How to create a Separate Servlet application?

Question

Hi,
Till now i have been servlet programs by placing the class files in the following directory path... ie ROOT/WEB-INF/CLASSES... and i access it like this
http://localhost:8080/servlet/hello..
My friend also works in my system... so i get confused which is hers n which is mine.
I know we can create a separate folder inside webapps directory and access... so i cretaed a folder called servpgms in webapps directory.. under serpgms i created web-inf and lib folders.... then inside web-inf i created classes folder n i placed class file there.... but i have not written any web.xml file... so when i access my program like this ie..
http://localhost:8080/servpgms/hello...
i get HTTP 404 servlet not found..
Can any one elaborate on writing the web.xml file and help me in creating a separate app?
Thanks,
Akshatha

Answer 1

Hi
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.2//EN"
"http://java.sun.com/j2ee/dtds/web-app_2_2.dtd">
<web-app>
<servlet>
<servlet-name>dbServlet</servlet-name>
<servlet-class>com.mycompany.dbServlet</servlet-class>
<load-on-startup>1</load-on-startup>
<init-param>
<param-name>dbdrivername</param-name>
<param-value>qualified driverclass</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name> dbServlet </servlet-name>
<url-pattern> /com/* </url-pattern>
</servlet-mapping>
</web-app>This is enough for testing a servlet. If you want to add more, read deployment descriptor file structure document and add elements that satisfy your needs.
bye for now
sat