL COLUMNS OF CUR1;
So is there a easy way to accomplish this. Thank you, AJ

Answer 1

As Walter says, this is simply an intersect if you are comparing all the columns.
However, if you really must do it in a slow by slow, PL/SQL loop (no real valid reason why you would though)...
DECLARE
  VAR_T2 T2%ROWTYPE;
  CUR_T1 IS
    SELECT * FROM T1;
BEGIN
  FOR i IN CUR_TI
  LOOP
    SELECT * INTO VAR_T2
    FROM T2
    WHERE T2.col1 = i.col1
      AND T2.col2 = i.col2
      AND T2.col3 = i.col3
      AND T2.colN = i.colN;
  END LOOP;
END;There is no simple mechanism for just saying "compare all the columns", you will have to specify each one individually in the WHERE clause.